Given thatܽ a=3/5+X, b= 3+X/5 and c=3+X/5+Xwhereܺ is a whole number greater than zero, which
one of the following is true?

Answer:

12) B

Since 6 out of the 7 options mention ‘all values of X’ we can use X = 1 to make everything simpler.

a = 3
5 + X

b = 3 + X
5

c = 3 + X
5 + X

Substituting X = 1,

a = 3 = 3/6 = 1/2
5 + 1

b = 3 + 1 = 4/5
5

c = 3 + 1 = 4/6 = 2/3
5 + 1

The order of inequalities: a < c < b

However, option G states that the order of fractions depend on the value of X. In order to proves this wrong, we need to use a different value for X. Let us say X = 2.

a = 3 = 3/7
5 + 2

b = 3 + 2 = 5/5 = 1
5

c = 3 + 2 = 5/7
5 + 2

The order still remains the same: a < c < b