# Sami Qamar

> Medstudent & a YouTuber given IMAT


## Posts

- [BMAT 2003 Section 2 Question 21](https://samiqamar.com/bmat-2003-section-2-question-21/): Diagrams 1 to 5 show five types of levers. Diagram 6 shows the bones of the arm with arrows showing its movement up and down. Which two levers would be involved in the forcible up and down movement? Answer: 21) E The question gives you the types of levers. You just need to understand which one applies to the action of moving load up and which lever is used to move the load down. Imagine yourself doing a bicep curl in the gym! You have the weight (load) in your hand which acts downwards due to gravity. Using your elbow (fulcrum) […]
- [BMAT 2003 Section 2 Question 20](https://samiqamar.com/bmat-2003-section-2-question-20/): The electronic configuration of an isolated, non-ionised, atom is shown below. In which group and in which period of the periodic table is this atom situated? Answer: 20) C The number electrons in the valence shell determines which group the atom belongs to. The number of shells determines which period the atom belongs to. 4 outer electrons so the atom is in group 4 2 shells in total means that the atom is in period 2
- [BMAT 2003 Section 2 Question 19](https://samiqamar.com/bmat-2003-section-2-question-19/): The energy in joules (E) associated with a photon of radiation is related to its frequency inhertz (f) by the equation: f =E/h where h is a constant (6.63 
 10-34). What is the energy of aphoton of radiation if 5 waves of this radiation are produced in 1 
 10-13 sec? Answer: 19) C Frequency = (5 ÷ 10⁻¹³) = 5 x 10¹³ (PLEASE LEARN THE POWERS RULES) Energy = f x h = 5 x 10¹³ x 6.63 x 10⁻³⁴ = 33.15 x 10⁻²¹ = 3.32 x 10⁻²⁰ J
- [BMAT 2003 Section 2 Question 18](https://samiqamar.com/bmat-2003-section-2-question-18/): The antidiuretic hormone (ADH) is produced by the pituitary gland and its target organ isthe kidney. ADH leaves the head in the jugular vein. In what order will the hormone pass through the following blood vessels to reach its target? Answer: 18) E, B, C, A, D It is essential that you know the direction of blood flow and the order of blood vessels that it flows in. Of course, ADH travels in blood. I will use a flow chart to show exactly how the ADH will reach the kidney. Pituitary Gland → Jugular Vein → Vena Cava → Right Atrium […]
- [BMAT 2003 Section 2 Question 17](https://samiqamar.com/bmat-2003-section-2-question-17/): Which one of the following is not equal to volts? Answer: 17) E You need to learn electricity equations which link power, current, voltage, energy and charge. Also, you need to learn the units of each measurement. Let us look at the options: Ajoules/coulombs = Energy/ChargeWe know the formula, Energy=Charge x VoltageHence, Voltage = Energy/Charge Bamperes x ohms = Current x ResistanceWe know V=IR which is Voltage = Current x Resistance Cwatts/amperes = Power/CurrentWe know P=VI which Power = Voltage x CurrentRearranging, we get Voltage = Power/Current D√watts x ohms = √Power x ResistanceWe know:P = VI and I = V/RIf we substitute I = V/R in P=VI, […]
- [BMAT 2003 Section 2 Question 16](https://samiqamar.com/bmat-2003-section-2-question-16/): The graph shows the solubility of potassium chlorate(V). A sample of potassium chlorate(V) weighing 80 g was added to 200 g of water at 70 C.The solution was allowed to cool to 20 C.What mass of crystals was formed? Answer: 16) C Solubility of potassium chlorate(V) in 100g of water at 70ºC is 78g.Our sample was dissolved in 200g of water. Therefore, 136g of potassium chlorate(V) should have been dissolved. However, we only added 80g. So, the full sample would have been dissolved.So far: 80g of potassium chlorate(V) has fully dissolved in 200g of water. Now, the solution becomes saturated when […]
- [BMAT 2003 Section 2 Question 15](https://samiqamar.com/bmat-2003-section-2-question-15/): In an experiment concerning radioactive decay, the count rate of radiation 5 cm from asource X was measured as 140 counts per minute. 12 minutes later, with the detector in thesame position, the count rate was measured as 35 counts per minute.Background radiation was recorded as 20 counts per minute.Calculate the half-life of source X. (Give your answer in minutes.) Answer: 15) 4 minutes Initial count rate = 140 – 20 (background radiation) = 120Final count rate = 35 – 20 = 15We need to figure out the number of half lives. 120 → 60 = 1 half life 60 → […]
- [BMAT 2003 Section 2 Question 14](https://samiqamar.com/bmat-2003-section-2-question-14/): The diagram shows the inheritance of a condition in a family. (i) Identify the three individuals who must be heterozygous for this condition.(ii) What are the chances that a second child of individuals 3 and 4 will be a female whohas this condition? Answer: 14) i) 3, 4, 5    ii) E i) 7 has inherited the disease in an autosomal recessive fashion since 4 and 5 do not have the disease. Therefore, 4 and 5 must be heterozygous.Since 7 is affected, 3 must also be heterozygous. ii) We now know that 3 and 4 are heterozygous.           […]
- [BMAT 2003 Section 2 Question 13](https://samiqamar.com/bmat-2003-section-2-question-13/): Solve the inequalityx^2 >8 – 2x Answer: 13) D We need to rearrange this inequality so that we have 0 on one side and the other figures on the other side. x² is equal to or more than 8 – 2x  Shifting ‘8 – 2x’ to the other side, we have:x² + 2x – 8 is equal to or more than 0Now we factorise the expression ‘x² + 2x – 8′ It is essential that you understand how to ‘Factorise the middle term’ We get (x+4) (x-2) is greater than or equal to 0Solutions: x is less than or equal to -4 and […]
- [BMAT 2003 Section 2 Question 11](https://samiqamar.com/bmat-2003-section-2-question-11/): Three of the characteristic phenomena demonstrated by waves are reflection, refraction anddiffraction. How many of these phenomena cause the frequency of the wave to change? Answer: 11) A Frequency remains the same in all of these phenomena. So A (0) is the answer. You cannot work this out. This requires pre-requisite knowledge.
- [BMAT 2003 Section 2 Question 12](https://samiqamar.com/bmat-2003-section-2-question-12/): In the citric acid cycle, succinic acid, C4H6O4, is converted into fumaric acid, C4H4O4. This is an example of which one of the following chemical changes? Answer: 12) A Fumaric acid is formed when succinic acid loses 2 hydrogen atoms. This is an oxidation reaction. 
- [BMAT 2003 Section 2 Question 10](https://samiqamar.com/bmat-2003-section-2-question-1-2/): Which one of these graphs could be a sketch of the graph of the function y = 2x? Answer: 10) B For this question, you can substitute values into the the variables ‘y’ and ‘x’ So, whenx = 1, y = 2 (This eliminates D)x = 0, y = 1 (This immediately rules out A & C) (IT IS IMPORTANT TO UNDERSTAND THE POWER RULES)
- [BMAT 2003 Section 2 Question 9](https://samiqamar.com/bmat-2003-section-2-question-9/): Ammonia is manufactured from the reaction between nitrogen and hydrogen.N2 + 3H2 ⇌ 2NH3What is the maximum mass of ammonia that can be obtained from a mixture of 56g ofnitrogen with 9 g of hydrogen? (Relative atomic masses: H = 1; N = 14.) Answer: 9) B n(H₂) = 9/2 = 4.5 molesn(N₂) = 56/28 = 2 moles Ratio of H₂:NH₃ = 3:24.5 moles of Hydrogen reacts with 3 moles of Ammonia We then use the formula:moles = mass/Mrmoles = 3mass = unknownMr = 14 + 3 = 17 moles = m/Mrm = moles x Mr = 3 x 17 = […]
- [BMAT 2003 Section 2 Question 8](https://samiqamar.com/bmat-2003-section-2-question-8/): Three resistors of equal value are connected up as shown. Arrange the letters corresponding to the four combinations in increasing order of resistance (least resistance first). Answer: 8) A, B, C, D Resistors in parallel have a lower overall resistance than same resistors in series. A has lowest resistance. Now, B only has one resistor in each branch but C has two in the top branch. Hence, C has a lower resistance than B. All resistors in D are in series hence D will have the greatest resistance. If you are still confused, let us assume that each resistor has a […]
- [BMAT 2003 Section 2 Question 7](https://samiqamar.com/bmat-2003-section-2-question-7/): The diagram shows the menstrual (oestrus) cycle for a human female who is not pregnant. During which period, A, B, C or D, will the concentration of oestrogen reach its highest level? Answer: 7) B Oestrogen reaches its highest level in the days prior to ovulation. So B is the answer (before ovulation).
- [BMAT 2003 Section 2 Question 6](https://samiqamar.com/bmat-2003-section-2-question-6/): A horse of weight 6000N gallops at a speed of 16 m/s. Taking the acceleration of free fallas 10m/s2, calculate the kinetic energy of the horse. (Give your answer in kJ.) Answer: 6) 76.8 kJ Weight = mass x gHorse’s mass = 6000/10 = 600 kgKinetic energy = ½mv² = (0.5 x 600 x 16²) = 300 x 256 = 76800 J = 76.8 kJ
- [BMAT 2003 Section 2 Question 5](https://samiqamar.com/bmat-2003-section-2-question-5/): The colors of three indicators are shown. Equal volumes of these three indicators were mixed and the mixture was added to a solution of pH 5.0. What color would be seen? Answer: 5) D At pH 5: Methyl orange would be yellowBromothymol blue would be yellowPhenolphthalein would be colorless So, yellow + yellow + colorless = yellow.
- [BMAT 2003 Section 2 Question 4](https://samiqamar.com/bmat-2003-section-2-question-4/): The diagram shows a uniform beam pivoted at its centre. The bar weighs 800N, and threeother forces act on it as shown. Distance x can be varied. What value of distance x would cause the beam to be balanced? Answer: 4) B Pivot is located in the middle. So ignore the weight of the bar. Moments clockwise = Moments anticlockwise: (500 x 0.2) = (0.4 x 200) + 200x 100 = 80 + 200x x = 20 ÷ 200 = 0.1m = 10 cm
- [BMAT 2003 Section 2 Question 3](https://samiqamar.com/bmat-2003-section-2-question-3/): What values of a, b and c are needed to balance the equation?aC3H6 + bO2 6CO2 + cH2O Answer: 3) 2, 6, 9 Carbon3a = 6Hence, a = 2 Hydrogen6a = 2c6 (2) = 2c12 = 2cc = 6 Oxygen2b = 12 + c2b = 12 + 62b = 18b = 9
- [BMAT 2003 Section 2 Question 2](https://samiqamar.com/bmat-2003-section-2-question-2/): The mass of an atom of uranium is 4 
 10-25 kg.What is the mass, in milligrams, of 8 million atoms of uranium? Answer: 2) E Mass of 8×10⁶ uranium atoms = 4 x 10⁻²⁵ x 8 x 10⁶(32 x 10⁻¹⁹) kg = (32 x 10⁻¹³) mg Answer: 3.2 x 10⁻¹² mg
- [BMAT 2003 Section 2 Question 1](https://samiqamar.com/bmat-2003-section-2-question-1/): The table below shows the proportions of undigested and digested carbohydrates, fats andproteins in three regions of the digestive system. Which row of the table below correctly identifies the types of nutrient 1, 2 and 3? Answer: 1) B Amylase in mouth partially digests starchPepsin secreted in the stomach digests proteinSmall intestine is the location for the digestion of fats1 represents starch 2 represents protein 3 represents fats
- [IMAT 2023 Rankings and Cutoffs](https://samiqamar.com/imat-2023-rankings-and-cutoffs/): Pursuing the world of medical admissions can be stressful, especially when aiming for a prominent university in Italy. The IMAT (International Medical Admissions Test) is a critical stage in this process, and understanding the IMAT 2023 ranking is crucial for upcoming aspirants. As we delve into this issue, let’s simplify the specifics of IMAT rankings and give you with up-to-date information on cutoff scores across Italian universities. IMAT 2023 Rankings The 2023 IMAT rankings were released on the 7th of November, setting the stage for prospective medical students across the globe. directed by reliable sources such as UniversItaly for EU candidates […]
- [BMAT 2009 Section 2 Question 10](https://samiqamar.com/bmat-2009-section-2-question-10/): 2.00g of a carbon compound is burnt in excess oxygen.4.77g of carbon dioxide is produced.What percentage (to the nearest 1%) of carbon is in the original compound? A 21%B 26%C 42%D 52%E 65% Answer: 10) E Mass of CO₂ produced = 4.77 g Mr of CO₂ = 12 + 16 + 16 = 44Moles = Mass ÷ Mr = 4.77 ÷ 44 ≈ 0.1 Molar ratio of (C : CO₂) = 1 : 1Moles of C = 0.1 mol Mass of C = 0.1 x 12 = 1.2 g Percentage = (1.2 / 2) x 100 = 60% This is closest […]
- [BMAT 2009 Section 2 Question 9](https://samiqamar.com/bmat-2009-section-2-question-9/): The data below considers the risk of having a cancer in the neck region due to drinking alcoholand one genetic factor (presence of a mutant allele for the CYP1A1 gene). A risk value of 1.0 isthe mean average risk in the human population. Using only the data from the table, which of the following tentative conclusions about the risk of having a cancer of the neck, is not correct? Answer: 9) D A – CorrectThe table shows that when number of mutant alleles increase from 0 to 1, the risk value also increases from 1.0 to 1.5 in the light drinker […]
- [BMAT 2009 Section 2 Question 8](https://samiqamar.com/bmat-2009-section-2-question-8/): A cube has unit length sides. What is the length of a line joining a vertex to the midpoint of oneof the opposite faces (the dashed line in the diagram below)? Answer: 8) B Let the dashed line be called L.Let length of each side = 1 We first need to calculate the length of half of the diagonal of one of the faces.Let diagonal be = D Using Pythagoras,D² = 1² + 1²D² = 1 + 1 = 2D = √2 Half of D = √2                    2 Imagine the dashed line forming […]
- [BMAT 2007 Section 2 Question 1](https://samiqamar.com/bmat-2007-section-2-question-1/): The table shows the percentages of some substances measured in fluid taken from a human kidney.Which letter on the diagram shows the most likely source of the fluid? Answer: 1) B A – if it was A, there would be some protein present.Water is reabsorbed and glucose is completely reabsorbed as we progress through the kidney. This would lead to an increase in the percentage of urea in the fluid. Since the percentage of urea is only a little, the sample must have been taken from an initial part of the nephron. Therefore, the answer is B.
- [BMAT 2009 Section 2 Question 7](https://samiqamar.com/bmat-2009-section-2-question-7/): Which of the following is a correct unit of potential difference (voltage)?A amp per ohmB coulomb per jouleC joule per secondD newton per coulombE watt per amp Answer: 7) E A – WrongVoltage = current x resistance = amp x ohm. Hence amp/ohm is wrong. B – Wrong We cannot prove voltage = coulomb per joule C – Wrong joule/second is the unit of power D – WrongWe cannot prove voltage = newton per coulomb E – Wrong We know power = voltage x current. voltage = power/current = watt/amp = watt per amp
- [BMAT 2009 Section 2 Question 6](https://samiqamar.com/bmat-2009-section-2-question-6/): Which one of the following covalent substances could exist as a giant structure? A SiCl4B SiO2C IClD Cl2OE H2SF CF4 Answer: 6) B Out of all the options, SiO₂ is the only molecule which can form giant structure. Silicon is a large molecule as has more diffuse valence orbitals. This allows it to form giant structures.
- [BMAT 2006 Section 2 Question 27](https://samiqamar.com/bmat-2006-section-2-question-27/): A small conducting sphere is held at a fixed distance from a larger sphere which is continually charged by a generator. The surface area of the large sphere is 0.04m^2, and it discharges by sparking to the small sphere when the charge density on the large sphere reaches 0.25 C/m². charge density = charge per unit surface area If the large sphere is charged at a rate of 2 mA, calculate the time interval (in seconds) between sparks. Answer: 27) 5 seconds Current (I) = Charge (Q) ÷ time (t) I = Q ÷ t We know charge density = charge […]
- [BMAT 2009 Section 2 Question 5](https://samiqamar.com/bmat-2009-section-2-question-5/): Which one of the following statements is true about the members of a clone? Answer: 2009 Section 2 Question 5 5) E A – Wrong Clones will not always have identical external features due to the environment. B – WrongThis is not necessarily true as twins show some differences between each other. They can also be non-identical C – WrongClones can occur naturally in the environment too in asexual reproduction. D – Wrong If mutation did occur, there would be some sort of variation in their DNA and genes. Mutation is the complete opposite of clones. E – Wrong Clones contain identical DNA and […]
- [BMAT 2006 Section 2 Question 26](https://samiqamar.com/bmat-2006-section-2-question-26/): a is inversely proportional to the square of b.When a = 9 , b = 4.What is the positive value of b when a = 4 ? Answer: 26) A ‘a’ is inversely proportional to ‘b²’.a ∝ 1/b² In order to turn this inequality into an equation, we need to use a constant (let us say ‘k’) a ∝ 1/b²a = k/b² When a = 9, b = 4a = k/b²9 = k/4²k = 9 x 4² = 9 x 16 = 144 When a = 4, b = ?a = k/b²b² = k/ab² = 144/4b² = 36b = 6
- [BMAT 2009 Section 2 Question 4](https://samiqamar.com/bmat-2009-section-2-question-4/): A bag contains x red balls, y blue balls and z yellow balls. One ball at random is taken out andreplaced. A second ball at random is taken out and replaced.If the balls are identical in all respects except colour and are well mixed, what is the probability that the first ball was red and the second blue? Answer: 4) C Total number of balls = (x + y + z) Probability of first ball being red  =          x                                      […]
- [BMAT 2009 Section 2 Question 3](https://samiqamar.com/bmat-2009-section-2-question-3/): Shortly after opening her parachute, a free-fall parachutist of mass 60kg experiences the forcesshown in the diagram. Which line in the table gives the size and direction of the acceleration of the parachutist at this instance? Answer: 3) C Resultant force = 900N – 600N = 300N upwards Direction would be upwards as the drag force (upward force) is greater than weight (downward force). We know that Force = mass x acceleration; Acceleration = Force/Mass Force = 300NMass = 60kg (given in question)Acceleration = Force/Mass = 300/60 = 5 m/s²
- [BMAT 2009 Section 2 Question 2](https://samiqamar.com/bmat-2009-section-2-question-2/): Which of the following could take part in an addition polymerisation?1 CHI₃ 2 C₂₄H₄₈ 3 C₃H7Br 4 C₄H₆Cl₂ 5 C₈H₁₂Cl₄ Answer: 2) E Only molecules that contain a double bond can participate in an addition polymerisation. Such molecules have twice as many other atoms as there are carbon atoms. e.g. C₃H₆, C4H8  The only molecules that contain twice as many other atoms as carbon atoms in the molecule are C₂₄H₄₈, C₄H₆Cl₂, C₈H₁₂Cl₄
- [BMAT 2009 Section 2 Question 1](https://samiqamar.com/bmat-2009-section-2-question-1/): Individual A in the family pedigree below is homozygous dominant and individual B is homozygous recessive for a particular feature. What is the percentage probability that individual F is homozygous recessive if: Answer: 1) C Firstly, we must find out what D is.                  R                                    R r               Rr                                   Rr r       […]
- [BMAT 2006 Section 2 Question 25](https://samiqamar.com/bmat-2006-section-2-question-25/): In stars four protons, p, are fused together to form helium, He, with a mass of four units, by the following processes. Which one of the following shows the overall change that has taken place when He is formed? (e^+ is a positively charged electron, n is a neutron, H is a hydrogen of mass two and He is helium of mass three.) Answer: 25) B The equations are made to confuse you.Helium has a mass number of 4 because it has 2 protons and 2 neutrons.We are given the information that 4 protons are used to make Helium.Since a Helium […]
- [BMAT 2006 Section 2 Question 24](https://samiqamar.com/bmat-2006-section-2-question-24/): The statements are about respiration.1 Aerobic respiration releases more energy per unit mass of glucose than anaerobic respiration.2 Aerobic respiration in muscles causes an oxygen debt to occur.3 Aerobic respiration forms carbon dioxide as the only waste product.4 Reduced aerobic respiration will limit the active uptake of mineral ions in the kidney tubules.5 When there is little oxygen available to muscles only anaerobic respiration occurs.6 Anaerobic respiration forms lactic acid as the only waste product.Which statements are correct? 24) E 1 – CorrectThe statement itself is correct. This require pre-requisite knowledge of aerobic respiration and anaerobic respiration. 2 – WrongAnaerobic respiration […]
- [BMAT 2006 Section 2 Question 23](https://samiqamar.com/bmat-2006-section-2-question-23/): The diagram shows the dispersion of white light as it passes from air into glass. Red light travels at speed c in air, but only 2c/3 in glass. Red light has a wavelength of λ in air. What is the frequency of red light, and the speed of blue light in glass? Answer: 23) C The equation for speed (c) with relation to wavelength (λ) and frequency (ƒ) is: c = ƒ x λƒ = c/λ Speed of red light in glass = 2c/3Now, wavelength is directly proportional to speed. Since speed decreases, wavelength also decreases by by same amount.Wavelength of […]
- [BMAT 2006 Section 2 Question 22](https://samiqamar.com/bmat-2006-section-2-question-22/): The energy profile for a reaction is shown below. Which of the following is a fully correct statement about this energy level profile? Answer: 22) D Let us start by identifying what the letters are. The reaction is endothermic (energy is absorbed during the reaction) since products have more energy than reactants. A:Reaction is endothermic – CorrectV is the heat of reaction – CorrectX is the activation energy – WrongSo, A is wrong. B:Products (Z) have more energy than the reactants (U) – CorrectX shows the route taken when a catalyst is present – WrongW is the activation energy – WrongSo […]
- [BMAT 2006 Section 2 Question 21](https://samiqamar.com/bmat-2006-section-2-question-21/): Evaluate? Answer: 21) 9 If you are not sure about solving powers, click here. Let us solve the values given in the problem individually. 32^¹⁄₅ = ⁵√32 = 2 9⁰ = 1 81^¾ = (⁴√81)³⁴√81 = 3(⁴√81)³ = (3)³ = 27 So we have:²⁺¹⁄₂₇ = ³⁄₂₇ = ¹⁄₉ We also have a (⁻¹) power too.So (¹⁄₉)⁻¹ = 9
- [BMAT 2006 Section 2 Question 20](https://samiqamar.com/bmat-2006-section-2-question-20/): Five identical resistors are connected to a cell as in the diagram. The potential differences across R1 , R2 and R3 are V1, V2 and V3 respectively. What is the order of increasing potential differences (smallest first)? Answer: 20) E Parallel circuits rule: Voltage is equal in all branches.Hence the two branches of the given circuit must have the same voltage. Circuits rule: Resistance in series is always greater than resistance in parallel. In branch 1, the resistors are in series. In branch 2, resistors are in parallel. Hence, branch 1 has more resistance than branch 2.Since current is inversely proportional […]
- [BMAT 2006 Section 2 Question 19](https://samiqamar.com/bmat-2006-section-2-question-19/): Which row of the table shows the response of the iris to reducing levels of light? Answer: 19) C This is no longer on the BMAT syllabus. However, you should have been able to at least eliminate options A and D. This is because when levels of light are reducing, the pupil would get bigger (dilated) to allow more light to enter the eye. To allow the pupil to dilate, the radial muscles need to contract and the circular muscles need to relax.
