BMAT 2006 Section 2 Question 21

Evaluate?

Answer:

If you are not sure about solving powers, click here.

Let us solve the values given in the problem individually.

32^¹⁄₅ = ⁵√32 = 2

9⁰ = 1

81^¾ = (⁴√81)³
⁴√81 = 3
(⁴√81)³ = (3)³ = 27

So we have:
²⁺¹⁄₂₇ = ³⁄₂₇ = ¹⁄₉

We also have a (⁻¹) power too.
So (¹⁄₉)⁻¹ = 9

Sami Qamar

I’m Sami Qamar. I’m a YouTuber, Blogger, and first year med student.

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