The diagram represents the circular cross-section of an artery with external diameter d of 1.6 cm. The thickness t of the artery wall is 1 mm. What is the internal cross-sectional area of the artery (shaded in the diagram)?

Answer:

12) D

There are two circles in this diagram. The grey circle and the outer circle.

In order to get the diameter of the grey circle, we need to subtract 2mm (2 x 1mm) from 1.6 cm.

Diameter of grey circle = 1.6 – 0.2mm = 1.4cm

Radius = 0.7cm = 7mm

Area of a circle = πr²

Area of internal cross sectional area (grey circle) = π(7)² = 49π mm²