- [BMAT 2006 Section 2 Question 18](https://samiqamar.com/bmat-2006-section-2-question-18/): The table shows some details of the composition of inhaled and exhaled air of a student. The student is breathing 500 cm³ of air 14 times per minute. How many dm³ of oxygen will be absorbed into the lung capillaries in 4 minutes? A 0.14 dm³ B 0.35 dm³ C 1.4 dm³ D 3.5 dm³ E 35.0 dm³ F 140.0 dm³ Answer: 18) C Volume of air inhaled in 1 minute = 500 x 14= 7000cm³ = 7dm³Volume in 4 minutes = 7 x 4 = 28dm³Volume of oxygen inhaled in 4 min = 0.21 x 28 = 5.88 dm³Volume of […]
- [BMAT 2006 Section 2 Question 17](https://samiqamar.com/bmat-2006-section-2-question-17/): The element has a mass number of 40 and an atomic number of 20. Consider the statements and decide which of them are correct. 1 The nucleus has a relative mass of 20. 2 It is a noble gas. 3 It would form a negative ion. 4 It is in group 2 of the periodic table. 5 It is a non-metallic element. Answer: 17) E The mass number is given as 40. So the nucleus’ relative mass must also be 40. Therefore, 1 is incorrect. Noble gases have full outer shells. This element has an atomic number of 20. So the […]
- [BMAT 2006 Section 2 Question 16](https://samiqamar.com/bmat-2006-section-2-question-16/): An object with a mass of 20 kg is lifted by the arrangement shown in the diagram. Air resistance (drag) can be ignored, and the gravitational field strength (acceleration due to gravity) can be taken as 10 N/kg. What is the acceleration of the object, in m/s²? Answer: 16) 2m/s² Downward force (Weight of object) = 20 x 10 = 200NUpward force = 120 + 120 = 240 NResultant force = 240-200 = 40 N Force = mass x acceleration40 = 20 x aa = 40 ÷ 20 = 2 m/s²
- [BMAT 2006 Section 2 Question 15](https://samiqamar.com/bmat-2006-section-2-question-15/): The diagram shows part of the circulatory system Which row of the table identifies the blood vessels that best fit the descriptions after eating a carbohydrate rich meal? Answer: 15) E When the concentration of glucose is high, it gets converted to glycogen and stored in the liver. This is why glucose concentration must be high in the blood vessel connecting stomach&intestines and liver (2). This leaves us with options C and E. Urea is a waste product produced by the breakdown of protein in the liver. Since it is produced by the liver, it must go back into the blood […]
- [BMAT 2006 Section 2 Question 14](https://samiqamar.com/bmat-2006-section-2-question-14/): Find the positive solution of the following simultaneous equations: Answer: 14) x = 3 ; y = 1 2x – y = 5y = 2x – 5 Substitute this expression of ‘y’ into the first equation.4x² + (2x – 5)² + 10 (2x – 5) = 474x² + (4x² – 20x + 25) + (20x – 50) = 474x² + 4x² – 20x + 25 + 20x – 50 = 478x² – 25 = 478x² = 72x² = 9x = 3 Substitute this value of ‘x’ into the second equation.y = 2 (3) – 5y = 6 – 5 = 1
- [BMAT 2006 Section 2 Question 13](https://samiqamar.com/bmat-2006-section-2-question-13/): At 200 °C, potassium hydrogencarbonate decomposes according to the following equation. What is the loss in mass when 50.0 g of potassium hydrogencarbonate are heated at 200 °C to constant mass? Answer: 13) B Mr of 2KHCO₃ = 2(39 + 1 + 12 + 48) = 200moles of KHCO₃ = m/Mr = 50 ÷ 200 = 0.25 moles of K₂CO₃ = 0.25 ÷ 2 = 0.125mass of K₂CO₃ = 0.125 x 138 = 34.5g The loss in mass is calculated as the mass of the gases (H₂O and CO₂) produced.Loss in mass = Mass of KHCO₃ – Mass of K₂CO₃ = […]
- [BMAT 2006 Section 2 Question 12](https://samiqamar.com/bmat-2006-section-2-question-12/): In statistics Spearman’s rank correlation coefficient is given by the formula: Rearrange the formula to make ∑ 2 d the subject: Rearrange the formula to make ∑ 2 d the subject Answer: 12) E We need to get rid of the 1 from the right hand side first. So we get: r – 1 =  (-) 6 Σd²             n (n² – 1) We need to get rid of the (-) sign from RHS, 1 – r =  6 Σd²            n (n² – 1) Solving n (n² – 1), we get = n³ – […]
- [BMAT 2006 Section 2 Question 11](https://samiqamar.com/bmat-2006-section-2-question-11/): A force F is applied to the piston X of a brake pedal. This force is transmitted, hydraulically, to piston Y as shown in the diagram. Diameter of piston X = 2 cm.Diameter of piston Y = 20 cm.The pressure applied at X is 2 N/cm^2 .What is the pressure transmitted to Y? Answer: 11) C No calculations required for this question. The pressure applied at X will remain the same at Y.
- [BMAT 2006 Section 2 Question 10](https://samiqamar.com/bmat-2006-section-2-question-10/): A gene controls the production of chlorophyll in lettuce plants. The recessive allele of this gene blocks chlorophyll formation which prevents seedling development. Plants heterozygous for this gene were cross bred and 1000 of their seeds were planted. Only about 750 developed into mature plants. What percentage of these mature plants would be heterozygous for this gene? Answer: 10) D Let ‘T’ be the dominant allele and let ‘t’ be the recessive allele.                               T                         […]
- [BMAT 2006 Section 2 Question 9](https://samiqamar.com/bmat-2006-section-2-question-9/): Which changes to the conditions will increase the yield of the salt in the exothermic reaction shown? Answer: 9) B Firstly, catalysts do not affect the equilibrium position and so, 1 is incorrect. This rules out options A, D and F. Adding more ammonia will favour the forward reaction, which desirable. So 2 is correct. This rules out option C. Increasing the pressure will favour the forward reaction, which will increase the yield of salt. So, 3 is correct. Increasing the temperature will favour the backward endothermic reaction and hence, the salt yield will decrease. So 4 is incorrect and this […]
- [BMAT 2006 Section 2 Question 8](https://samiqamar.com/bmat-2006-section-2-question-8/): A health club monitors the average heart rate of its members when using a cardiovascular workout machine. The lower quartile of the heart rate is 115, the upper quartile is 165. What is the probability that when a group of 4 members is chosen at random at least 3 of them had an average heart rate of more than 165 when doing this workout? Answer: 8) C Upper quartile means 75% to 100%.Difference = 100 – 75 = 25% Probability of a person having a heart beat of 165 or more = 25% ÷ 100% = ¼ 4 members were chosen. […]
- [BMAT 2006 Section 2 Question 7](https://samiqamar.com/bmat-2006-section-2-question-7/): The following statements can be applied to certain types of wave:1 Their oscillations are longitudinal.2 They travel at the speed of light in air.3 They are used in pre-natal scanning.4 They are used in thermal imaging.5 They will not travel through a vacuum.Which of these statements can be applied to microwaves? Answer: 7) A Microwaves are transverse waves. So 1 is not correct.Microwaves travel at the speed of light. So 2 is correct For pre-natal scanning, ultrasound is used. So 3 is not correctInfrared is used for thermal imaging. So 4 is not correct.Microwaves along with other EM waves travel in […]
- [BMAT 2006 Section 2 Question 6](https://samiqamar.com/bmat-2006-section-2-question-6/): The sides of triangle ABC are as follows: AB = 3, AC = 2, BC = 4. Use the cosine rule, a^2=b^2+c^2-2bc cosA , to find the cosine of ∠BAC Answer: 6) This is no longer in your BMAT specification. If you do not know how to do it, then skip the question and move on! You cannot afford to waste time in the BMAT, especially in Section 2. Draw the triangle out first. A visual representation always helps. a = BC = 4b = AC = 2c = AB = 3A = ∠BAC a² = b² + c² – 2bc […]
- [BMAT 2006 Section 2 Question 5](https://samiqamar.com/bmat-2006-section-2-question-5/): Listed are the electronic configurations for the atoms of different elements. Which one represents the most reactive non-metal? Answer: 5) C As you go along a period, reactivity of non-metal increases since their electronegativity increases. Therefore, the halogens are the most reactive non-metals within each period. Noble Gases ARE NOT the most reactive since they are inert. As you can see from the periodic table below, reactivity increases across a period and up a group for non-metals. Therefore, Fluorine is the most reactive non-metal. The electronic configuration for Fluorine is 2,7. Hence, C is the answer
- [BMAT 2006 Section 2 Question 4](https://samiqamar.com/bmat-2006-section-2-question-4/): The amount of water in urine is controlled by the hormone ADH. Which sequence of events will occur when you need to keep water in your body? Answer: 4) B Always remember that when water needs to be kept in the body, the urine produced will be concentrated. This eliminates A, C and F. Since, water needs to be kept in the body, more water must be reabsorbed from the nephrons. In order to reabsorb more water, ADH production must increase. This is shown only by B.ADH (Anti-Dieuretic Hormone) reabsorbs water from kidney.
- [BMAT 2006 Section 2 Question 3](https://samiqamar.com/bmat-2006-section-2-question-3/): A particular radioisotope X with a half-life of 4 years decays into the stable isotope Y. At a particular time, a sample contains 32 x 10²º atoms of nuclide X and 4 x 10²º atoms of nuclide Y. How many atoms of nuclide Y will be present in the sample 8 years later? Answer: 3) F Number of half-lives after 8 years = 8/4 = 2 half-livesNumber of atoms of X left after 8 years = 32×10²⁰ ÷ (2×2) = 8×10²⁰ We know all of the X atoms decay into isotope Y.Number of X atoms that decay = 32×10²⁰ – 8×10²⁰ = 24×10²⁰We […]
- [BMAT 2006 Section 2 Question 2](https://samiqamar.com/bmat-2006-section-2-question-2/): Compound T has a melting point of 78 °C and a boiling point of 134 °C. T is soluble in water and its solution does not conduct electricity. T has covalent bonding and has a simple molecular structure. Which property of T is not usually associated with its bonding and structure? Answer: 2) C The melting temperature and boiling temperature are normal and the fact that they lack of  conductivity of its solution is reasonable. However the property of solubility in water is not normal as simple molecular structures are usually insoluble in water.
- [BMAT 2006 Section 2 Question 1](https://samiqamar.com/bmat-2006-section-2-question-1/): The graph shows changes in the mass of glycogen stored in the liver and skeletal muscles. During which periods will the concentration of insulin in the blood be below normal? Answer: 1) E Remember that insulin converts glucose to glycogen so it can be stored in the liver and in the muscles. Therefore, when insulin levels drop in the blood, glycogen synthesis will also decrease. This can be seen in time periods 3 and 5; when glycogen levels are decreasing, meaning that insulin concentration is below normal.
- [BMAT 2005 Section 2 Question 27](https://samiqamar.com/bmat-2005-section-2-question-27/): A circle has a diameter of 20cm. The line AC is a diameter of the circle. B is a point on the circumference of the circle with AB = 12cm. The point D lies on the arc AC on the opposite side to point B. What is the sine of ∠BDC? Answer: 27) 0.8 Let the centre of the circle be O. Here is how the diagram should look like: AO = CO = 10 cm Since D is opposite B, BD is also a diameter of the circle, meaning:BO = DO = 10 cm We know that triangle ABC is […]
- [BMAT 2005 Section 2 Question 26](https://samiqamar.com/bmat-2005-section-2-question-26/): Which of the following thermal decomposition reactions will require the highest temperature? Answer: 26) D This requires to remember the reactivity series off by heart as such question do often come up. Na is the most reactive and it will require the most energy to break its oxide. Hence reaction D would enquire the highest temperature.
- [BMAT 2005 Section 2 Question 25](https://samiqamar.com/bmat-2005-section-2-question-25/): A heart exerts a maximum (systolic) pressure of 152mm Hg. This pressure is applied to an aorta of cross sectional area 2.0cm2 What force must be generated by the heart in order to apply this pressure? (Take 760mm Hg to be 1.0 atmosphere which is 100kPa.) Answer: 25) B 760 mm Hg has a force of 100kPa.152 m Hg would have a force of = [(152 ÷ 760) x 100] = [0.2 x 100 kPa] = 20 kPa = 20 x 10³ Pa 2.0 cm² = 0.0002 m² Pressure = Force ÷ Area 20 x 10³ Pa = Force ÷ 0.0002 […]
- [BMAT 2005 Section 2 Question 24](https://samiqamar.com/bmat-2005-section-2-question-24/): During the fetal stage an opening, the foramen ovale, exists in the septum between the two atria. This allows blood to flow from the right atrium to the left atrium.The opening should close during birth. If this fails to happen, which one of the following is the main problem to the health of the baby? Answer: 24) A If the foramen ovale does not close, the deoxygenated blood from the right atrium will mix with the oxygenated blood in the left atrium.This will cause the aorta (which carries oxygenated blood from left ventricle to the body) to carry some deoxygenated blood. […]
- [BMAT 2005 Section 2 Question 23](https://samiqamar.com/bmat-2005-section-2-question-23/): A sample of butane, C4H10 is treated with deuterium, D (an isotope of hydrogen) and some of the hydrogen atoms are replaced by deuterium atoms. Analysis shows that the substituted butane contains 80.0% of carbon by mass. Which one of the following is its formula? (Ar: H=1; D=2; C=12) Answer: 23) B Butane would always have 4 carbon atoms.Mr of 4 carbon atoms = 12 x 4 = 48 80% = 481% = 48 ÷ 80 = 0.6100% = 0.6 x 100 = 60 So the mass of butane = 60 Mass that must be made by deuterium and hydrogen = […]
- [BMAT 2005 Section 2 Question 22](https://samiqamar.com/bmat-2005-section-2-question-22/): When a 1kg mass is dropped from the top of a building 20m high it hits the Earth with a speed of 20m/s. What would be its speed if the same experiment was carried out on a planet where the acceleration due to gravity is ¼ that on Earth? Answer: 22) D Acceleration on Earth = 10 m/s²¼ of Earth’s acceleration = 2.5 m/s² u = 0a = 2.5s = 20v = ? v² – u² = 2as Since u = 0,v² = 2 (2.5) (20) v² = 5 x 20 = 100 v = 10 m/s²
- [BMAT 2005 Section 2 Question 21](https://samiqamar.com/bmat-2005-section-2-question-21/): In the shape shown below, A, B and C are the vertices of an equilateral triangle, side length xcm. The arc AC forms a semicircle. Which of the following alternatives is a correct expression for the area, in cm^2, of the shape? Answer: 21) A The third side of the equilateral triangle is the diameter of the semi-circle. Therefore, diameter of semi-circle = ‘x’ cm Radius = ½x = (ˣ⁄₂) We first need to find the area of the equilateral triangle. In order to do this, we need to find its height using Pythagoras theorem. Divide the equilateral triangle into two right-angled triangles.Hypotenuse […]
- [BMAT 2005 Section 2 Question 20](https://samiqamar.com/bmat-2005-section-2-question-20/): The table shows the concentrations, in arbitrary units, of four substances. These substances are present in each of two animal cells, K and L, whose cell membranes are in contact. Which movement of a substance between the two cells requires oxygen? Answer: 20) C Oxygen is only required for active transport. Active transport is the movement of molecules from a region of lower concentration to a region of higher concentration. (opposite of diffusion) A – WrongCytosine will move from L to K from a region of higher concentration to lower concentration. So movement of cytosine from L to K would not […]
- [BMAT 2005 Section 2 Question 19](https://samiqamar.com/bmat-2005-section-2-question-19/): A sample of an acid, H2X, weighing 4.5g was dissolved in water. This solution was neutralised by 50.0cm3 of aqueous sodium hydroxide containing 2mol/dm3. What is the relative molecular mass, Mr, of the acid? Answer: 19) B Volume of NaOH = 50 cm³ = 0.05 dm³Moles of NaOH = c x v = 2 x 0.05 = 0.1 mol Molar ratio of NaOH : H₂X = 2 : 1 So moles of H₂X = 0.1 ÷ 2 = 0.05 mol Mr of acid = Mass ÷ Moles Mr = 4.5 ÷ 0.05 = 90 19) B Volume of NaOH = 50 […]
- [BMAT 2005 Section 2 Question 18](https://samiqamar.com/bmat-2005-section-2-question-18/): A sample of rock contains 235U and 207Pb in the proportion one part 235U to seven parts 207Pb. It is known that 235U decays to 207Pb with a half life of 7.1 × 108years. the maximum possible age of the rock is Answer: 18) B Total number of parts = 7 + 1 = 8The maximum age would be when the rock contained 8 parts of ²³⁵U. Here are the half lives: Half – life  ²³⁵U  ²⁰⁷Pb 0 8 0 1 4 4 2 2 6 3 1 7 So it was after 3 half-lives that the ratio became 1 : […]
- [BMAT 2005 Section 2 Question 17](https://samiqamar.com/bmat-2005-section-2-question-17/): Evaluate: Answer: 17) A We know the general quadratic formula (a – b)² = a² – 2ab + b² So we have, (√5 – √2)² = (√5)² – [2 (√5) (√2)] + (√2)² (√5)² – [2 (√5) (√2)] + (√2)² = 5 – 2√10 + 2 = 7 – 2√10 We know the general quadratic formula (a + b)² = a² + 2ab + b² (√5 + √2)² = (√5)² + [2 (√5) (√2)] + (√2)²(√5)² + [2 (√5) (√2)] + (√2)² = 5 + 2√10 + 2 = 7 + 2√10 So we have: (√5 – √2)² (√5 + √2)² = (7 […]
- [BMAT 2005 Section 2 Question 16](https://samiqamar.com/bmat-2005-section-2-question-16/): The diagram shows three sections, separated by hinge-like joints, of the leg of a crab with an exoskeleton. By comparison with the elbow joint of a human, select the letters that match the following Answer: 16) A This is no longer on the BMAT syllabus.
