BMAT 2008 Section 2 Question 4Post author:Sami QamarPost published:11 January 2024Post category:BMAT Solved Papers / BMAT 2008Post comments:0 CommentsIn the formula P=2r2tr = 3 x 10-3 t = 2.5 x 10 4Calculate the value of P. Leave your answer in standard form.Answer:4) DP = 2r²tP = 2 (3 x 10⁻³)² (2.5 x 10⁴)P = 2 (9 x 10⁻⁶) (2.5 x 10⁴)P = 5 x 10⁴ x 9 x 10⁻⁶P = 45 x 10⁻²P = 4.5 x 10⁻¹ Tags: bmat 2008, bmat 2008 past paper, bmat 2008 section 2 answers, bmat 2008 worked solution, bmat section 2 question 4 answer, bmat testRead more articles Previous PostBMAT 2008 Section 2 Question 3 Next PostBMAT 2008 Section 2 Question 5 Sami Qamar I’m Sami Qamar. I’m a YouTuber, Blogger, and first year med student. You Might Also Like BMAT 2003 Section 2 Question 245 January 2024 BMAT 2007 Section 2 Question 29 January 2024 BMAT 2005 Section 2 Question 65 January 2024Leave a Reply Cancel replyCommentEnter your name or username to commentEnter your email address to commentEnter your website URL (optional) Save my name, email, and website in this browser for the next time I comment.