BMAT 2013 Section 2 Question 4

Answer:

Substitute the values given in the problem

4.6 x 10⁷ + 7 (2 x 10⁶)
4.6 x 10⁷ – 2 (2 x 10⁶)

(4.6 x 10⁷) + (14 x 10⁶)
(4.6 x 10⁷) – (4 x 10⁶)

(4.6 x 10⁷) + (1.4 x 10⁷)
(4.6 x 10⁷) – (0.4 x 10⁷)

6 x 10⁷
4.2 x 10⁷

The two (10⁷) will cancel out

6 = 1 = 10
4.2 0.7 7

Sami Qamar

I’m Sami Qamar. I’m a YouTuber, Blogger, and first year med student.

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