- [BMAT 2005 Section 2 Question 15](https://samiqamar.com/bmat-2005-section-2-question-15/): The reaction between nitrogen and hydrogen to form ammonia is exothermic The strengths of the bonds in the three molecules are as shown. Which statement can be deduced from this information? Answer: 15) D Number of N ≡ N bonds in reactants = 1Total energy of N ≡ N bonds in reactants = 1 * x = xNumber of H – H bonds in reactants = 3Total energy of H – H bonds in reactants = 3 x y = 3y Number of N – H bonds in products = 3 x 2 = 6Total energy of N – H bonds in products = 6 x z = […]
- [BMAT 2005 Section 2 Question 14](https://samiqamar.com/bmat-2005-section-2-question-14/): A pulse of frequency 100kHz is emitted from an ultrasound scanner, and is reflected from a fetus 10cm below the transmitter placed on the mother’s abdomen. The speed of sound within the mother’s body is 500m/s. How long does it take for the pulse to reach the receiver which is adjacent to the transmitter? Answer: 14) B Distance of transmitter from abdomen = 10 cm = 0.1 mTime taken to reach the abdomen = Distance ÷ Time = 0.1 ÷ 500 = 0.0002 s Since the receiver is adjacent to the transmitter, distance from the abdomen to receiver must also equal […]
- [BMAT 2005 Section 2 Question 13](https://samiqamar.com/bmat-2005-section-2-question-13/): Rearrange the following equation to give x in terms of y. Answer: 13) A y = ⎡x² + 2ax⎤½       ⎣     b       ⎦ y² = x² + 2ax            b     by² = x² + 2ax This is a bit tricky. (x² + 2ax) is part of (x + a) (x + a) = x² + 2ax + a² (x + a) (x + a) = x² + 2ax + a²x² + 2ax = (x + a) (x + a) – a² So we get, by² = (x + a) (x + a) – a²by² […]
- [BMAT 2005 Section 2 Question 12](https://samiqamar.com/bmat-2005-section-2-question-12/): Which row of the table shows what occurs in the eye when you watch a bird flying away from you? Answer: 12) B Don’t worry if you do not know the answer to this as this is no longer on the BMAT specification. When looking away, you need to cover more area. The suspensory ligaments tighten to make the lens less convex so you can do so and the ciliary muscles relax. So the answer is B
- [BMAT 2005 Section 2 Question 11](https://samiqamar.com/bmat-2005-section-2-question-11/): Which fraction is the percentage by mass of water of crystallisation in sodium carbonate decahydrate? (Relative atomic masses, Ar: Na=23; C=12; O=16; H=1) Answer: 11) D Sodium carbonate = Na₂CO₃ Decahydrate means 10 moles of water. (deca = 10) So the formula of sodium carbonate decahydrate = Na₂CO₃.10 H₂O Mr of sodium carbonate decahydrate = (23 x 2) + (12 x 1) + (16 x 3) + (2 x 10) + (16 x 10)(23 x 2) + (12 x 1) + (16 x 3) + (2 x 10) + (16 x 10) = 46 + 12 + 48 + 180 Since […]
- [BMAT 2005 Section 2 Question 10](https://samiqamar.com/bmat-2005-section-2-question-10/): A uniform beam of length 60cm weighs 10N. Its centre of gravity (the point where its weight can be assumed to act) is at its centre. A weight of 800N rests at one end of the beam as shown, and the beam is balanced by another weight of 200N placed at distance x from the pivot. What is distance x in cm? Answer: 10) 39 cm The problem requires the knowledge of Moments. Length of beam = 60cmThe weight always acts on the centre of an object. In this case, the centre is (60 ÷ 2) = 30cm.Weight of beam = […]
- [BMAT 2005 Section 2 Question 9](https://samiqamar.com/bmat-2005-section-2-question-9/): Two variables are connected by the relation: A∝ 1/B2 B is increased by 40%. Describe the change in A in percentage terms Answer: 9) C Increase by 40% = 140% = 1.4 A ∝     1            (1.4B)² A ∝   1          1.96B The fraction (1 / 1.96) is just above 50% (50% of 1.96 = 0.98) So the decrease in percentage terms of A must be just under 50%. So C is the answer.
- [BMAT 2005 Section 2 Question 8](https://samiqamar.com/bmat-2005-section-2-question-8/): The length of a person’s eyelashes is controlled by a single gene. The diagram shows the inheritance of this feature in a family. Which individual, A, B, C, D, or E, must be heterozygous for eyela Answer: 8) A If the long lashes were caused by being homozygous recessive then A and her mate would have to be homozygous recessive. If both were homozygous recessive, then all of their offsprings would also have to be homozygous recessive and have long lashes. However, that is not the case. So the long lashes is caused by the presence of a dominant allele. So […]
- [BMAT 2005 Section 2 Question 7](https://samiqamar.com/bmat-2005-section-2-question-7/): During metabolism, two molecules of pyruvic acid, C3H4O3, are formed from one moleculeof glucose, C6H12O6. Answer: 7) A You will realise that the number of hydrogen atoms do not add up to the original 12. There are 4 hydrogen atoms in each molecule of pyruvic acid. Since there are two molecules, total number of hydrogen = 4 x 2 = 8 So 4 atoms of hydrogen are lost. When hydrogen is lost, the molecule becomes oxidised. Since one big molecule is broken into two smaller ones, decomposition occurs. So the answer is A: oxidation and decomposition.
- [BMAT 2005 Section 2 Question 6](https://samiqamar.com/bmat-2005-section-2-question-6/): Using the formula:z = xy^2 Answer: 6) C z = xy² y² = 1.2 x 10¹³         3 x 10⁻⁶ 1.2 x 10¹³ = 3 x 10⁻⁶ (y²) y² = 0.4 x 10¹⁹ y² = 4 x 10¹⁸ y = 2 x 10⁹
- [BMAT 2005 Section 2 Question 5](https://samiqamar.com/bmat-2005-section-2-question-5/): Smoking cigarettes can lead to emphysema. This occurs because. Answer: 5) A Emphysema is a condition in which lungs and air sacs are damaged, causing breathlessness. Breathlessness is caused by shortage of oxygen. If carbon monoxide reduces the supply of oxygen to the body cells, then this would cause emphysema. Carbon monoxide binds to the red blood cells and prevents the red blood cells from carrying oxygen to the body cells. B – WrongDamage to cilia will not interfere with transport of oxygen C – WrongRapid growth of cells is called cancer not emphysema. D – WrongCoughing cannot really cause emphysema. E – […]
- [BMAT 2005 Section 2 Question 4](https://samiqamar.com/bmat-2005-section-2-question-4/): Four 1000Ω resistors are connected as shown in the following circuit. Two of the resistors are changed to 900Ω. Changing which pair of resistors would make a current flow in the ammeter? Answer: 4) C No calculations needed for this question.  Current follows the path with least resistance.  A – WrongIf resistance of p and q becomes lower, then the current will only flow through the top branch. It will not go down to the ammeter from the top branch. B – WrongIf resistance of p and q becomes lower, then the current will split equally between top and bottom branch. […]
- [BMAT 2005 Section 2 Question 3](https://samiqamar.com/bmat-2005-section-2-question-3/): One type of fission of 23892 U gives 9538 Sr and 13954 Xe as the main products.What else would be given off in the fission reaction? Answer: 3) D We need to calculate the difference in mass numbers and atomic numbers. Mass number of U = 238Sum of mass number of products Sr and Xe = 95 + 139 = 234 Atomic number of U = 92Sum of atomic numbers of products Sr and Xe = 38 + 54 = 92 Atomic number is same, meaning that no protons are emitted. Since the mass number decreases by 4 and no protons […]
- [BMAT 2005 Section 2 Question 2](https://samiqamar.com/bmat-2005-section-2-question-2/): You are told that three different gas jars contain carbon dioxide, hydrogen and oxygenrespectively.Which single method of testing for gases will enable you to identify all three gases? Answer: 2) B A – WrongBromine water is the test for the presence of alkenes. B – CorrectA burning splint makes a popping sound in hydrogen, goes out in carbon dioxide and then the glowing splint relights in oxygen.  C – WrongLimewater turns milky in the presence of carbon dioxide. However, no observations are made in the presence of hydrogen and oxygen.  D – WrongThis is the test for acids. Blue litmus turns […]
- [BMAT 2005 Section 2 Question 1](https://samiqamar.com/bmat-2005-section-2-question-1/): The movement of air in and out of the lungs can be measured using a spirometer. The graph is a trace from a spirometer Which lettered arrow represents the tidal volume? Answer: 1) A A – CorrectTidal volume is the volume of air displaced in the absence of extra respiratory effort.  B – WrongB represents the total lung capacity. C – WrongInspiratory reserve volume D – WrongResidual volume E – WrongInspiratory capacity
- [BMAT 2004 Section 2 Question 27](https://samiqamar.com/bmat-2004-section-2-question-27/): The sum of the roots of a quadratic equation is 7, the product of the roots is 9. What is theequation? Answer: 27) C To solve this, we need to use the equation: (x – a) (x – b) = (x² – xb – xa + ab), where a and b are the solutions. x² – xb – xa + ab = x² – x (b + a) + ab We know that the sum of the roots of the quadratic equation is 7 and the product is 9.i.e. (a + b) = 7 and (ab) = 9. So, we need […]
- [BMAT 2004 Section 2 Question 26](https://samiqamar.com/bmat-2004-section-2-question-26/): The list below describes some events that occur during nuclear division. Indicate, by shading the appropriate circles on the answer sheet, which events occur during mitosis and which occur during meiosis. Answer: 26) i) mitosis, ii) both, iii) meiosis, iv) meiosis, v) both i) MitosisIn mitosis, the daughter nuclei are always genetically identical to the parent cells or nucleus. ii) BothIn order to carry out nuclear division, both processes must involve all chromosomes being replicated. iii) MeiosisGametes can only be produced by meiosis. Since gametes are haploid, they must be formed by meiosis as mitosis only forms diploid cells. iv) MeiosisHaploid […]
- [BMAT 2004 Section 2 Question 25](https://samiqamar.com/bmat-2004-section-2-question-25/): For a rigid body performing small oscillations about a fixed horizontal axis, the period of oscillations is given by. where h is the distance of the centre of mass from the axis, g is the acceleration due to gravity, and k is the radius of gyration of the body about a parallel axis through the centre of mass. Rearrange the formula to make k the subject. Answer: 25) D We first need to square both the LHS and RHS. We get:T² = ⎡2π  √(k² + h²) ⎤²       ⎣          √gh      ⎦ T² = ⎡4π² (k² + […]
- [BMAT 2004 Section 2 Question 24](https://samiqamar.com/bmat-2004-section-2-question-24/): The diagram shows the leg muscles of an athlete leaving the starting blocks for a race. Which muscles contract and which relax to bring about the change from position 1 to position 2? Answer: 24) C This is no longer on the BMAT. In the picture, you can see that the person is straightening their leg. To straighten your leg, you need to contract your quadriceps (upper front thigh = R) and relax your hamstrings (upper back thigh = P). The glutes (Q) must also contract to provide maximum force to get a good start to the race. You can see […]
- [BMAT 2004 Section 2 Question 23](https://samiqamar.com/bmat-2004-section-2-question-23/): In water, the Fe^2+ ion bonds with water to form Fe(H2O)6^2+. In haemoglobin in the blood, five of the water molecules have been displaced. In the presence of air, the last water molecule is displaced by oxygen to give oxyhaemoglobin. In the presence of carbon monoxide, the oxygen is displaced to give carboxyhaemoglobin.Which of the following shows the correct order of the strength of the bonding to the Fe^2+ ion (weakest first)? Answer: 23) E The order is clearly given by the paragraph. The third sentence says that in the presence of air, the last water molecule is displaced by oxygen. […]
- [BMAT 2004 Section 2 Question 22](https://samiqamar.com/bmat-2004-section-2-question-22/): Nuclide P decays by emission of ionising radiation to produce nuclide Q. This new nuclide then decays by further emission into nuclide R. The process is shown below, with the appropriate mass numbers (nucleon numbers) and atomic numbers (proton numbers). Which line in the table shows the type of particle emitted at each stage, and the value of X Answer: 22) F In the first decay, the atomic number is increased by 1 but the mass number remains the same. This can only be beta decay. In beta decay, a fast moving electron is emitted, the mass number remains the same […]
- [BMAT 2004 Section 2 Question 21](https://samiqamar.com/bmat-2004-section-2-question-21/): Which blood vessel will have capillaries at both ends? Answer: 21) D The Hepatic portal vein is the only blood vessel which carries nutrient rich blood from one organ to another (gut to liver). So it has capillaries at both ends. Other vessels do not do the same. You probably could have figured this out by the process of elimination. (No problem if you couldn’t. Now you know!)
- [BMAT 2004 Section 2 Question 20](https://samiqamar.com/bmat-2004-section-2-question-20/): Which one of the following is not a measure of electrical power? (V = potential difference, I = current, Q = charge, t = time, R = resistance) Answer: 20) C A is a measure of electrical power.P = VII = Q / tSubstituting (I = Q / t) in the equation P = VI,P = (Q / t) x V = QV / t B is a measure of electrical power. P = IVV = IRSubstituting (V = IR) in the equation P = VI,P = I x IR = I²R C is not a measure of electrical power. There is no […]
- [BMAT 2004 Section 2 Question 19](https://samiqamar.com/bmat-2004-section-2-question-19/): The diagram shows three sperm and three ova containing sex chromosomes X and Y (notdrawn to scale). Indicate the letters (A to F) of all the sex cells which are normal. Answer: 19) A, D & E An egg always has only the X chromosome. So A is correct but B and C are wrong. A sperm could either have X or Y chromosome (but not both). So D and E are correct but F is wrong.
- [BMAT 2004 Section 2 Question 18](https://samiqamar.com/bmat-2004-section-2-question-18/): The general formula for the alkane series of hydrocarbons is CnH2n+2 The primary amine series has the same saturated structure as the alkanes, but also contains an –NH2 group. What is the general formula for the primary amine series? Answer: 18) D Let us take an alkane: Butane. Butane is C₄H₁₀ The -NH₂ group will be joined by taking out an hydrogen atom from the butane. So the formula would be C₄H₁₁N. This amine has one extra hydrogen atom and one nitrogen atom compared to the original butane. So the general formula would be CnH2n+3n
- [BMAT 2004 Section 2 Question 17](https://samiqamar.com/bmat-2004-section-2-question-17/): A parachutist of total mass 90kg (including the parachute) is falling at a terminal velocity of 6m/s. Take the force due to gravity on a mass of 1kg to be 10N. What is the magnitude of the air resistance force acting on her? Answer: 17) D Since the parachutist has reach terminal velocity, the resultant force (i.e. sum of forces acting on the parachutist) will be zero. The forces acting on the parachutist would be the weight and air resistance. Weight = 90 x 10 = 900 N Since resultant force is zero, weight = air resistance So air resistance = […]
- [BMAT 2004 Section 2 Question 16](https://samiqamar.com/bmat-2004-section-2-question-16/): In 2001 a quarter of the population of Wales reported having a limiting long-term illness or disability which restricted their daily activities. What is the probability that out of a random group of three people who live in Wales, exactly one of them will have reported such an illness or disability? Answer: 16) B Tree diagrams are really helpful in solving such probability questions. Let Y represent a person having the illness and let N represent a person not having the illness.There can be three possibilities of exactly one person having such an illness. YNN, NYN, NNY 25% of the people […]
- [BMAT 2004 Section 2 Question 15](https://samiqamar.com/bmat-2004-section-2-question-15/): In these circuits the cells are identical and their internal resistances can be ignored. Indicate whether each of the statements below is true or false for the circuits shown Answer: 15) i) False, ii) False, iii) True, iv) False, v) False i) FalseSince the circuit is in parallel, the voltage in the voltmeter and the bulb will remain the same. ii) FalseThe voltmeter and the bulb will have the same voltage. Due to Ohm’s Law, current will also remain the same. iii) TrueClosing S2 will open a new pathway for current to flow in the bulb in the lowest branch. This […]
- [BMAT 2004 Section 2 Question 14](https://samiqamar.com/bmat-2004-section-2-question-14/): Plugs of cotton wool containing concentrated aqueous ammonia and concentrated hydrochloric acid are placed at opposite ends of a tube, at room temperature. A white ring of solid ammonium chloride forms nearer the hydrochloric acid.Which of the following can be deduced from this experiment? Answer: 14) D Lighter molecules diffuse faster than heavier molecules. Since the mass of an ammonium molecule is less than that of a hydrogen chloride molecule, it will diffuse across the tube more than the hydrogen chloride molecule. Hence, the white ring is formed near the concentrated hydrochloric acid.
- [BMAT 2004 Section 2 Question 13](https://samiqamar.com/bmat-2004-section-2-question-13/): Solve the inequalityx^2 ≥ 8 – 2x Answer: 13) D We need to use the inequalities given in the options to solve this question. x² ≥ 8 – 2x Rearranging,x² + 2x – 8 ≥ 0 Factorising (x + 2x – 8),x² – 2x + 4x – 8x(x – 2) + 4(x – 2)So we have, (x – 2) (x + 4) ≥ 0Writing them down individually, x – 2 ≥ 0x + 4 ≤ 0 Rearranging,x ≥ 2x ≤ -4 So the answer is D.
- [BMAT 2004 Section 2 Question 12](https://samiqamar.com/bmat-2004-section-2-question-12/): The diagram shows a family tree. The grandfather, individual 1, carries a recessive allele on his X chromosome. Which other individuals could have inherited this allele? Answer: 12) D Individual 1 has a recessive X allele. Since individual 1 is a male, he must have X and Y chromosomes. Only his daughters can receive his recessive X chromosome. So 4 and 5 will receive it by 6 will not. Since 5 does not have any offsprings, she cannot pass on the X chromosome.4 will pass on her X chromosome to her offsprings. So 8 and 9 will obtain the X chromosome. […]
- [BMAT 2004 Section 2 Question 11](https://samiqamar.com/bmat-2004-section-2-question-11/): One of the steps in the breakdown of glucose is the conversion of pyruvic acid, CH3COCO2H, into lactic acid, CH3CH(OH)CO2H. This is an example of. Answer: 11) B Counting the number of atoms of each element of both pyruvic acid into lactic acid, we can see that lactic acid has 2 more Hydrogen atoms than pyruvic acid. The addition of hydrogen atoms to a molecule is called reduction.
- [BMAT 2004 Section 2 Question 10](https://samiqamar.com/bmat-2004-section-2-question-10/): The diagram shows two sets of parallel lines. Angles θ, α, β and γ are as marked. Which of the following statements are true? (shade all that apply). Answer: 10) A & B This is no longer on the BMAT specification.
- [BMAT 2004 Section 2 Question 9](https://samiqamar.com/bmat-2004-section-2-question-9/): A ball is thrown vertically upwards and leaves the thrower’s hand with a speed of 12m/s.Calculate the height to which it rises. You may assume that all of the initial kinetic energyof the ball has been converted into gravitational potential energy when the ball reaches itshighest point. (Take the value of g to be 10N/kg.) Answer: 9) 7.2 m Kinetic energy = 0.5mv²Potential energy = mgh Since Kinetic energy = Potential energy, 0.5mv² = mgh0.5 x 144 = 10 x hh = 72 ÷ 10 = 7.2 m OR We can just use a SUVAT equation v² – u² = 2as […]
- [BMAT 2004 Section 2 Question 8](https://samiqamar.com/bmat-2004-section-2-question-8/): An oxide of tungsten contains 79.31% by mass of tungsten.What is the formula of this oxide? (relative atomic masses: O = 16; W = 184) Answer: 8) E Round up the percentage mass of tungsten = 80%So percentage mass of oxygen = 20% We know Moles = Mass / Mr Moles of W = (80 ÷ 184) = 0.44Moles of O = (20 ÷ 16) = 1.25 Ratio = 0.44 : 1.25This gives us an approximate ratio of 1 : 3 So the answer is WO
- [BMAT 2004 Section 2 Question 7](https://samiqamar.com/bmat-2004-section-2-question-7/): The table shows some properties of five substances A – E. From the substances in the table, select the substances that could be: Answer: 7) E, B, A and C i) EA giant molecular structure would have a very high melting and boiling point. Also, it would not conduct electricity. ii) BA metal would have a moderate melting and high boiling temperature and would conduct electricity when solid or molten. iii) AAn ionic compound would only conduct electricity when molten. iv) CRoom temperature = 25º C.The only substance that would be a liquid at room temperature would be the one which […]
- [BMAT 2004 Section 2 Question 6](https://samiqamar.com/bmat-2004-section-2-question-6/): The diagram shows a section through the thorax. When breathing out (expiring), what happens to the muscles at X and Y and the pressure at Z? Answer: 6) E The easiest one to figure out is Y. During expiration, the diaphragm relaxes and curves upwards. The pressure Z increases to force the air to move out of the thoracic cavity. The intercostal muscles also relax to allow expiration.
- [BMAT 2004 Section 2 Question 5](https://samiqamar.com/bmat-2004-section-2-question-5/): During the electrolysis of hydrochloric acid, positively charged hydrogen ions move towardsthe cathode at a rate of 1018 ions per second. Negatively charged chloride ions movetowards the anode at the same rate. Both hydrogen and chloride ions carry charges ofmagnitude 1.6 × 10-19C.What is the resulting current flow between the electrodes? Answer: 5) 0.32 A Total number of ions per second = 10¹⁸ ions Total charge = 2 x 1.6 x 10⁻¹⁹ C Current = (2 x 1.6 x 10⁻¹⁹) x (10¹⁸) (2 x 1.6 x 10⁻¹⁹) x (10¹⁸) (3.2 x 10⁻¹⁹) x (10¹⁸) (3.2 x 10⁻¹⁹⁺¹⁸) (3.2 x 10⁻¹) 0.32 […]
- [BMAT 2004 Section 2 Question 4](https://samiqamar.com/bmat-2004-section-2-question-4/): The diagram shows a simplified version of the brake pedal of a car. A driver applies a force of 60N to the pedal. What force is applied to the piston? Answer: 4) E This requires the knowledge of moments. The perpendicular distance from the midpoint of pivot to the midpoint of the pedal = 16 + 4 = 20 cmForce applied to the pedal = 60 NMoments = F x d = 60 x 20 = 1200 N cm The perpendicular distance from the midpoint of pivot to the midpoint of the piston= 4 = 4 cmLet Force applied to the […]
- [BMAT 2004 Section 2 Question 3](https://samiqamar.com/bmat-2004-section-2-question-3/): The equation summarises the reaction of copper and dilute nitric acid.qCu + rHNO3 → sCu(NO3)2 + 6H2O + tNO2What values of q, r, s and t are needed to balance the equation? Answer: 3) q = 3, r = 12, s = 3, t = 6 There are a total of 12 Hydrogen atoms on the RHS and that is unchangeable. Hydrogen is only present in HNO₃ on the LHS.  Therefore, to balance the Hydrogen atoms on both sides, r = 12. Copper is present on its own on LHS and in Cu(NO₃)₂ on RHS. So q = s Let us form algebraic […]
- [BMAT 2004 Section 2 Question 2](https://samiqamar.com/bmat-2004-section-2-question-2/): The right-angled triangle shown has horizontal and vertical sides measuring (4 + √2) cm and(2 – √2) cm respectively. Calculate the area of the triangle. Answer: 2) B Area of a right angled triangle = 1/2 x base x height 0.5 x (4 + √2) x (2 – √2) 0.5 x [4 (2 – √2) + √2 (2 – √2)] 0.5 x [(8 – 4√2) + (2√2 – 2)] 0.5 x [8 – 4√2 + 2√2 – 2] 0.5 x [6 – 2√2] (3 – √2) is the answer
- [BMAT 2004 Section 2 Question 1](https://samiqamar.com/bmat-2004-section-2-question-1/): The diagram shows a view from the front of a section through the heart and associated bloodvessels. Which sequence of numbers shows the course of blood flow from the point of entry to theheart from the lungs, to its eventual exit from the heart to supply the lungs? Answer: 1) B From the lungs, the blood will flow into the heart via the pulmonary vein (2)From the pulmonary vein, the blood will enter the left atrium (3)From the left atrium, the blood will enter the left ventricle (4)From the left ventricle, the blood will flow to the rest of the body […]
- [BMAT 2003 Section 2 Question 29](https://samiqamar.com/bmat-2003-section-2-question-29/): In triangle PQR<QPR = 60 <PQR = 45< QRP = 75RQ = 6 units Given that cos 60 is ½, find the length of side PR. (The diagram is not drawn to scale.) Answer: 29) This is no longer on the BMAT specification as this includes the use of sine rule.
- [BMAT 2003 Section 2 Question 28](https://samiqamar.com/bmat-2003-section-2-question-28/): The enamel on teeth treated with fluorine may include fluoroapatite, which contains Ca^2+,PO4^3- and F^- ions. Which one of the following is a possible formula for fluoroapati Answer: 28) C This is actually a pretty simple question. All of the compounds are electrically neutral i.e. they have no charge. We have been given the charges of the individual ions. We just need to calculate which of the options would give us an answer of 0. A(2) + (-3) + (-1) = -2 B(6) + (-6) + (-1) = -1 C(10) + (-9) + (-1) = 0 D(14) + (-15) + (-1) […]
- [BMAT 2003 Section 2 Question 27](https://samiqamar.com/bmat-2003-section-2-question-27/): A parachutist falls from an aircraft and reaches a terminal velocity. After a while he openshis parachute and reaches a new (lower) terminal velocity. Which graph shows how the air resistance (drag) force acting on him varies with time during the fall? Answer: 27) A As soon as the parachutist falls from the aircraft, air resistance (drag force) immediately acts against him and starts to increase. Soon after, the drag force will become equal to the weight of the parachutist. They will reach a terminal velocity. As soon as the parachutist open his parachute, the drag force increase greatly as air […]
- [BMAT 2003 Section 2 Question 26](https://samiqamar.com/bmat-2003-section-2-question-26/): The bar charts X and Y show the concentration of five substances in the blood before andafter passing through two organs. What are the organs X and Y through which the blood has passed? Answer: 26) C Y is relatively easy to figure out. The oxygen concentration greatly increases after blood passes through it. This is obviously the lungs. You can rule out options B, D, E, F. Now, in organ X, carbon dioxide level increases, salt level decreases, glucose level decreases and oxygen level decreases. The only thing that stands out is the urea level. Urea level in blood only […]
- [BMAT 2003 Section 2 Question 25](https://samiqamar.com/bmat-2003-section-2-question-25/): Simplify{[2x^3/2 y^3]/√Z}^2 Answer: 25) B Let us solve this question in portions. (2x^³⁄₂)² = 4x³ (y³)² = y⁶ (√z)² = z So the simplification would be: 4x³ y⁶   z
- [BMAT 2003 Section 2 Question 24](https://samiqamar.com/bmat-2003-section-2-question-24/): Which set of events occurs during exhalation? Answer: 24) C The process of exhalation or expiration is as follows: If you face any confusion, try exhaling yourself and feel the movement of your ribs. Also, you will also notice that when you are about to exhale, the pressure inside your lungs increases. Since pressure is inversely proportional to volume, volume would decrease.
- [BMAT 2003 Section 2 Question 23](https://samiqamar.com/bmat-2003-section-2-question-23/): The reactivity of the alkali metals (group 1) increases as the atomic number increases.Which one of these statements is the correct explanation of this fact? Answer: 23) E As we go down group 1, the number of shells increases by 1. Since the number of shells increases, the atomic radius also increase. The attraction between the nucleus and the outer electron decreases. Therefore, it becomes easier to lose the outer electron as you go down group 1. Hence, the alkali metals become more reactive. The other options are correct statements but they do not explain why the reactivity increases.
- [BMAT 2003 Section 2 Question 22](https://samiqamar.com/bmat-2003-section-2-question-22/): In an a.c. generator driving a resistive load a coil is rotated slowly between the poles of amagnet. Which of the following will increase if the coil is rotated more quickly? 1 the frequency of the a.c.2 the amplitude of the a.c.3 the output e.m.f. of the generator Answer: 22) E If the coil is rotated more quickly, frequency and amplitude will increase. Together with this, the total output e.m.f. will also increase.
- [BMAT 2011 Section 2 Question 22](https://samiqamar.com/bmat-2011-section-2-question-22/): An ore of lead contains 70% of PbS. Calculate the mass of lead that can be extracted from 478kg of the ore.[Ar : Pb = 207; S = 32] Answer: 22) D Mass of PbS in 478kg of ore = 70% of 478 = 0.7 x 478 = 334.6kg ≈ 335 kgMr of PbS = 207 + 32 = 239n = 335/239 ≈ 336/240 = 1.4 moles Moles of Pb = 1.4 molesn = m/Mrm = n x Mrm = 1.4 x 207 = 289.8 Hence D is the answer. 
- [BMAT 2011 Section 2 Question 21](https://samiqamar.com/bmat-2011-section-2-question-21/): Using the table, select the correct answer from the table.Cell Quantity of nuclear DNAP 1Q 2R 0 Answer: 21) D All body cells such as red blood cells and skin cells have double the amount of DNA as gametes. Zygotes also have double the DNA as gametes. The easiest one to spot is from the ‘0’ column. Only an enucleated egg cell has ‘0’ DNA. Since egg cell is a gamete, it will have ‘1’ DNA. Since nerve cell is a body cell, it will have ‘2’ DNA.  So, D is the answer. 
- [BMAT 2011 Section 2 Question 20](https://samiqamar.com/bmat-2011-section-2-question-20/): The diagram shows three similar right-angled triangles. What is the area of the largest triangle? Answer: 20) B Let hypotenuse of smaller triangle = HLet hypotenuse of larger triangle = ALet hypotenuse of largest triangle = B Using Pythagoras theorem, H² = 1² + 3²H² = 1 + 9 = 10H = √10 Since the triangles are similar,   3      =     √10 √10             A A = (¹⁰⁄₃) Since larger triangle and largest triangle are similar,  Small edge of the largest triangle = ⅓ x (¹⁰⁄₆) = (¹⁰⁄₉) Area of a right angled triangle = ½ x base x height = ½ x (¹⁰⁄₉) x (¹⁰⁄₃) […]
- [BMAT 2011 Section 2 Question 19](https://samiqamar.com/bmat-2011-section-2-question-19/): Which graph correctly shows how the resistance (R) varies with applied voltage (V) for a resistor at constant temperature? Answer: 19) A V (voltage) is directly proportional to I (current). If voltage increases, then current also increases since there is a constant temperature.  We know the equation: V = IRVoltage increases and Current increases. Since they both increase proportionally, resistance would have to remain the same. 
- [BMAT 2011 Section 2 Question 18](https://samiqamar.com/__trashed/): Nitrogen Monoxide is prepared by reacting copper with nitric acid. What should the values of a, b, x and y be in order to balance the following equation?aCu + bHNO3 → xCu (NO3) 2 + yH2 O + 2NO Answer: 18) E Set up algebraic equations for any of the elements present. e.g. Cu on the left side appears ‘a’ times. Cu appears ‘x’ number of times on the right side.  a = xHowever, all of the options has a = x. (Option A has a = 2, x = 2) Let us try Nb = 2x + 2Try substituting the values of ‘b’ and ‘x’ […]
- [BMAT 2011 Section 2 Question 17](https://samiqamar.com/bmat-2011-section-2-question-17/): The genetic condition represented by the shading is caused by the presence of at least one allele for the condition.Which of the following are possible reasons why U has the condition?1 The condition is dominant.2 The sperm from T carried the allele for the condition.3 A mutation present in a egg of S. Answer: 17) D 1 – We know that statement 2 could definitely be a reason. If the sperm carried the allele and one allele is enough to cause the condition, then 2 could be reason. We can eliminate B and E.  2 – If the condition is dominant, then P, Q, R […]
- [BMAT 2011 Section 2 Question 16](https://samiqamar.com/bmat-2011-section-2-question-16/): The graphs of the following equations are drawn:1 y = 3x – 22 y = x23 y = 1 – x24 y = x + 6Which pair of graphs do not intersect? Answer: 16) E Let x = 1. Equation 1:y = 3x – 2y = 3(1) – 2y = 1 Equation 2:y = x²y = 1²y = 1 (eq 1 and 2 will intersect)  Equation 3:y = 1 – x²y = 1 – 1y = 0 (this is pretty close to 1 and 2)  Equation 4:y = x + 6y = 1 + 6.y = 7 (very far away from all […]
- [BMAT 2011 Section 2 Question 15](https://samiqamar.com/bmat-2011-section-2-question-15/): A bullet of mass 50g is fired from a rifle with a velocity of 300m/s. It hits a bank of earth and after travelling 60cm into the bank comes to rest. What is the average stopping force of the earth in the bank on the bullet? Answer: 15) B Equation for Force is: Force = mass x accelerationWe know the mass is 50g which is equal to 0.05kg To find the acceleration we need to use the XUVAT or SUVAT equations: We have the following information: v = 300m/s, u = 0 m/s,s = 60cm = 0.6m, t = not known (cannot use eq 2, […]
- [BMAT 2011 Section 2 Question 14](https://samiqamar.com/bmat-2011-section-2-question-14/): Which of the following (A-E) correctly identifies all of the compounds from the list below that contain covalent bonds in their structure?CO2 (g) Ca(OH)2 (s) H 2SO4 (l) MgCO3 (s) NaCl (s) Na 2O (s) Na 3PO4 (s) SO2 (g) SiO2 (g) Answer: 14) C We know that when a metal bonds with a non-metal, an ionic bond is formed. This means that NaCl and Na₂O do not form covalent bonds whilst all other form covalent bonds. So C is correct. 
- [BMAT 2011 Section 2 Question 13](https://samiqamar.com/bmat-2011-section-2-question-13/): The table below shows information relating to gas exchange in an active muscle when blood first enters that muscle.Which row of the table is correct? Answer: 13) E Read the question carefully! It says “when blood first enters that muscle”When blood first enters the muscle, it’s oxygen concentration would be higher than the muscle and the carbon dioxide concentration would be lower than in muscle to allow diffusion of both gases.The first column should have low and the second column should have high. We can rule out A,B and C. We know that the process involved is diffusion. Hence, we can rule out […]
- [BMAT 2011 Section 2 Question 12](https://samiqamar.com/bmat-2011-section-2-question-12/): w, x, y and z are integers such that w < x2, x > y2, y2 < z2 and x > z . Which one of the following inequalities must be true? Answer: 12) D The easiest way to solve this is to assign values to the integers given in options A, B, C, D and E. However, the inequalities in the question should still be true) A – This cannot be 100% proven as true.Let us say x = 10 and w = 20, this cannot be true.However, w(20) < x² (10² = 100) is true. B – This cannot […]
- [BMAT 2011 Section 2 Question 11](https://samiqamar.com/bmat-2011-section-2-question-11/): Consider this circuit. Which line in the table gives the current flowing in the ammeter, in amps, when the switch isopen, and when it is closed? Answer: 11) B The current flows from positive to negative, meaning it flows from the bigger line on the battery to the smaller line on the other side of the battery. It flows clockwise. The diode breaks the circuit. If the switch on the branch is open, then it means that no current is flowing to the circuit. So the ammeter would show 0. If the switch is closed, it means that current flows through […]
- [BMAT 2011 Section 2 Question 10](https://samiqamar.com/bmat-2011-section-2-question-10/): Cyclohexene, C6H10, can be represented as:Use this information to calculate the relative molecular mass of the hydrocarbon shown below:[Ar values: H = 1; C = 12] Answer: 10) D In the hydrocarbon shown, there are 10 carbon atoms and 18 hydrogen atoms. We cannot double count the corners in the middle (since there is an overlap). (12 x 10) + (18 x 1) = 138
- [BMAT 2011 Section 2 Question 9](https://samiqamar.com/bmat-2011-section-2-question-9/): Here are five statements about natural selection:1 Individuals within a species show variation.2 Individuals within a species compete with each other for, among other things, resources.3 Individuals with advantageous adaptations are more likely to survive to adulthood.4 Only individuals with advantageous adaptations will be able to breed.5 Alleles for advantageous adaptations are more likely to be inherited.Which of the above statements are correct? Answer: 9) C 1 – All individuals within a species show variation. e.g. All humans have some sort of variation in our genes such, as different eye colour or faces. So 1 is correct. 2 – Competition between […]
- [BMAT 2011 Section 2 Question 8](https://samiqamar.com/bmat-2011-section-2-question-8/): If you look at a clock and the time is 9.45, what is the angle between the hour and the minute hands? Answer: 8) D Number of degrees in a clock (circle) = 360˚Number of divisions in a clock = 12Angle between each division = 360/12 = 30˚ This clock shows 9:45. The hour hand is 3/4 of the way between 9 and 10, whilst the minute hand is on 9. We know angle between each division = 30˚So angle between 9 and 10 = 30˚ Angle between hour hand and minute hand = 3/4 x 30˚ = 22.5˚
- [BMAT 2011 Section 2 Question 7](https://samiqamar.com/bmat-2011-section-2-question-7/): Which one of the following statements about nuclear physics is true? Answer: 7) E A – WrongThe definition of nuclear fission is splitting of a nucleus into two smaller nuclei. The definition given in this statement is wrong. B – WrongThe definition of half life is wrong. Half life is the time taken for the half of the substance to decay. C – WrongNumber of neutrons = Mass number – Atomic number. (Not Atomic number – Mass number) D – WrongFission is used in nuclear power stations. E – CorrectWhen a nucleus emits a ß-particle, the number of particles in the […]
- [BMAT 2011 Section 2 Question 6](https://samiqamar.com/bmat-2011-section-2-question-6/): When molecules collide, for a reaction to take place, two conditions must be met. Firstly, theymust have sufficient energy to react and secondly, they must have the right orientation. Thismeans that the ends of the molecules that are going to react must be in contact with each other.Raising the temperature speeds up a chemical reaction.Which of the following could be responsible for this?1 More collisions take place.2 The average collision has more energy.3 The orientation of the molecules is more favourable. Answer: 6) D 1 – When temperature increases, molecules gain more kinetic energy, therefore they move around a lot. This […]
- [BMAT 2011 Section 2 Question 5](https://samiqamar.com/bmat-2011-section-2-question-5/): The following statements relate to typical nuclear division in human cells:1 mitosis results in variation within the species2 meiosis results in the production of genetically identical cells3 mitosis results in the production of diploid cells4 meiosis results in the production of haploid cells5 mitosis results in the production of two daughter cellsWhich statements are correct? Answer: 5) F 1 – Mitosis produces genetically identical cells. So it cannot introduce variation. This is wrong. 2 – Meiosis introduces variation in species. It cannot produce genetically identical cells. This is wrong. 3 – In mitosis, the 2 daughter cells produced are diploid. So […]
- [BMAT 2011 Section 2 Question 4](https://samiqamar.com/bmat-2011-section-2-question-4/): Simplify:3x(3x⁻⅓)³ Answer: 4) C 3x(3x⁻⅓)³ 3x(3³ x⁻³⁄₃) 3x(27x⁻¹) 3x (27/x) 3 x 27 = 81
- [BMAT 2011 Section 2 Question 3](https://samiqamar.com/bmat-2011-section-2-question-3/): Two identical cars, P and Q, start at the same level. Car P moves at a constant speed of 10m/s up a hill to a height of 25m in a time of 20s. In the same time car Q moves at a constant speed of 20m/s up a hill to a height of 50m. What are the kinetic energies of the cars while they are travelling up the hills, and what are their gravitational potential energies once they have reached the top? Answer: 3) C Formula for kinetic energy = ½mv²Let mass of P and Q be ‘m’KE of P = […]
- [BMAT 2011 Section 2 Question 2](https://samiqamar.com/bmat-2011-section-2-question-2/): A metal, X, is in group III of the periodic table. A non-metal, Y, is in group VI of the periodic table. They react together to form a compound. What is the formula of the compound? Answer: 2) B This question deals with valencies. X, being in group 3, has a valency of +3. It has 3 electrons in its outer shell. It needs to donate its 3 electrons to be stable. Y is in group 6, meaning it needs 2 electrons to be stable. Its valency is -2. To find the formula we can use the following technique: X   […]
- [BMAT 2011 Section 2 Question 1](https://samiqamar.com/bmat-2011-section-2-question-1/): Which word or statement does not correctly fit into one of the gaps left in the table? Answer: 1) F A – insulin can fit in the pancreas row. B – Adrenaline increases heartbeat rate, so this option can fit in the first row C – Pituitary gland is the gland which secretes ADH, so it fits. D – Testes secrete testosterone so it fits in the fourth row E – Ovary secretes oestrogen so it fits in the second row F – Carbohydrase is an enzyme. It is neither a gland, hormone nor a function. So it does not fit […]
- [BMAT 2008 Section 2 Question 27](https://samiqamar.com/bmat-2008-section-2-question-27/): Taking the speed of sound in air as 300 m/s and in steel as 4800 m/s. A worker lies next to a railway line and hears the whistle of a train through the steel rails and 1.5 s later hears the same whistle through the air. How far away was the train when its whistle sounded Answer: 27) C Time taken by sound to travel in steel = tLet time taken by sound to travel in air = t + 1.5 The distance travelled by the sound in steel would be the same as distance travelled by sound in air Distance […]
- [BMAT 2008 Section 2 Question 26](https://samiqamar.com/bmat-2008-section-2-question-26/): A sample of an alkali XOH of mass 2.8 g was dissolved in water. This solution was neutralised by 12.5 cm3 of sulphuric acid of concentration 2.0 mol dm-3.2 XOH (aq) + H2SO4 (aq) → X2SO4 (aq) + 2 H2O (l)What is the relative atomic mass of X?(Ar : H = 1, O = 16, S = 32) Answer: 26) C Volume of sulphuric acid = 12.5 = 0.0125 dm³Concentration of sulphuric acid = 2 mol/dm³Moles of sulphuric acid = concentration x volume = 0.0125 x 2 = 0.025 mol Molar ratio (XOH: H₂SO₄) = 2:1Moles of XOH = 0.025 x […]
- [BMAT 2008 Section 2 Question 25](https://samiqamar.com/bmat-2008-section-2-question-25/): Red-green colour blindness is a condition caused by a recessive allele. The gene is carried on the X chromosome. A man is red-green colour blind, which of his relatives must carry the recessive allele? Answer: 25) D The man has chromosomes X and Y. He must have received the Y chromosome from his father and the X chromosome from is mother.Since the condition is only carried on the X chromosome, his mother must carry the recessive allele. His daughter must have the chromosomes X and X. The daughter must have received one X chromosome from her father (the man in the […]
- [BMAT 2008 Section 2 Question 24](https://samiqamar.com/bmat-2008-section-2-question-24/): A quadratic equation has solutions a and b.a + b = -5 ab = 3What is the equation? Answer: 24) A (x = a) and (x = b)x – a = 0x – b = 0 We can write : (x – a) (x – b) = 0x² – xb – ax + ab = 0 We know (ab) = 3x² – xb – ax + 3 = 0x² – x(a + b) + 3 = 0 We know (a + b) = 5x² – x(5) + 3 = 0x² – 5x + 3 = 0 Hence A is correct.
- [BMAT 2008 Section 2 Question 23](https://samiqamar.com/bmat-2008-section-2-question-23/): A lorry of mass m, and travelling initially at speed v along a horizontal road, is brought to rest by an average braking force F in time t. Ignoring any other resistive forces, what distance is travelled by the lorry during this time? Answer: 23) C We first need to find the work done by the braking force. The work done would be equal to the energy of the lorry. Since the lorry was moving, its energy would be kinetic energy. So work done by braking force = KE of lorryWork = ½(mv²)We know that work done = force x distanceForce […]
- [BMAT 2008 Section 2 Question 22](https://samiqamar.com/bmat-2008-section-2-question-22/): In addition to diamond and graphite, another allotrope of carbon is Buckminster fullerene, C 60, which is in the shape of a sphere. Which one of the following statements applies to all three allotropes? Answer: 22) D A – WrongDiamond does not have any intermolecular forces. It only has intramolecular forces which are strong covalent bonds between carbon atoms. B – WrongIn graphite, each carbon atom is only bonded to 3 other carbon atoms. C – WrongDiamond is the hardest material on the planet whilst graphite is really soft. D – CorrectAll of these allotropes have only carbon atoms. They do […]
- [BMAT 2008 Section 2 Question 21](https://samiqamar.com/bmat-2008-section-2-question-21/): The four statements are about the movement of blood during one complete circuit of the body.1 Blood flowing from the lungs flows through the heart twice.2 All the blood flowing from the lungs flows through the kidneys.3 All the blood flowing from the liver flows through the lungs.4 Only blood flowing from the digestive system flows through the liver.Which of the above statements are correct? Answer: 21) B 1 – CorrectBlood from lungs flows to the heart. The heart then pumps the blood to the rest of the body. From the body, blood then flows back to the heart followed by […]
- [BMAT 2008 Section 2 Question 20](https://samiqamar.com/bmat-2008-section-2-question-20/): The diagram below shows three identical resistors and a battery that supplies a constant 12 V. With the switch open, as shown, the current in resistor Y is 20 mA. When the switch is closed, what is the current in resistor X, and what is the potential difference (voltage) across resistor Z Answer: 20) F Since the switch is now closed, current is likely to flow through the wire with the switch rather than through resistor Y. Current always flows where there is least resistance.Current in Y = 0Hence voltage in Y = 0Now voltage is shared amongst two resistors (X […]
- [BMAT 2008 Section 2 Question 19](https://samiqamar.com/bmat-2008-section-2-question-19/): I stop while out walking and take the bearing of a windmill and note it as θ º. I then walk 5 km north and take the bearing again – it is now 2 θ. How far away, in km, was the windmill from the position where I took the first bearing? Answer: 19) C A bearing is an angle measured clockwise from the north direction.It is much easier to draw a diagram to show the situation. The original bearing is ‘ø’ and when the person walks 5 km towards the north, the bearing becomes 2ø. The angle inside the triangle […]
- [BMAT 2008 Section 2 Question 18](https://samiqamar.com/bmat-2008-section-2-question-18/): The general formula for the alkane series is CnH2n+2. The amide series has the same saturated structure as the alkanes but with one H substituted by the -CONH2 group. What is the general formula for the amide series? Answer: 18) F 1 Hydrogen atom is removed and replaced with -CONH₂ group.Formula with 1 less hydrogen atom = CnH2n+1When the -CONH₂ group is added, The number of carbon atoms increases by 1Number of Hydrogen atoms increases by 2Oxygen atom is addedNitrogen atom is added New formula would be: C(n+1)H(2n+1)+2ON = C(n+1)H(2n+3)ON Hence F is the answer.
- [BMAT 2008 Section 2 Question 17](https://samiqamar.com/bmat-2008-section-2-question-17/): The reflex arc enables the body to make rapid responses to certain stimuli. Which row in the table correctly identifies the elements 1 to 5 in the reflex arc shown above? Answer: 17) B In order to produce a reflex, a stimulus must be present.So 1 is the stimulus. Receptors sense the stimulus.So 2 must receptor. The receptors send electrical impulses to CNS via sensory neurones.3 must be CNS. CNS then relays these electrical impulses to the muscles via motor neurones.4 must be muscle. Muscle then contracts to produce a movement (response).5 must be response. Hence B is correct.
- [BMAT 2008 Section 2 Question 16](https://samiqamar.com/bmat-2008-section-2-question-16/): A right-angled triangle is shown. Calculate the area of the triangle. Answer: 16) A This is rather an easy question. Since the triangle is right-angled, we can use the formula: Area = 1/2 x base x height Area = 0.5 x (4 – √6) x (6 + √6) Area = 0.5 x [4 (6 + √6) – √6 (6 + √6)] Area = 0.5 x [24 + 4√6 – 6√6 + 6] Area = 0.5 x [18 – 2√6] Area = 9 – √6
- [BMAT 2008 Section 2 Question 15](https://samiqamar.com/bmat-2008-section-2-question-15/): A car is accelerated from rest along a horizontal road by a constant thrust force produced by the engine. The car eventually reaches a terminal speed, and the graphs below show the variation with time of three quantities (X, Y and Z) for the car: Which line in the table could correctly identify the quantities X, Y and Z? Answer: 15) F I think that graph Z is the easiest one to identify.There are two options given to us for Z: kinetic energy and weight.Kinetic energy depends on velocity. As velocity changes, kinetic energy changes.However, weight remains the same no matter […]
- [BMAT 2008 Section 2 Question 14](https://samiqamar.com/bmat-2008-section-2-question-14/): In the manufacture of hydrogen from methane and steam, carbon monoxide is produced as anunwanted side product. The amount of carbon monoxide is reduced by mixing the gases withsteam when the following reversible reaction takes place.CO (g) + H2 O (g) CO2 (g) + H2 (g) ∆H negative (exothermic)When this reaction reaches equilibrium, which of the following changes would result in morecarbon monoxide being removed? Answer: 14) D A – WrongThe addition of a catalyst never affects the equilibrium of a reaction. B – WrongNumber of moles of gas on left side = Number of moles of gas on right side. […]
- [BMAT 2008 Section 2 Question 13](https://samiqamar.com/bmat-2008-section-2-question-13/): In the diagram below, the triangles are congruent, PQ is a continuation of NL and both L and Pare equidistant from the line X = 0 and from the line Y = 0 Of the transformations (1 to 5) described below, which one of the combinations (A to E) will mapthe triangle LMN onto the triangle PQR?1 Reflection in the line y = 02 Rotation of 90º about the origin3 Reflection in the line y = x4 Reflection in the line x = 05 Rotation of 180º about the origin Answer: 13) D Try drawing out graphs on the question paper […]
- [BMAT 2008 Section 2 Question 12](https://samiqamar.com/bmat-2008-section-2-question-12/): During the breakdown of a solution containing carbohydrates, proteins and lipids bycarbohydrase, protease and lipase enzymes, the pH changed from neutral due to the productsformed. Which of the options, A to E, correctly shows which constituents contribute to the change in pH? Answer: 12) E We must first identify the products that will be formed due to the enzyme action. Carbohydrase will break down carbohydrates to form sugars such as glucoseProtease will break down proteins to form amino acidsLipase will break down lipids to form fatty acids and glycerol Sugars such as glucose will not cause a change in pH because […]
- [BMAT 2008 Section 2 Question 11](https://samiqamar.com/bmat-2008-section-2-question-11/): Here are four statements about radioactivity:1 A beta particle is an electron that is emitted from the outermost electron shell ofan atom.2 A beta particle is emitted from the nucleus of the atom when a proton changesinto an electron.3 A beta particle is emitted from the nucleus of the atom when a neutron changesinto an electron.4 After a beta particle is emitted the mass number of the nucleus of the atom isunchanged.Which statement(s) is/are true? Answer: 11) D Remember! A beta particle is a fast moving electron. A neutron turns into a proton and an electron. The proton stays in the […]
- [BMAT 2008 Section 2 Question 10](https://samiqamar.com/bmat-2008-section-2-question-10/): Which one of the following would not be formed by cracking the hydrocarbon C12H26? Answer: 10) C A – WrongThis is methane (a type of alkane). This can be produced. B – WrongThis is ethene (a type of alkene). This can be produced. C – CorrectThis is not a possible product or a molecule. 6 carbons cannot be attached to 16 hydrogens. The maximum number of hydrogens that can bond with 6 carbons is 14. D – WrongThis is octene (a type of alkene). This can be produced. E – WrongThis is dodecene (a type of alkene). This can be produced.
- [BMAT 2008 Section 2 Question 9](https://samiqamar.com/bmat-2008-section-2-question-9/): The graph shows oxygen supply and demand in muscle cells during exercise Which statement correctly describes what is happening in the muscle cells between 0 and 11 minutes? Answer: 9) D A – WrongOxygen demand is more than oxygen demand. Since there is a lack of oxygen, anaerobic respiration must be taking place. However, there is still some aerobic respiration taking place as oxygen is present. Therefore, this is wrong as both aerobic and anaerobic respiration is taking place and not only anaerobic. B – WrongThis is clearly wrong as the line for oxygen demand is higher than oxygen supply. C […]
- [BMAT 2008 Section 2 Question 8](https://samiqamar.com/bmat-2008-section-2-question-8/): The diagram shows a crane that lifts a load with a mass of 100 kg at a constant speed of 0.4 m/sfor 5 seconds. (g=10 N/kg) Here are 3 statements about this activity:1 The gain in gravitational potential energy of the load is 2000 J.2 The tension in the cable at point P is 2000 N.3 The load accelerates at 10 m/s2Which statements is/are true? Answer: 8) A Speed of lift = 0.4 m/sTime the load is lifted for = 5sDistance (height above ground) = 0.4 x 5 = 2 m Potential energy = m x g x h = 100 […]
- [BMAT 2008 Section 2 Question 7](https://samiqamar.com/bmat-2008-section-2-question-7/): The nth term of a sequence is n/n+1. What is the expression for the difference between the (n+1)th term and the nth term? Answer: 7) B nth term = n/(n+1) So, (n + 1)th term: n + 1n+1+1 n + 1n + 2 Difference between (n + 1)th term and nth term: n + 1 – nn +2 n + 1 n + 1 (n + 1) – n (n +2)(n + 2) (n + 1) n² + 2n + 1 – n² – 2n(n + 2) (n + 1) 1/(n+2) (n+1)
- [BMAT 2008 Section 2 Question 6](https://samiqamar.com/bmat-2008-section-2-question-6/): Look at the equation for making chlorine gas and decide which answer will provide you with the numbers to balance itaKMnO4 + bHCl Œ aKCl + aMnCl 2 + xH2O + yCl. Answer: 6) E Most efficient way: make equations. Equation for Cl b = a + 2a + 2y b = 3a + 2y Let us check which of the options can satisfy the equation above. A – Wrong 8 ≠ 3 + 6 B – Wrong 8 ≠ 3 + 8 C – Wrong 4 ≠ 3 + 2 D – Wrong 16 ≠ 6 + 12 E – […]
- [BMAT 2008 Section 2 Question 5](https://samiqamar.com/bmat-2008-section-2-question-5/): In mice the recessive form of a gene causes the death of the fetus if present in the homozygous state. Mice heterozygous for this gene were crossbred. What percentage of the live offspring would be homozygous dominant? Answer: 5) C Let the dominant allele be (T )and the recessive allele be (t) T                                  t T                      TT (33%)                   Tt (66%) t                       Tt (66%)                    tt (dead) There can only be two genotypes present in live offspring. The fetus with genotype (tt) will die.Possibility of homozygous dominant (i.e. TT) = 1/3 = 33%
- [BMAT 2008 Section 2 Question 4](https://samiqamar.com/bmat-2008-section-2-question-4/): In the formula P=2r2tr = 3 x 10-3 t = 2.5 x 10 4Calculate the value of P. Leave your answer in standard form. Answer: 4) D P = 2r²t P = 2 (3 x 10⁻³)² (2.5 x 10⁴) P = 2 (9 x 10⁻⁶) (2.5 x 10⁴) P = 5 x 10⁴ x 9 x 10⁻⁶ P = 45 x 10⁻² P = 4.5 x 10⁻¹
- [BMAT 2008 Section 2 Question 3](https://samiqamar.com/bmat-2008-section-2-question-1-2/): A radioactive isotope X decays into the stable isotope Y with a half-life of 20 s. Which graph correctly shows how the mass (m) of Y present in an initially pure sample of X varies with time (t)? Answer: 3) B X decays into Y. Therefore, as time progresses, the mass of X will decrease and mass of Y will increase. Half-life of X is 20s. After every 20s, mass of X will halve whilst mass of Y will double. The question is asking us to identify how the mass of Y varies with time. Graphs A, C and E show that as […]
- [BMAT 2008 Section 2 Question 2](https://samiqamar.com/bmat-2008-section-2-question-2/): Element Y forms an ion Y 3- with the electronic configuration 2, 8, 8.To which group and period of the periodic table does Y belong? Answer: 2) C The (-3) charge on Y suggests that an atom of Y requires 3 electrons to fill its outer shell. The ion Y³⁻ has an electronic configuration of 2, 8, 8. Since Y has gained 3 electrons to form Y³⁻, Y must have an electronic configuration of 2, 8, 5 (8 – 3 = 5) The number of outermost electrons (in this case there are 5) determines which group the element belongs to. Y belongs […]
- [BMAT 2008 Section 2 Question 1](https://samiqamar.com/bmat-2008-section-2-question-1/): Which one of the following involves active transport? A movement of carbon dioxide into alveoli in the lungsB uptake of alcohol (ethanol) through the lining of the stomachC secretion of sweat onto the skin’s surfaceD re-absorption of glucose in the kidney tubulesE loss of urine from the urethraF transfer of oxygen into the blood from the alveoli Answer: 1) D Active transport is the movement of molecules from an area of lower concentration to an area of higher concentration. This requires energy.  A – WrongCO2 moves into the alveoli via diffusion. Carbon dioxide moves from an area of higher concentration (in […]
- [BMAT 2010 Section 2 Question 27](https://samiqamar.com/bmat-2010-section-2-question-27/): A car of mass 800kg moves up an incline of 1 in 20 (1 in 20 means for every 20m along the road the car gains 1m in height) at a constant speed of 20m/s. The frictional force opposing motion is 500N. How much work has been done by the engine after the car has moved 50m? Answer: 27) D Height of car after 50m = 50/20 = 2.5 PE = mghPE = 800 x 10 x 2.5PE = 8000 x 2.5 = 20,000J Force of engine against friction = 500NWork done against friction = Force x distance = 500 x […]
- [BMAT 2010 Section 2 Question 26](https://samiqamar.com/bmat-2010-section-2-question-26/): Cyclohexene, C6H10, is drawn as: Apply this information for the steroid-type structure shown below to find the total number of carbon atoms in the molecule. Answer: 26) B The first ring has 6.The second has 4 extra. (Total 6 but 2 are from the first ring).The third has 4 extra. (Total 6 but 2 are from the second ring).The fourth has 3 extra. (Total 5 but 2 are from the third ring). Total so far = 6 + 4 + 4 + 3 = 17 2 carbons are present in the CH₃ groups and 1 is present in CO₂H group. Total = 17 + […]
- [BMAT 2010 Section 2 Question 25](https://samiqamar.com/bmat-2010-section-2-question-25/): The hormonal and nervous systems are often compared because of their similar roles in thebody. Which of the following statements about the two systems are true? 1 The nervous system relies only on electrical impulses to work.2 Both the hormonal and nervous systems activate target structures.3 The fastest responses in the body are produced by the nervous system.4 Only the hormonal system relies on the activity of chemicals.5 Parts of the hormonal system may be controlled by the central nervous system. Answer: 25) E 1 – WrongThe nervous system does not only rely on electrical impulses to work. It also relies […]
- [BMAT 2010 Section 2 Question 24](https://samiqamar.com/bmat-2010-section-2-question-24/): A design is set up by joining the points which are one third of the way along the sides of a square. This forms a second square as shown. This process is repeated. Calculate the area of the fourth square as a fraction of the original square. Answer: 24) C Let side of first square = A = 1Let side of second square = BLet side of third square = CLet side of fourth square = D Using Pythagoras theorem, Second SquareB² = (¹⁄₃)² + (²⁄₃)² = ¹⁄₉ + ⁴⁄₉ = ⁵⁄₉B = √⁵⁄₉ = √53 Third squareC² = (¹⁄₃ x […]
- [BMAT 2010 Section 2 Question 23](https://samiqamar.com/bmat-2010-section-2-question-23/): In an ornamental fountain, water is squirted vertically upwards through a nozzle by a pump. 5kg of water pass through the nozzle each second, and the water reaches a height of 5m after leaving the nozzle. What is the power of the pump (assuming 100% efficiency), and at what speed does the water leave the nozzle? (Take g to be 10N/kg) Answer: 23) G It is important to remember that power = energy per second.Potential energy (PE) of water when it reaches a height of 5m = m x g x hPE = 5 x 10 x 5 = 250J This […]
- [BMAT 2010 Section 2 Question 22](https://samiqamar.com/bmat-2010-section-2-question-22/): A student prepared nitrobenzene by the following reaction.C6H6 + HNO3 → C6H5NO2 + H2Obenzene nitrobenzeneStarting with 3.9g of benzene, the student obtained 3.69g of nitrobenzene.What is the percentage yield?(Ar : H = 1; C = 12; N = 14; O = 16) Answer: 22) C Mr of benzene = (12 x 6) + (1 x 6) = 78Mass of benzene given = 3.9 gMoles of benzene = mass/Mr = 3.9/78 = 1/20 moles = 0.05 mol Molar ratio of benzene and nitrobenzene = 1:1Moles of nitrobenzene = 0.05 molesMr of nitrobenzene = (12 x 6) + (1 x 5) + (14 […]
- [BMAT 2010 Section 2 Question 21](https://samiqamar.com/bmat-2010-section-2-question-21/): The following statements are about nuclear division by meiosis and mitosis.1 In animals meiosis only occurs in the reproductive organs.2 Mitosis can result in the formation of clones.3 Meiosis results in two nuclei.4 Mitosis results in four nuclei.5 Meiosis does not occur during asexual reproduction.Which of these statements are true? Answer: 21) B 1 – CorrectGametes are the only cells in animals produced by meiosis. 2 – CorrectMitosis is basically replication of cells. 3 – WrongMeiosis results in 4 haploid nuclei. 4 – WrongMitosis result in 2 identical diploid nuclei. 5 – CorrectMitosis occurs during asexual reproduction. An identical individual(clone) is […]
- [BMAT 2010 Section 2 Question 20](https://samiqamar.com/bmat-2010-section-2-question-20/): The total surface area of a cylinder is numerically the same as its volume. The radius of the cylinder is r cm, the height is h cm. Express h in terms of r. Answer: 20) A Total surface area of a cylinder = 2πrh + 2πr²Volume of a cylinder = πr²h Since they are numerically the same, 2πrh + 2πr² = πr²h 2πr (h + r) = πr²h 2 (h + r) = rh 2h + 2r = rh 2r = rh – 2h 2r = h (r – 2) h = 2r ÷ (r – 2)
- [BMAT 2010 Section 2 Question 19](https://samiqamar.com/bmat-2010-section-2-question-19/): The diagrams below show velocity-time or distance-time graphs for 4 different objects, P, Q, Rand S. Which graph(s) show an object accelerating at 2.4m/s2? Answer: 19) B A straight line on the distance-time graphs show us constance velocity (no change in velocity). Since there is not change in velocity, acceleration must be zero.So R and S are definitely wrong. A straight line on velocity-time graphs shows us constant acceleration.Equation for acceleration = (final velocity – initial velocity) ÷ timeAcceleration in P = (10 – 0)/24 = 0.4Acceleration in Q = (60 – 10)/20 = 2.5 (almost 2.4) Hence, the answer is […]
- [BMAT 2010 Section 2 Question 18](https://samiqamar.com/bmat-2010-section-2-question-18/): Magnesium hydrogen phosphate contains the following ions: Mg2+, H+ and PO43-. Which one of the following is a possible formula for magnesium hydrogen phosphate? Answer: 18) B To solve this question, we need to balance the charges to 0. A – WrongMg = 2+2H = 2+2PO₄ = 6-2 + 2 – 6 = -2 B – CorrectMg = 2+4H = 4+2PO₄ = 6-2 + 4 – 6 = 0 C – WrongMg = 2+3H = 3+PO₄ = 3-2 + 3 – 3 = +2 D – WrongMg = 2+6H = 6+2PO₄ = 6-2 + 6 – 6 = +2 E – […]
- [BMAT 2010 Section 2 Question 17](https://samiqamar.com/bmat-2010-section-2-question-17/): In the family tree shown below, both P and Q are carriers of a recessive allele which causes a condition. Only individuals R and X have the condition. What is the percentage likelihood of S, T and U each being a carrier? Answer: 17) E Let the recessive allele be ‘t’ We know P and Q have the recessive allele. Since the condition is caused by recessive allele, the person must have be homozygous recessive. Therefore, the person with the condition must have the genotype ‘tt’ However, we are told that only persons R and X have the condition, meaning that […]
- [BMAT 2010 Section 2 Question 16](https://samiqamar.com/bmat-2010-section-2-question-16/): A shape is formed by drawing a triangle ABC inside the triangle ADE. BC is parallel to DE.AB = 4cm BC = xcm DE = x + 3cm DB = x – 4cm Calculate the length of DE. Answer: 16) C This involves the use of rule of similarity. Triangles ABC and ADE are similar. AB/BC = DA/DE 4/x = x/(x+3)4x + 12 = x²x² – 4x – 12 = 0 Factorising, we get:x² – 6x + 2x – 12x (x – 6) + 2 (x – 6)(x – 6) (x + 2) So x = 6 or x = -2Since […]
- [BMAT 2010 Section 2 Question 15](https://samiqamar.com/bmat-2010-section-2-question-15/): The circuit shows five identical filament bulbs designed to work at 12V connected in a circuit with two switches. Switch P is initially open and switch Q is initially closed. Switch P is then closed and switch Q is opened. Compared with their brightness before these changes were made, how has the brightness of bulbs X and Y changed? Answer: 15) B When switch Q is closed, the current has three pathways to go:1 – the path which has bulbs X and Y2 – the second path which has 2 bulbs3 – the third path with switch Q. When switch Q […]
- [BMAT 2010 Section 2 Question 14](https://samiqamar.com/bmat-2010-section-2-question-14/): Which of the following ionic equations are correct?1 X+ e- → X2 X- e- → X3 O2- + 2e- → O4 O2- – e- → O25 2I- 2e- → I6 Ca2+ + 2e- → Ca Answer: 14) F 1 – If a positively charged ion gains an negatively charge electron, the total charge on the atom would be 0. Hence, this is correct. 2 – If a negatively charged ion loses a negatively charged electron, the total charge on the atom would be 0. Hence, this is correct. 3 – If an ion has charge (2-) and it gains two negatively […]
- [BMAT 2010 Section 2 Question 13](https://samiqamar.com/bmat-2010-section-2-question-13/): Signals are transmitted from one neuron to the next neuron, by molecules. These statements are about this process: 1 Transmitter molecules are formed in the receptors.2 The signal is transmitted across the synapse by osmosis.3 Transmitter molecules are released once the signal has been transmitted across the synapse.4 The release of transmitter molecules is triggered by an impulse.5 The signal is transmitted across the synapse by diffusion.Which of the above statements are correct? Answer: 13) F 1 – WrongTransmitter molecules diffuse to the receptors to be recognised. They are not formed in the receptors. 2 – WrongThe signal is transmitted across […]
- [BMAT 2010 Section 2 Question 12](https://samiqamar.com/bmat-2010-section-2-question-12/): The mean time for running a race by a group of 20 people was 54 seconds. The times for a second group of people were added and the value of the mean went up to 56 seconds. Which formula represents the relationship between the number of people in the second group, P, and the mean time of the second group, T? Answer: 12) C Total time taken by first group = 54 x 20 = 1080sWe know number of people in second group = ‘P’Mean time of second group = ‘T’Total number of people = 20 + PTotal time taken by […]
- [BMAT 2010 Section 2 Question 11](https://samiqamar.com/bmat-2010-section-2-question-11/): When radioactive isotopes decay, they sometimes have to go through a succession of disintegrations to reach a stable isotope. These are called decay chains, and involve the successive emission of numerous α and/or β particles. One such isotope is radon-219 ( 219 86 Rn), which goes through a chain in which three α particles and two β particles are emitted before reaching a stable isotope. What are the atomic and mass numbers of the resulting stable isotope? Answer: 11) C It is important to know what α-particles are and what ß-particles are. An α-particle is basically an Helium atom which contains […]
- [BMAT 2010 Section 2 Question 10](https://samiqamar.com/bmat-2010-section-2-question-10/): Which two of the following are produced by the complete combustion of fuels? 1 CH42 CO3 CO24 H2O5 He6 NH3 Answer: 10) D Be careful! It specifies “complete combustion of fuels”. This makes the whole difference as we will discuss now. 1 – CH4 is not produced in combustion. 2 – CO is produced in INCOMPLETE combustion 3 – CO2 is produced in combustion as all carbon reacts with the oxygen combustion 4 – H2O is produced as the the hydrogen in the hydrocarbons reacts with oxygen during combustion 5 – He is never produced in combustion 6 – NH3 is not […]
- [BMAT 2010 Section 2 Question 9](https://samiqamar.com/bmat-2010-section-2-question-9/): Which one of the following correctly completes the statement: During the process of evolution, natural selection will favour individuals with… Answer: 9) B A – WrongA gene pool consists of all of the alleles within an individual. Natural selection refers to the survival of individuals with and advantageous gene (or alleles within a gene) but not a gene pool. B – CorrectThis is correct. Individuals with advantageous allele will be favoured by natural selection. C – WrongA high reproductive capacity does not necessarily mean that it will have the advantageous allele needed to survive in its environment. D – WrongGeographic distribution […]
- [BMAT 2010 Section 2 Question 8](https://samiqamar.com/bmat-2010-section-2-question-8/): A children’s game is played on a square grid starting in the centre. Players spin two spinners to decide how to move their counters. The first spinner decides the direction (Left, Right, Up or Down) and the second spinner decides the distance (1, 2, 3 or 4 squares). What are the chances that, after two moves, a player is exactly back where they started? Answer: 8) C In order to return to the same position, a player has to land on the opposite direction but the same distance. e.g. A player lands on Right and distance 2. In order to return […]
- [BMAT 2010 Section 2 Question 7](https://samiqamar.com/bmat-2010-section-2-question-7/): The depth of water in a particular tidal harbour varies with time as shown in the graph: If the variation in depth caused by the effect of the tide is considered as a wave, what are the amplitude and frequency of this wave? Answer: 7) A The amplitude is the maximum displacement of a wave from its CENTRE. The amplitude of this wave is (16 – 10)/2 = 3m We know that ƒ=1/T Time period (T) is the total time taken for one oscillation, i.e. time between 2 consecutive troughs or peaks. On the x axis, the time is given. Let […]
- [BMAT 2010 Section 2 Question 6](https://samiqamar.com/bmat-2010-section-2-question-6/): Carbon, in the form of coke, is used to reduce iron oxide in a blast furnace. The three stages are shown below:1 C + O2 → CO22 CO2 + C → 2CO3 3CO + Fe2O3 → 2Fe + 3CO2If 12g of carbon is used in stage 2 and all the carbon monoxide produced is used in stage 3, what mass of carbon dioxide is produced in stage 3? Answer: 6) D Be careful! The question states that 12g of CARBON (i.e. not carbon dioxide) is used in stage 2. In the 2nd equation:Mass of carbon = 12gMr of carbon = 12Moles […]
- [BMAT 2010 Section 2 Question 5](https://samiqamar.com/bmat-2010-section-2-question-5/): The following statements are about hormone levels and their effect:1 Increasing levels of insulin cause an increase in blood glucose levels.2 Increasing levels of oestrogen increases the thickness of the inner lining of the uterus.3 Increasing levels of adrenaline increases the heart rate.Which of the statements are true? Answer: 5) C 1 – WrongInsulin decreases the blood glucose levels 2 – CorrectOestrogen increase the thickness of the inner lining of the uterus 3 – CorrectAdrenaline increase heart rate. Statements 2 and 3 are correct. So C is the answer.
- [BMAT 2010 Section 2 Question 4](https://samiqamar.com/bmat-2010-section-2-question-4/): I have two containers with different capacities. Initially, the larger one is full of water and the smaller one is empty. I pour water from the larger container into the smaller container until they contain the same volume of water. The volume of water in the large container is now p times its capacity and the volume of water in the small container is q times its capacity. Which one of the following statements about p and q must be true? Answer: 4) C Since the big container is full of water, it represents 1 (whole). The water from the big […]
- [BMAT 2010 Section 2 Question 3](https://samiqamar.com/bmat-2010-section-2-question-3/): In a laboratory experiment, protactinium-234 undergoes radioactive decay by β-emission into uranium-234. The table below describes how the mass of uranium-234 present in the sample varies with time from the start of the experiment: Using the information in the table, approximately what is the half-life of protactinium-234? Answer: 3) A This may seem slightly confusing.To start with, we need to know the starting mass of protactinium-234.We know that all of protactinium-234 undergoes decay. So all starting mass of protactinium-234 must have undergone decay to make uranium-234. We know the total mass of uranium-234 formed was 16 g. This means that the […]
- [BMAT 2010 Section 2 Question 2](https://samiqamar.com/bmat-2010-section-2-question-2/): A compound of iodine and oxygen contains 63.5g of iodine and 20.0g of oxygen. Which of the following would be its formula? Answer: 2) E We need to use the formula: n=m/Mr to find out the moles of each of the elements in the compound.mass of iodine = 63.6gMr of Iodine = 127moles = 63.5 ÷ 127 = 0.5 moles mass of oxygen = 20gMr of oxygen = 16moles of oxygen = 20 ÷ 16 = 1.25 Molar ratio = 1.25 ÷ 0.5 = 2.5So for ever 1 mole of iodine, there will be 2.5 moles of oxygen. This can only […]
- [BMAT 2010 Section 2 Question 1](https://samiqamar.com/bmat-2010-section-2-question-1/): Which row of the table correctly describes what happens when body temperature rises in a human? Answer: 1) E Homeostatsis (temperature, water level in body etc.) is related to the hypothalamus. This rules out A,B and C. When our temperature rises, the hair muscles relax, meaning our hair (on hands) lay flat. This rules out F. Our arterioles dilate (become wider or larger) to create a larger surface area. This allows more heat to be radiated out of our body. This rules out option D. Hence E is correct.
- [BMAT 2009 Section 2 Question 27](https://samiqamar.com/bmat-2009-section-2-question-27/): The first graph shows the variation of the displacement of particles with distance along a wave at aparticular instant in time: The second graph shows the variation with time of the displacement of a particular particle in this wave: What is the speed of this wave? Answer: 27) E Time taken for three complete oscillations = 0.6Time taken for one complete oscillation = 0.6 ÷ 3 = 0.2Time taken for two complete oscillations = 0.2 x 2 = 0.4 Distance covered by two complete oscillations = 60m Speed = Distance ÷ TimeSpeed = 60 ÷ 0.4 = 150 m/s
- [BMAT 2009 Section 2 Question 26](https://samiqamar.com/bmat-2009-section-2-question-26/): Naturally occurring chlorine is a mixture of two isotopes with mass number 35 and 37. Theisotope with mass number 35 is three times as common as the isotope with mass number 37. Naturally occurring bromine is a mixture of two isotopes with mass numbers 79 and 81. They are present in equal amounts.What fraction of the naturally occurring compound CH2BrCl has a relative molecular mass of 128? Answer: 26) C We are not sure which isotopes of chlorine and bromine are present in the molecule. Let Ar of Br in the molecule = MLet Ar of Cl in the molecule = […]
- [BMAT 2007 Section 2 Question 8](https://samiqamar.com/bmat-2007-section-2-question-8/): An oxide of iron has the formula Fe3O4 and contains both Fe^2+ and Fe^3+ ions. Which one of the following is the fraction of iron ions that are in the Fe^2+ state? Answer: 8) B                Oxidation number of O in Fe₃O₄ = (-2) x 4 = -8Oxidation number of Fe = +8Possible number of Fe²⁺ and Fe³⁺ atoms = 8 = (3 x 2) + (2)So there are 2 Fe3+ atoms and 1 Fe2+ atom. Fraction = ⅓
- [BMAT 2009 Section 2 Question 25](https://samiqamar.com/bmat-2009-section-2-question-25/): The following five statements relate to homeostasis (the maintenance of stable internal conditions of the body):1 Insulin helps to control the water content of the body.2 Homeostasis depends only on hormones.3 The pancreas helps to control the glucose content of the blood.4 Both the nervous and hormonal systems are involved in homeostasis.5 The skin is used to help control the body temperature.Which statements are correct? Answer: 25) F 1 – WrongInsulin helps to control the glucose content in the body. 2 – WrongHomeostasis also depends on the nervous system and not only hormones. 3 – CorrectPancreas secretes the hormone insulin which […]
- [BMAT 2009 Section 2 Question 24](https://samiqamar.com/bmat-2009-section-2-question-24/): The equation gives y in terms of x. y = 5 (ˣ⁄₂ – 3 )² -10 Rearrange the equation to give an expression for x in terms of y Answer: 24) A We first need to remove the (-10) from the RHSy + 10 = 5 (ˣ⁄₂ – 3 )² We need to remove the 5 and the 4 from the RHS (y + 10) =  (ˣ⁄₂ – 3 )²       5 Square rooting on both sides, ± √y + 10 = ˣ⁄₂ – 3       √5 Removing the 3 from the RHS±  √y + 10 + 3 = ˣ⁄₂       √5 Removing ¹⁄₂ from RHS, 2 [ […]
- [BMAT 2009 Section 2 Question 23](https://samiqamar.com/bmat-2009-section-2-question-23/): A train consists of a powered engine pulling two unpowered carriages. The engine has a mass of 20000kg, and each carriage has a mass of 5000kg. When the engine accelerates from rest it develops a thrust (driving force) of 15000N as shown.Ignoring resistive forces, what is the tension (pulling force) T in the coupling between carriage 1 and carriage 2? Answer: 23) A Total mass of the train = 20000 + 5000 + 5000 = 30000 kg Ratio of masses = 20000 : 5000 : 5000 = 4 : 1 : 1 Initial thrust = 15000 N Total parts in the […]
- [BMAT 2009 Section 2 Question 22](https://samiqamar.com/bmat-2009-section-2-question-22/): At room temperature, a reaction is very fast if no bonds are broken while it takes place, and is slow if bonds have to be broken.1 H2 + I2 → 2HI2 Ag+ + Cl – → AgCl3 ĊH3 + ĊH3 → C2H64 OH- + CH3Br → CH3OH + Br –Which of the following are the two fastest reactions? Answer: 22) D 1 – Slow H-H and I-I bonds are broken. Molecules H₂ and I₂ split to form 2HI. Since bonds are broken, this will be a relatively slow reaction.  2 – Fast No bonds are broken. Ag+ and Cl- just react […]
- [BMAT 2009 Section 2 Question 21](https://samiqamar.com/bmat-2009-section-2-question-21/): The diagram shows a section through an alveolus. Gases diffuse through the alveolar andcapillary walls. Which row explains why gaseous exchange occurs in the alveolus? Answer: 21) D We know that at the alveolus, oxygen diffuses out of the alveolus and carbon dioxide diffuses into the  alveolus.  Since oxygen diffuses out of the alveolus and into the capillary, its concentration must be high in the alveolus since diffusion is movement of particles from high concentration to low concentration.  So first column must be high.  Since oxygen diffuses into, its concentration must be low in the capillary since diffusion is movement of particles from high concentration to low concentration.  So […]
- [BMAT 2009 Section 2 Question 20](https://samiqamar.com/bmat-2009-section-2-question-20/): A solid sphere of radius r fits inside a hollow cylinder. The cylinder has the same internal diameter and length as the diameter of the sphere. The volume of a sphere is ⁴⁄₃ πr³ , where r is the radius of the sphere.What fraction of the space inside the cylinder is taken up by the sphere? Answer: 20) D Diameter of sphere = r x 2 = d Height (or length) of cylinder = d Radius of cylinder = r Volume of cylinder = πr²h = πr²d We need to find the fraction of space taken by the sphere   ⁴⁄₃ πr³    […]
- [BMAT 2009 Section 2 Question 19](https://samiqamar.com/bmat-2009-section-2-question-19/): An object of mass 5kg falls from rest and hits the ground at a speed of 20m/s. Air resistance isnegligible.From what height has the object fallen? Answer: 19) B From rest indicates the initial velocity (u) = 0 Final velocity (v) = 20 m/s Mass = 5 kg Acceleration (g) = 10 m/s² Using SUVAT equation, v = u + at t = (v – u) ÷ a t = (20 – 0) ÷ 10 = 20 ÷ 10 t = 2 seconds s = ut + ½at² s = 0 + ½ x 10 x 2² s = 5 x […]
- [BMAT 2007 Section 2 Question 7](https://samiqamar.com/bmat-2007-section-2-question-7/): A 100 % efficient transformer has 1500 turns on its primary coil. The input to the transformer is 250V ac. The output current is 10A and the output power is 0.5 kW. is the number of turns on the secondary coil? Answer: 7) 300 Let number of turns on primary coil be = N1 = 1500Let number of turns on secondary coil be = N2Input voltage = V1 = 250VOutput voltage = V2 = P/I = (0.5×1000)/10 = 50 V Formula: N1 = N2V1    V2 1500 = N2 250     50 N2 = 300
- [BMAT 2007 Section 2 Question 6](https://samiqamar.com/bmat-2007-section-2-question-6/): The oscillation period, t, for a spiral spring (weight w, radius R made from wire length l, radius r with a modulus of rigidity n) with a weight W hanging from it is given by If such a spring is used to measure the weight, W, of an object we need to rearrange the equation so W is the subject. Which of the following is the correct rearrangement of the equation? Answer: 6) A
- [BMAT 2009 Section 2 Question 18](https://samiqamar.com/bmat-2009-section-2-question-18/): The equation for the preparation of nitrogen monoxide is:a Cu + b HNO3 ——- a Cu (NO3)2 + c H2O + 2NOWhat is the value of b? Answer: 18) D Let us form an equation for the number of O atoms present in the reaction equation. eq 1: 3b = 6a + c + 2 Let us form an equation for the number of H atoms present in the reaction equation. eq 2: b = 2c Let us form an equation for the number of N atoms present in the reaction equation. eq 3: b = 2a + 2 Using the second and third […]
- [BMAT 2007 Section 2 Question 5](https://samiqamar.com/bmat-2007-section-2-question-5/): The three statements below are about exhaling.1 The ribs swing down and inwards during exhaling.2 The diaphragm muscles contract during exhaling.3 The pressure in the lungs increases during exhaling.Which statements are correct? Answer: 5) E Exhale now! You will notice that when you breathe out, your ribs come inwards and downwards. So 1 is correct. However, the diaphragm does not contract while exhalation. It only contracts when you inhale. So 2 is incorrect. Think about statement 3. Air goes from high pressure to low pressure. Since air comes out of your lungs into the surrounding air, it must be going from […]
- [BMAT 2009 Section 2 Question 17](https://samiqamar.com/bmat-2009-section-2-question-17/): Which of the four statements below about natural selection are correct?1 Competition occurs between individuals of the same species.2 Competition occurs between individuals of different species.3 Selection can lead to evolution.4 Selection can lead to extinction. Answer: 17) F 1 – Correct Competition between individuals of the same species is known as intra-specific competition. Intra-specific competition is a part of natural selection.  2 – Correct Competition between individuals of different species is known as inter-specific competition. Inter-specific competition is a part of natural selection.  3 – Correct Natural selection can lead to evolution when individuals with certain characteristics have a greater […]
- [BMAT 2007 Section 2 Question 4](https://samiqamar.com/bmat-2007-section-2-question-4/): The equation connects the variables A, x, y, z, P and Q The following changes are made:x and y are both increased by 50 %z is decreased by 20 %P is doubled and Q remains the same.What is the resulting percentage change in A? Answer: 4) A ‘x’ increases by 50% = 1.5x ‘y’ increases by 50% = 1.5y ‘z’decreases by 20% = 0.8z ‘P’ is doubled = 2P ‘Q’ remains the same = Q
- [BMAT 2009 Section 2 Question 16](https://samiqamar.com/bmat-2009-section-2-question-16/): Evaluate: Answer: 16) F Let us break down such a complicated problem into smaller parts. (2 x 10³) = 2000(8 x 10²) = 800 So, (2 x 10³) + (8 x 10²) = 2000 + 800 = 2800     1      =   0.0004   =    4 x 10⁻⁴  2500 (4 x 10⁻⁴) + (3 x 10⁻⁴) = 7 x 10⁻⁴   2800      =    400 x 10⁴  =  4,000,000  7 x 10⁻⁴ √4,000,000 = 2000
- [BMAT 2007 Section 2 Question 3](https://samiqamar.com/bmat-2007-section-2-question-3/): A detector of radioactivity shows background radiation to be 20 counts per minute with no radioactive sources nearby. A radioactive source which emits alpha particles and beta particles is brought very close to the detector and the detector reading increases to 280 counts per minute. A sheet of paper is then placed between the source and the detector, and the detector reading drops to 60 counts per minute. How many counts per minute were caused by alpha particles and by beta particles from the source? Answer: 3) α = 220, ß = 40 Background radiation = 20 unitsα + ß = […]
- [BMAT 2009 Section 2 Question 15](https://samiqamar.com/bmat-2009-section-2-question-15/): The graph represents the motion of a vehicle during part of a journey. What is the best estimate of the distance travelled during the part of the journey shown? Answer: 15) D We know that total distance travelled = area under graph.  However, remember to always convert the minutes into seconds as the speed is given in metres/second Let us split the graph into a trapezium, a rectangle and a triangle.  Area under trapezium = [h (a+b)] ÷ 2 [60 seconds (15+20)] ÷ 2 = (60 x 35) ÷ 2 = 30 x 35 = 1050m Area under rectangle = (240 […]
- [BMAT 2007 Section 2 Question 2](https://samiqamar.com/bmat-2007-section-2-question-2/): Element x is in the second period of the Periodic Table. An atom of element y has six moreprotons than an atom of element x. Which statement must be correct? A Elements x and y are in the same period of the table.B Elements x and y have the same number of electrons in the first shell.C Element y has six more electrons in its outer shell than does element x.D The nucleon number of element y is six more than that of element x. Answer: 2) B This is quite an obvious answer. The answer is only asking for 1 […]
- [BMAT 2009 Section 2 Question 14](https://samiqamar.com/bmat-2009-section-2-question-14/): The order of reactivity of four elements is J>M>Q>T i.e. J is the most reactive and T the leastreactive. A series of reactions are given below: Which three reactions could take place? Answer: 14) C 1 – Wrong T is less reactive than M. This means that it will not displace M to form TCl₂. 2 – Correct J is more reactive than M. This means that it will displace M to form JSO₄. 3 – Correct Q is more reactive than T. This means that it will displace T to form QO. 4 – Correct J is more reactive than […]
- [BMAT 2009 Section 2 Question 13](https://samiqamar.com/bmat-2009-section-2-question-13/): Which one of the following movements will be severely and immediately disrupted if the oxygenconcentration in the blood becomes very low? Answer: 13) B The key to solve this question is to find out which of these processes are passive and which one is active. Passive processes do not require energy to occur Active processes require energy to occur, meaning they need ATP. ATP can only be formed in the presence of oxygen. So we must find out which of these processes require ATP to occur. A – WrongCO₂ diffuses into the alveoli and diffusion is passive. B – CorrectGlucose absorption […]
- [BMAT 2009 Section 2 Question 12](https://samiqamar.com/bmat-2009-section-2-question-12/): The symbol ⟐ defines a mathematical binary operation such that y ⟐ x =x y^xfor all positive integers.What is the value of (2 ⟐ 3) ⟐ 2? Answer: 12) C From the given information about the symbol, we can form the equation: 2 ⟐ 3 = (2³ ÷ 3 )= [(2 x 2 x 2) ÷ 3] = ⁸⁄₃ [(⁸⁄₃) ⟐ 2] = [(⁸⁄₃)² ÷ 2] = [(⁶⁴⁄₉) ÷ 2] = (⁶⁴⁄₉ x ½)
- [BMAT 2009 Section 2 Question 11](https://samiqamar.com/bmat-2009-section-2-question-11/): It is known that a radioactive source emits a single type of radiation. Detectors are placed in the two positions shown. The graph shows how the readings change over time. Which type of radiation does the source emit, and what is its half-life? Answer: 11) C The detector 2 graph shows us that the background radiation is 20 counts. In order to find the half life, we need to find the initial count rate of the source. This is = 220 – 20 = 200 The half life of the activity would be the time take for the count rate to […]
- [BMAT 2015 Section 2 Question 14](https://samiqamar.com/bmat-2015-section-2-question-14/): Cycloalkanes are alkane compounds that are in a ring shape. Some examples of cycloalkanes are given below. Which statement about these compounds is correct? Answer: 14) C A – They clearly do not have the formula CnH2n+2. They have the formula CnH2ne.g. Cyclohexane has 6 carbons and 12 hydrogen B – They do not react with bromine water. ALKENES react with bromine water.  C – They are saturated compounds. As you can see, all carbon atoms have the maximum number of hydrogen atoms attached to them. Also, all alkanes also have single bonds, meaning they are are fully saturated.  D – They burn in excess […]
- [BMAT 2015 Section 2 Question 13](https://samiqamar.com/bmat-2015-section-2-question-13/): A human consumes the same amount and type of food and drink on two consecutive days. He also does the same activities on both days. However, one of the days is hot and the other is cold. Which row in the table correctly shows the mass of two substances found in the urine of this human on the hot day compared with the cold day? Answer: 13) B On a hot day, more sweating occurs, which results in a decline in water level in the body. So compared to a cold day, the water level in the body on a hot […]
- [BMAT 2015 Section 2 Question 12](https://samiqamar.com/bmat-2015-section-2-question-12/): Given thatܽ a=3/5+X, b= 3+X/5 and c=3+X/5+Xwhereܺ is a whole number greater than zero, whichone of the following is true? Answer: 12) B Since 6 out of the 7 options mention ‘all values of X’ we can use X = 1 to make everything simpler. a = 35 + X b = 3 + X5 c = 3 + X5 + X Substituting X = 1, a = 3 = 3/6 = 1/25 + 1 b = 3 + 1 = 4/55 c = 3 + 1 = 4/6 = 2/35 + 1 The order of inequalities: a < c < […]
- [BMAT 2015 Section 2 Question 11](https://samiqamar.com/bmat-2015-section-2-question-11/): Below are three statements about radioactivity or nuclear energy.1 Neutrons emitted in nuclear fission can cause further fission.2 The half-life of a radioactive substance is half the time taken for all its nuclei to decay.3 The process that produces heat and light in the Sun is called nuclear fission. Which of these statements is/are correct? Answer: 11) A 1 – This statement is correct as neutrons emitted in nuclear fission can cause further fission 2 – The definition of half life is wrong. Half life is the time taken for the radioactivity of a specified isotope to fall to half its […]
- [BMAT 2015 Section 2 Question 10](https://samiqamar.com/bmat-2015-section-2-question-10/): Which of the following statements about the alkali metal rubidium is correct? Answer: 10) D Firstly, alkali metals are the elements in group 1 of the periodic table. A – Rubidium is more reactive than the hydrogen present in the water. Therefore, hydrogen would be formed and not rubidium B – Melting points and boiling points decrease as you move down group 1. Therefore, sodium would have a higher melting and boiling point than rubidium. C – Reactivity increases down group 1. Therefore, rubidium would react more vigorously than sodium in water. D – All elements of the group 1 are […]
- [BMAT 2015 Section 2 Question 9](https://samiqamar.com/bmat-2015-section-2-question-9/): The diagram shows the results of a breeding experiment using a homozygous black mouse and a white mouse. Mouse 1 was then allowed to mate with mouse 2. Using C for the dominant allele for coat colour and c for the recessive allele, which answer below correctly identifies the details of their offspring? Answer: 9) D We first need to know the genotype of mouse 2.We know mouse 1 is homozygous dominant, meaning it is CC.The white mouse must then be homozygous recessive, cc. C C c Cc Cc c Cc Cc There is a 100% chance that mouse 2’s genotype […]
- [BMAT 2015 Section 2 Question 8](https://samiqamar.com/bmat-2015-section-2-question-8/): PQR is an isosceles triangle in which PQ=PR=6cm and QR =8cm. What is the value of the tangent of angleܴܳܲ ? Answer: 8) E Divide the isosceles triangle into two right-angled triangles by joining the midpoint of the largest side with the top vertex. Label the midpoint of QR as M. QM = 8 ÷ 2 = 4 (since M is the midpoint of QR) We first need to find the value of PM.Using Pythagoras, PQ² = QM² + PM²6² = 4² + PM²36 – 16 = PM²PM² = 20PM = √20 = √(2 x 2 x 5) = 2√5 tanθ […]
- [BMAT 2015 Section 2 Question 7](https://samiqamar.com/bmat-2015-section-2-question-7/): A 100% efficient step-down transformer decreases the voltage of an alternating current (a.c.) electricity supply. What effect does this step-down transformer have on the mean power transferred and the alternating current delivered? Answer: 7) D Step down transformer decreases the voltage and increases the current. Power = voltage x current If voltage decreases but current increases, then there is no change in the power transferred.
- [BMAT 2015 Section 2 Question 6](https://samiqamar.com/bmat-2015-section-2-question-6/): The diagram shows the suggested changes in energy labelled as a, b, c, d and e, during a chemical change from reactants to products. Which value is the correct energy change for the REVERSE reaction? Answer: 6) A ‘a’ is the energy change. ‘b’ is the energy of reactants ‘c’ is the activation energy ‘e’ is energy of products Here, the energy of products is more than energy of reactants.Therefore, (products – reactants) would give a positive value. Here it is labelled ‘a’ In the reverse reaction, energy of reactants would be more than energy of products. Therefore, (products – reactants) […]
- [BMAT 2015 Section 2 Question 5](https://samiqamar.com/bmat-2015-section-2-question-5/): Which row identifies what is occurring during anaerobic respiration in animal cells? Answer: 5) A The respiration is ANAEROBIC, meaning no oxygen is used.Carbon dioxide is only formed in aerobic respiration. In anaerobic respiration, no carbon dioxide is formed. Water is never formed in both types of respiration. So, there would be ‘no’ in all three columns. The answer is hence, A.
- [BMAT 2015 Section 2 Question 4](https://samiqamar.com/bmat-2015-section-2-question-4/): A bag contains only 8 beads. The beads are identical in all respects except colour. 3 of the beads are black and the other 5 beads are white. A bead is taken at random from the bag and not replaced. A second bead is then taken at random from the bag. What is the probability that both beads are black? Answer: 4) B Number of beads = 8Number of black beads = 3 Probability of picking a black bead first time = 3/8 Since the bead is not replaced, the bag now contains 7 beads in total. Since a black bead […]
- [BMAT 2015 Section 2 Question 3](https://samiqamar.com/bmat-2015-section-2-question-3/): The colour of the surface of an object has an effect on the rate of infrared radiation that it absorbs and emits. As a result of this, some clothes which are otherwise identical will keep a person warmer when outside in winter because of their differences in colour. Which line in the table shows the correct comparison between black and white surfaces? Answer: 3) B Black surfaces are better absorbers and emitters of infrared than white surfaces. In winter, people need to keep themselves warm. The white, shiny surfaces will reflect infrared back into the person to keep them warm inside […]
- [BMAT 2015 Section 2 Question 2](https://samiqamar.com/bmat-2015-section-2-question-2/): Which of the following organic compounds will decolourise bromine water by reacting with it at room temperature? Answer: 2) C Only alkenes are the organic compounds which turn orange-brown bromine water to colourless. Alkenes have double bonds and have a formula in which there are double the number of other atoms as there are carbon atoms. e.g. C₂H₄, C₃H₆, C₄H₈ 1 – C₂H₄ is an alkene so it will decolourise bromine water 2 – propene is an alkene but polypropene is not as it does not have a double bond. 3 – CH₂ C(CH₃)₂ can be simplified to C₄H₈. This is […]
- [BMAT 2015 Section 2 Question 1](https://samiqamar.com/bmat-2015-section-2-question-1/): Which one of the following is not part of a reflex to the stimulus of placing your hand on a hot object? Answer: 1) E The brain is not involved in the REFLEX to a stimulus. Hence, E is the correct answer. A – Sensory neurone senses a stimulus and then transmits an electrical impulse to the central nervous system.  B – Muscle cells need to to contract in order to produce a movement  C – The motor neurone is the neurone that signals the muscle cells in the erector muscle to take action D – Relay neurones are like bridges which connect sensory neurones and motor […]
- [BMAT 2014 Section 2 Question 27](https://samiqamar.com/bmat-2014-section-2-question-27/): The graph shows the variation with time of the height through which a crane lifts a mass of20 kg.Assume the gravitational field strength g is 10 N / kg, and that the effects of air resistance andfriction are negligible.What is the power output of the crane when the mass is at a height of 10 m? Answer: Power output in this question is about the change in potential energy (mgh) per unit time.The mass and gravitational field strength are constant, so the change in potential energy with time isdirectly related to the change in height with time.In the graph above we […]
- [BMAT 2014 Section 2 Question 26](https://samiqamar.com/bmat-2014-section-2-question-26/): Which of the following atoms / ions contain(s) exactly 18 electrons?1 18O82 34S163 35Cl174 37Cl–175 40Ca2+20 Answer: In an atom, the number of electrons equals the atomic number (the number of protons). None of theatoms (options 1, 2 and 3) have atomic number 18.Negative ions have additional electrons. For example, a 2– ion has two extra electrons compared tothe atom it is formed from. Positive ions have fewer electrons. For example, a 2+ ion has two fewerelectrons than the atom it was formed from. Option 4 has 17 protons and as a 1– ion has 17 + 1electrons, i.e. 18 electrons. […]
- [BMAT 2014 Section 2 Question 25](https://samiqamar.com/bmat-2014-section-2-question-25/): A woman has a recessive genetic condition but neither of her parents has the condition.Which one of the following could not be true? Answer: In order to have the condition, the woman must have two copies of the recessive allele – informationfrom the question. In order to inherit two copies, she must have inherited a recessive copy from eachof her parents. As neither of them have the disorder, they must be heterozygous, so A is true. Herparents must have inherited a recessive allele each from their parents (the woman’s grandparents) sothey could all be carriers (D), one of each set of […]
- [BMAT 2014 Section 2 Question 24](https://samiqamar.com/bmat-2014-section-2-question-24/): A test is developed to detect a certain medical condition. The test is not perfect, and sometimesgives incorrect results. The behaviour of the test on 1000 randomly selected members of thepopulation is shown in this tree diagram, where the following notation is used: Answer: The following is a partially completed tree diagram, showing all the information we need.Therefore 8 + 99 = 107 people test positive, of whom 8 have the condition, so the probability thatsomeone has the condition, given that they test positive, is 8107.Comment: This is only about 7.5%, so the test is quite poor on this population: over […]
- [BMAT 2014 Section 2 Question 23](https://samiqamar.com/bmat-2014-section-2-question-23/): When a particular nucleus of uranium-235 undergoes the process of nuclear fission, it absorbs a neutron and then splits into a nucleus of barium and a nucleus of krypton, as well as releasing further neutrons. Which one of the rows of the table below gives the correct number of neutrons released and the isotopes of barium and krypton produced by this nuclear reaction. Answer: The total mass number of the particles before fission is 235 + 1 = 236 (uranium + neutron). Becausethe total mass number is conserved, the total mass number of the particles after fission must also be236.E) is […]
- [BMAT 2014 Section 2 Question 22](https://samiqamar.com/bmat-2014-section-2-question-22/): Graphene is a new material composed of carbon atoms arranged in tightly bound hexagons just one atom thick.The diagram shows a simplified structure of graphene.Considering its structure, which of the properties below could be predicted about graphene?1 high melting point2 good electrical conductivity3 soluble in water. Answer: The graphene description indicates that it has a giant covalent structure. Typically, substances with agiant covalent structure have high melting and boiling points; they do not dissolve in water and theydo not conduct electricity. However, the structure of graphene is very similar to that of graphite in thateach C atom is covalently bonded to […]
- [BMAT 2014 Section 2 Question 21](https://samiqamar.com/bmat-2014-section-2-question-21/): In order to function, the cells of the brain need large amounts of energy. Any reduction in thefunction of these cells can have serious consequences for the body. For example, a loss ofoxygen supply to the brain can cause unconsciousness within 5–10 seconds.Which of the following statements are true?1 Neurons in the brain are capable of relying on anaerobic respiration for longperiods of time.2 The homeostatic systems of the body will constantly have to work to resisttemperature increases in the brain.3 An overdose of insulin in the body could produce a serious loss of brain function,such as inducing a coma.4 During […]
- [BMAT 2014 Section 2 Question 20](https://samiqamar.com/bmat-2014-section-2-question-20/): The diagram shows part of a glass structure. PQRS is a horizontal square with sides of 1 metre, and point X is 4 metres vertically above P. What is the cosine of the angle that XR makes with the horizontal? Answer: The angle required is XRPUsing Pythagoras theorem PR = √2, since PRis a diagonal of square PQRS.Then triangle XPR is a right angled triangle as X isvertically above P, and by Pythagoras XR = √18 = 3√2then cos(𝑋𝑅𝑃) = 𝑃𝑅/𝑋𝑅 = √2/3√2 = 1/3The answer is A
- [BMAT 2014 Section 2 Question 19](https://samiqamar.com/bmat-2014-section-2-question-19/): The displacement / time graph shown represents a wave of wavelength 1.5 cm. What is the speed of the wave? Answer: Period = 2.0 s so frequency = (1 / 2.0) = 0.50 Hz𝑣 = 𝑓 × 𝜆 = 0.50 × 1.5 = 0.75 cm / sThe answer is C
- [BMAT 2014 Section 2 Question 18](https://samiqamar.com/bmat-2014-section-2-question-18/): An organic compound is found to contain 6 parts of carbon, 1 part of hydrogen and 8 parts ofoxygen by mass.6 g of a gaseous sample of the compound would have a volume of 2.4 dm3 at room temperatureand pressure.Which formula (A–E) is the molecular formula for this compound?(Ar: H = 1; C = 12; O = 16)(1 mole of any gas occupies 24 dm 3 at room temperature and pressure) Answer: The key steps in this solution are finding the molecular mass, from the mass, volume and moleinformation, and then dividing this mass over the 3 elements to figure out […]
- [BMAT 2014 Section 2 Question 17](https://samiqamar.com/bmat-2014-section-2-question-17/): Which of the following statements about lipid digestion in the small intestine is / are correct?1 Emulsification by bile makes smaller lipid droplets, each with a smaller surface area.2 Bile contains an alkali to reduce the pH of the material from the stomach.3 Lipase secreted in bile breaks bonds in lipids to produce glycerol and fatty acids. Answer: Whilst emulsification increases overall surface area as it breaks a large lipid droplet into many smallerdroplets, at the individual droplet level, it decreases the droplet’s surface area. Hence statement 1 iscorrect.Bile is alkaline and neutralises the acid material released from the stomach into […]
- [BMAT 2014 Section 2 Question 16](https://samiqamar.com/bmat-2014-section-2-question-16bmat-2014-section-2-question-16bmat-2014-section-2-question-16/): Three classes in a school all took the same test. Class 1 achieved a mean score of 61, Class 2 achieved a mean score of 63, and Class 3 achieved a mean score of 70. The mean score of the students for all three classes combined was 65. Class 1 contains twice as many students as Class 2. Which one of the following statements about the number of students in Class 3 is true? Answer: Class 1 contains twice as many students as Class 2, so if there are 𝑛 students in Class 2, then thereare 2𝑛 students in Class 1.The […]
- [BMAT 2014 Section 2 Question 15](https://samiqamar.com/bmat-2014-section-2-question-15/): A container is filled with water at 20 °C and placed in a room that is also at 20 °C. The container can be fitted with an internal electric cooling unit, in one of the three labelled positions P, Q or R. The outside of the container can either be painted dull black, or be covered in shiny aluminium foil. In order to cool all the water as quickly as possible to 5 °C, in which position should the cooling unit be fitted, and should the outside of the container be dull black or shiny? Answer: Cooled water will become more […]
- [BMAT 2014 Section 2 Question 14](https://samiqamar.com/bmat-2014-section-2-question-14/): Which of the following statements about but-1-ene are true?1 it can form a polymer2 it contains C–C single bonds only3 it conforms to the general formula CnH2n4 it decolourises bromine water5 it is saturated Answer: The name ‘but-1-ene’ indicates that it is an alkene. Alkenes have the following features:
- [BMAT 2014 Section 2 Question 13](https://samiqamar.com/bmat-2014-section-2-question-13/): In humans, the water content in the blood is regulated via the hormonal system.Which of the following occur when the water content of the blood is too low?1 pituitary gland releases less ADH2 pituitary gland releases more ADH3 increase in water reabsorption by the kidneys4 decrease in water reabsorption by the kidneys5 increased reabsorption of glucose in the kidneys6 decreased reabsorption of glucose in the kidneys Answer: When the water content of the blood is too low, more ADH is released from the pituitary gland(statement 2). The ADH then travels, via the blood stream, to the kidneys and increases thepermeability of […]
- [BMAT 2014 Section 2 Question 12](https://samiqamar.com/bmat-2014-section-2-question-12/): In a town, the bearing of the library from the station is 𝑥∘. The theatre is due east of the library. The theatre and the station are equidistant from the library. What is the bearing (in degrees) of the station from the theatre? Answer: There are several approaches to solving this problem. One approach is given below.Extend north line down at L and recall that alternate anglesbetween parallel lines are equal,so angle SLT = 90 + 𝑥Because the interior angles of any triangle add up to 180°,LTS + LST = 180 − (90 + 𝑥)LTS + LST = 90 − 𝑥.Triangle […]
- [BMAT 2014 Section 2 Question 11](https://samiqamar.com/bmat-2014-section-2-question-11/): Two rods, X and Y, are made from different electrically insulating materials. A student rubs rod X, which is initially uncharged, with a cloth, then holds it near to rod Y. The two rods repel each other. Which statement explains why repulsion occurs in this experiment? Answer: Only electrons are transferred when an object becomes charged. Hence options C, D, G and H are allincorrect. The object becomes negatively charged if it gains electrons and positively charged if it loseselectrons. For repulsion to occur, two objects must have like charges, so either rod X gained electronsfrom the cloth and rod Y […]
- [BMAT 2014 Section 2 Question 10](https://samiqamar.com/bmat-2014-section-2-question-10/): Methanol can be oxidised by hydrogen peroxide to produce carbon dioxide and water.𝐚CH3OH + 3H2O2 → CO2 + 𝐛H2OWhat is the value of 𝐛 when this equation is balanced? Answer: When balancing this chemical equation, you must have the same number of carbon atoms, hydrogenatoms and oxygen atoms on both the reactant side and the product side of the equation. This is onlytrue for the correct answer, C.‘a’ can be calculated first. With just one carbon on the right hand side of the equation it can bededuced that a=1. With this knowledge, the remainder of the equation can be balanced and […]
- [BMAT 2014 Section 2 Question 9](https://samiqamar.com/bmat-2014-section-2-question-9/): Insulin is a protein involved in the regulation of human blood glucose levels. Genetic engineering can be used to allow the large-scale production of human insulin. Which statement describes the process of genetic engineering in this case? Answer: To answer this question correctly you need to understand that the process is carried out in order tomake more insulin (protein). In order to make more protein, you need to use DNA/genes. Therefore Aand B are incorrect since you need to start with DNA/genes. A is also incorrect since the end productrequired is insulin, not insulin DNA/genes.E is incorrect since the process involves […]
- [BMAT 2014 Section 2 Question 8](https://samiqamar.com/bmat-2014-section-2-question-8/): Given that 4𝑝 × 8𝑞 = 2𝑛, express 𝑛 in terms of 𝑝 and 𝑞. Answer: 4𝑝 × 8𝑞 = (22)𝑝 × (23)𝑞= 22𝑝 × 23𝑞= 22𝑝+3𝑞∴ 𝑛 = 2𝑝 + 3𝑞The answer is B
- [BMAT 2014 Section 2 Question 7](https://samiqamar.com/bmat-2014-section-2-question-7/): Which one of the following is a unit of current? Answer: From power 𝑃 = 𝑉𝐼, current 𝐼 = 𝑃 / 𝑉 , so unit (ampere) = watt / voltThe answer is F
- [BMAT 2014 Section 2 Question 6](https://samiqamar.com/bmat-2014-section-2-question-6/): Which row in the table correctly explains why an increase in temperature increases the rate of a reaction? Answer: When the temperature of a reaction is increased, the particles gain kinetic energy so they move fasterand increase the frequency of collisions. The proportion of successful collisions will also increasebecause the proportion of particles with energy greater than the activation energy has increased. Thisis why a small increase in temperature results in a large increase in the rate of a reaction.The activation energy is the minimum energy required by colliding particles to result in a successfulcollision and, therefore, a chemical change. Activation […]
- [BMAT 2014 Section 2 Question 5](https://samiqamar.com/bmat-2014-section-2-question-5/): Before a cell can divide by mitosis, DNA synthesis has to take place. Following DNA synthesis, the DNA is separated into each half of the cell and then the cell divides. The graph below shows the DNA content per cell over a period of time. Which of the letters on the graph represent the sequence of the three events described above? Answer: DNA synthesis doubles the DNA content in the cell so the content will increase from 1 to 2 arbitraryunits, which is M. The DNA separates within the cell but the total content is still 2, so this is N […]
- [BMAT 2014 Section 2 Question 4](https://samiqamar.com/bmat-2014-section-2-question-4/): Simplify:𝑥 2 −4𝑥𝑥 2 −16 Answer:𝑥 2 −4𝑥𝑥 2 −16 = 𝑥(𝑥−4)(𝑥+4)(𝑥−4) = 𝑥(𝑥+4)The answer is B
- [BMAT 2014 Section 2 Question 3](https://samiqamar.com/bmat-2014-section-2-question-3/): Below are four statements about electromagnetic radiation.1 Microwaves have a shorter wavelength than all other electromagnetic waves.2 For identical amplitudes, waves with the largest wavelength transfer the mostenergy.3 The speed of electromagnetic waves is inversely proportional to their frequency.4 Ultraviolet radiation can cause cataracts. Which of these statements is / are correct? Answer: Statement 1 is incorrect; microwaves have a longer wavelength than infrared radiation and manyother parts of the electromagnetic spectrum.Statement 2 is incorrect; energy increases with frequency (and consequently decreases withwavelength), and so in fact the shortest wavelengths transfer the most energy.Statement 3 is incorrect; the wavelength is inversely […]
- [BMAT 2014 Section 2 Question 2](https://samiqamar.com/bmat-2014-section-2-question-2/): Which of the following reactions are redox reactions?1 CuSO4 + Zn → Cu + ZnSO42 HCl + NaOH → NaCl + H2O3 Mg + H2SO4 → MgSO4 + H24 Pb(NO3)2 + 2KI → PbI2 + 2KNO3 Answer: Reaction 1 is a redox reaction because there are changes in oxidation states (ionic charges): theoxidation state of copper changes from +2 to 0 (Cu 2+ + 2e– → Cu [reduction]), and zinc changes from0 to +2 (Zn → Zn2+ + 2e– [oxidation]).Reaction 2 is not a redox reaction because there is no electron transfer (no change in ionic charge,nor oxidation state).Reaction 3 is […]
- [BMAT 2014 Section 2 Question 1](https://samiqamar.com/bmat-2014-section-2-question-1/): The following statements relate to the flow of blood through the heart.1 Oxygenated blood flows through the right side of the heart.2 The vena cava empties deoxygenated blood into the ventricle.3 The heart pumps oxygenated blood through the pulmonary artery.4 There is a valve that prevents backflow of blood from the aorta into the leftventricle.Which of these statements is / are correct? Answer: Statement 1 is incorrect because deoxygenated blood flows through the right side of the heart.Statement 2 is incorrect because blood from the vena cava enters a top chamber which is an atrium.Statement 3 is incorrect because the pulmonary […]
- [BMAT 2013 Section 2 Question 27](https://samiqamar.com/bmat-2013-section-2-question-27/): A resultant force of 20 N has accelerated a body of mass 4.0 kg from rest, until the present moment, at which time its kinetic energy is 1800 J. If this force continues to act unchanged, how much extra kinetic energy will the body gain during the next 2 seconds? Answer: 27) E KE = ½mv² = 1800 Jv = 30 m/s F = maa = F/m = 20/4 = 5 m/s² v = u + at v = ?u = 30a = 5t = 2
- [BMAT 2013 Section 2 Question 26](https://samiqamar.com/bmat-2013-section-2-question-26/): The addition of N0 as a catalyst to a mixture of S02 and 02 speeds up the following reaction: S02 + ½02 � S03The following reactions could be involved in the process. Which one of the following shows the most likely course of the overall reaction? Answer: 26) B We know that a catalyst always remains unchanged at the end of a reaction. This means that at the end of the reaction, NO must be recovered. Hence, reaction 6 will definitely be one of the reactions. Since 6 is only mentioned in option B, B is the answer.
- [BMAT 2013 Section 2 Question 25](https://samiqamar.com/bmat-2013-section-2-question-25/): Manx cats with two recessive alleles have a tail. Heterozygous Manx cats lack a tail. Individuals with both dominant alleles die before birth. Which answer shows the percentage of Manx cats without tails in a population for the two crosses given in the table? Answer: 25) C Manx cat with a tail x Manx cat without a tail t t T Tt Tt t tt tt Manx cat without tail = 50% Manx cat without a tail x Manx cat without a tail T t T TT (dead) Tt (67%) t Tt (67%) tt (33%) Manx cat without tail = 67% […]
- [BMAT 2013 Section 2 Question 24](https://samiqamar.com/bmat-2013-section-2-question-24/): A bag contains 8 blue and 2 red balls. Three balls are chosen at the same time at random from the bag. What is the probability that exactly two of the balls are the same colour? Answer: 24) C We need to find out the probability of either 2 blue balls or 2 red balls. Each of the scenarios has 3 possibilities.That is, 2 red balls can be obtained by RRB, RBR, BRR2 blue balls can be obtained by BBR, BRB, RBB Probability of 2 red balls = 2/10 x 1/9 x 8/8 x 3 = 42/720Probability of 2 red balls […]
- [BMAT 2013 Section 2 Question 23](https://samiqamar.com/bmat-2013-section-2-question-23/): Consider this graph. Which one of the following could the graph not represent if all quantities are in S.I. units? Answer: 23) D A – WrongWith the equation F = ma, we know that F ∝ a and hence this can be a graph of Force against acceleration. B – WrongWith the equation V = IR, we know that V ∝ I and hence this can be a graph of voltage against current. C – WrongWith the equation KE = ½mv², we know that KE ∝ v². D – CorrectWith the equation c = λ x ƒ, we know that λ […]
- [BMAT 2013 Section 2 Question 22](https://samiqamar.com/bmat-2013-section-2-question-22/): By using standard techniques to balance chemical equations and ensuring that the net charge is equal on both sides, find the correct value for ‘ e ‘ in the balanced equation below: Answer: 22) C Number of Cr on LHS = 2Number of Cr on RHS = dSo d = 2 (there are no other Cr on the left and right hand sides) Total charge on left side so far = -2 + 1 = -1Total charge on right side = 2 x (+3) = +6To balance charges, b = +6 – (-2) = + 6 + 2 = +8b = […]
- [BMAT 2013 Section 2 Question 21](https://samiqamar.com/bmat-2013-section-2-question-21/): Which of the following could be found in an adult liver cell? Answer: 21) E The complete set of genes of an organism is found in a cell meaning the liver cell would have the gene for amylase as well as sex chromosomes. However, starch is broken down before it reaches the liver. Hence starch is not found in the liver cell. 1 and 2 are found in an adult liver cell. So, E is the answer.
- [BMAT 2013 Section 2 Question 20](https://samiqamar.com/bmat-2013-section-2-question-20/): The sides of the smallest cube have a length of 1 cm. What is the total surface area of the shape? Answer: 20) D It is advisable to skip such long and tricky questions and finish the other simpler ones first. We need to use a lot of Pythagoras in this question. Side of smaller cube = 1cmSide of 2nd cube = ASide of 3rd cube = B 5 faces of the smallest cube can be seen.Surface area of the smallest cube = 1 x 1 x 5 = 5 cm² The vertices of the smallest cube are at the midpoints […]
- [BMAT 2013 Section 2 Question 19](https://samiqamar.com/bmat-2013-section-2-question-19/): 19 Two resistors of R1 ohms and R2 ohms are connected in series to a battery which has an e.m.f. of V. Which formula gives the power dissipated by resistor R1? Answer: 19) D Total resistance of the circuit = R₁ + R₂Voltage = V We know current remains the same across both resistors.Current of circuit (I) = V ÷ (R₁ + R₂) We know V = IRVoltage across R₁ (V₁) = I x R₁V₁ = [V÷ (R₁ + R₂)] x R₁ = VR₁ ÷ (R₁ + R₂) We know P = VIPower across R₁ = V₁ x IP₁ = [VR₁ […]
- [BMAT 2013 Section 2 Question 18](https://samiqamar.com/bmat-2013-section-2-question-18/): 18 An impure sample of sodium hydroxide has a mass of 1.20 g. All the sodium hydroxide completely reacts with a minimum of 50.0 cm3 of 0.50 mol dm-3 hydrochloric acid. What is the percentage purity of the sodium hydroxide sample? [Ar values: H = 1; 0 = 16; Na = 23; Cl = 35.5] Answer: 18) E Reaction equation: NaOH + HCl  ->  NaCl + H₂O Volume of HCl = 50 cm³ = 0.05 dm³Concentration of HCl = 0.5Moles of HCl = 0.05 x 0.5 = 0.025 mol Molar ratio of NaOH : HCl = 1 : 1Moles of NaOH […]
- [BMAT 2013 Section 2 Question 17](https://samiqamar.com/bmat-2013-section-2-question-17/): Since Dolly the sheep, many other mammals have also been cloned by somatic cell nuclear transfer. The genetic material from a body cell is inserted into an egg cell that has had its own nucleus removed. The success rate ranges from 0.1% to 3%, which is why so few cloned animals have been produced. Which of the following are possible correct reasons why cloning may fail? Answer: 17) A 1 – CorrectIf the off does not divide then the organism cannot form. 2 – WrongThere is no use of sperm cells 3 – CorrectIf the implantation fails, then the cloning will […]
- [BMAT 2013 Section 2 Question 16](https://samiqamar.com/bmat-2013-section-2-question-16/): Three variables x, y and z are known to be related to each other in the following ways: Which of the following correctly describes the relationship between x and y? Answer: 16) D Let us write down the information given into proportions first. x ∝ z²y ∝ ¹⁄z³ Making powers equal, x³ ∝ z⁶       (eq 1) y² ∝ ¹⁄z⁶z⁶ ∝ ¹⁄y²       (eq 2) Using eq 1 and 2, z ∝ x³ ∝ ¹⁄y² So the cube of x is inversely proportional to the square of y.
- [BMAT 2013 Section 2 Question 15](https://samiqamar.com/bmat-2013-section-2-question-15/): Two radioactive sources X and Y have half-lives of 4.8 hours and 8.0 hours respectively. Both decay directly to form only stable isotopes. The activity of a sample of the source X was measured by a detector as 320 counts per minute, and simultaneously the radioactivity of a sample of the source Y was measured as 480 counts per minute. Immediately after the measurements, the two samples were combined. What was the count rate when the activity of the combination of X and Y was measured 24 hours later?[Assume that all readings in this question have been corrected for background radiation.] […]
- [BMAT 2013 Section 2 Question 14](https://samiqamar.com/bmat-2013-section-2-question-14/): Which one of the following pairs do not have the same electronic structure? Answer: 14) A A – CorrectMg has 2 electrons on its outer shell. Each of these electrons will go to each of the Cl atoms. These chloride atoms will have the same electronic structure as an Ar atom. However, the Mg atom would have the electronic structure of a Ne atom. Hence, this is the answer. B – WrongCarbon has 4 electrons on its outer shell. It forms a triple bond with O. Both C and O would have eight electron on their outer shells.These N atoms form a […]
- [BMAT 2013 Section 2 Question 13](https://samiqamar.com/bmat-2013-section-2-question-13/): Which of the following is not needed in order to genetically engineer bacterial cells to produce a fluorescent protein from a jellyfish? Answer: 13) C This might be a tricky question but the actually, the answer is in the question itself. The question asks what is not needed to produce a fluorescent protein. This why the answer is C. We do not need a florescent protein in order to produce another a fluorescent protein.
- [BMAT 2013 Section 2 Question 12](https://samiqamar.com/bmat-2013-section-2-question-12/): The square ABCD is positioned so that its vertices are at the points with coordinates: (1, 1), (-1, 1), (-1, -1) and (1, -1). The square is rotated clockwise through 90o about the origin and then reflected in the line y = x. Which transformation will return the square to its original orientation? Answer: 12) B
- [BMAT 2013 Section 2 Question 11](https://samiqamar.com/bmat-2013-section-2-question-11/): The diagrams show two glass blocks in air. For the rays of light shown, the critical angle for the glass/air boundary is 42°. A ray of light is shown approaching the boundary in each case, with the angle of incidence labelled. Two possible labelled directions in which each ray might travel after reaching the boundary are also shown. Which line in the table correctly shows the direction taken by most or all of the light and also states whether total internal reflection (T.I.R.) will occur? Answer: 11) C Source: Wikipediahttps://en.wikipedia.org/wiki/Total_internal_reflection#/media/File:RefractionReflextion.svg -When angle of incidence is lower than critical angle, refraction occurs. […]
- [BMAT 2013 Section 2 Question 10](https://samiqamar.com/bmat-2013-section-2-question-10/): 1.15 g of sodium completely reacts with water at standard temperature and pressure (STP). What volume of hydrogen at STP is produced by this reaction? [Assume in this question that 1 mole of any gas at STP has a volume of 22.4 dm3 (litres).] [Ar values: H = 1, 0 = 16, Na = 23] Answer: 10) B We must first write down the full equation for the reaction. 2Na + 2H2O -> 2NaOH + H2 Moles of Na = m/Mr = (1.15 ÷ 23) ≈ (1.2 ÷ 24) = 0.05 molMolar ratio (NaOH:H2) = 2:1Moles of H2 = (0.05÷2) = […]
- [BMAT 2013 Section 2 Question 9](https://samiqamar.com/bmat-2013-section-2-question-9/): In a reflex action in which a person touches a hot plate and pulls their arm away, neurons of different lengths are involved. Which answer identifies the relative lengths of the neurons? Answer: 9) F Sensory neurones are the longest since they have to cover the length from the point of stimulus to the spinal chord. Motor neurones are shorter than sensory neurones but longer than relay neurones since they have to travel from the spinal cord to the muscle erector. Relay neurones are the shortest as they are only in the spinal cord.
- [BMAT 2013 Section 2 Question 8](https://samiqamar.com/bmat-2013-section-2-question-8/): Simplify: Answer: 8) F Break the problem into smaller parts 1st step:  x² (1 – 16x²) = x² – 16x⁴ 2nd step:  2x³ (4x – 1) = 8x⁴ – 2x³ 3rd step:   x² – 16x⁴8x⁴ – 2x³ 4th step:  4 –  x² – 16x⁴      8x⁴ – 2x³ 4 (8x⁴ – 2x³) – (x² – 16x⁴)           8x⁴ – 2x³ 32x⁴ – 8x³ – x² + 16x⁴       8x⁴ – 2x³ 48x⁴ – 8x³ – x²     8x⁴ – 2x³ x² (48x² – 8x – 1) x² (8x² – 2x) 48x² – 8x – 1   8x² – 2x […]
- [BMAT 2013 Section 2 Question 7](https://samiqamar.com/bmat-2013-section-2-question-7/): 7 The diagram shows three appropriate meters, P, Q and R, connected in the conventional way in a circuit. The switch is initially open. The switch is now closed. What happens to the readings on each meter? Answer: 7) H With the switch open, the circuit was in series. With the switch closed, the circuit became parallel. Parallel circuits have a lower overall resistance than a series circuit.With the equation, V=IR, we know that current is inversely proportional to resistance. The overall voltage cannot change.Since voltage doesn’t change and resistance decreases, current must increase. Since the switch is now closed, there […]
- [BMAT 2013 Section 2 Question 6](https://samiqamar.com/bmat-2013-section-2-question-6/): The following reaction is at equilibrium: 2R(g) + 3S(g)  2T(g)      llH is negative which conditions (A-E) would produce most of the product T? Answer: 6) B In order to produce more T, we need the forward reaction to occur. The forward reaction is exothermic since ∆H is negative. This means that the forward reaction releases energy. If we lower the temperature, the forward reaction will be favoured. Therefore, more T will be formed if temperature is low. A high pressure causes the equilibrium shifts to the side with the lower number of moles. There are 5 moles on the left side […]
- [BMAT 2013 Section 2 Question 5](https://samiqamar.com/bmat-2013-section-2-question-5/): The action of which enzyme(s) could decrease the pH of a mixture of carbohydrate, protein and lipid? Answer: 5) F A logical way of solving this question is to identify the products which will be formed when these three enzymes are added to the mixture. Carbohydrase enzyme will break carbohydrates into sugars which are non-acidic. Protease will break protein into amino acids. Amino acids are slightly acidic which means they would lower the pH Lipase will break fats into fatty acids and glycerol. So the action of enzymes protease and lipase will lower the pH of the mixture
- [BMAT 2013 Section 2 Question 4](https://samiqamar.com/bmat-2013-section-2-question-4/): Answer: 4) A Substitute the values given in the problem 4.6 x 10⁷ + 7 (2 x 10⁶)4.6 x 10⁷ – 2 (2 x 10⁶) (4.6 x 10⁷) + (14 x 10⁶)(4.6 x 10⁷) – (4 x 10⁶) (4.6 x 10⁷) + (1.4 x 10⁷)(4.6 x 10⁷) – (0.4 x 10⁷) 6 x 10⁷4.2 x 10⁷ The two (10⁷) will cancel out 6 = 1 = 104.2 0.7 7
- [BMAT 2013 Section 2 Question 3](https://samiqamar.com/bmat-2013-section-2-question-3/): Microwave, X-ray and infra-red radiation can all damage living tissues. Which of the following statements correctly explain why this damage occurs? Answer: 3) D 1 – Microwaves do get absorbed by water molecules. An example of this when water molecules in food absorb microwaves from the microwave oven and heat up the food. 2 – The ionising properties of X rays means that they can damage the DNA in the cells of the human body. 3 – Infra red waves do not penetrate matter Only statements 1 and 2 are correct so D is correct
- [BMAT 2013 Section 2 Question 2](https://samiqamar.com/bmat-2013-section-2-question-2/): The following chemicals are mixed together. In which of the mixtures will a displacement reaction occur? Answer: 2) D You must try and remember the reactivity series. This question is totally dependent on that. If the element in the salt is lower down in the reactivity series compared to element it is being reacted with, a displacement reaction will occur. 1 – Al is more reactive than Pb and so will displace Pb. 2 – K is more reactive than F- and hence no displacement reaction will occur 3 – Al is more reactive than Fe so no displacement reaction will […]
- [BMAT 2013 Section 2 Question 1](https://samiqamar.com/bmat-2013-section-2-question-1/): Which of the following applies to both the nervous system and the endocrine (hormonal) system? Answer: 1) H 1 – both the nervous system and the endocrine system can be involved in homeostasis. e.g. hypothalamus in the brain detects a decrease in water level in the body. Pituitary gland secretes ADH to reabsorb more water to prevent dehydration 2 – chemicals in the nervous system could include noradrenaline. Endocrine system secretes hormones which are chemicals. 3 – pituitary gland is in the brain and receives information from the hypothalamus. Brain is part of the nervous system. Statements 1, 2 and 3 […]
- [BMAT 2012 Section 2 Question 27](https://samiqamar.com/bmat-2012-section-2-question-27/): A sound wave is produced by a loudspeaker cone, which creates pulses of pressure by moving back and forth between two points X and Y as shown in the diagram.The distance between points X and Y is 5.0mm and the loudspeaker produces pulses of pressure every 0.2 milliseconds.The following statements about the sound wave produced are made:P It has a speed of 25m/sQ It has an amplitude of 5.0mmR It has a wavelength of 5.5mmS It has a fundamental frequency of 5.0kHzWhich of these statements can be correctly deduced from the information given? Answer: 27) G P – WrongWe can immediately […]
- [BMAT 2012 Section 2 Question 26](https://samiqamar.com/bmat-2012-section-2-question-26/): A mixture of C2H4(g) and H2(g) is placed in a sealed container. Some finely divided nickel is added as a catalyst to the mixture. The temperature rises to 150°C and the two gases slowly react to give C2H6(g). Which row of the table correctly identifies how the pressure changes after the nickel is added? Answer: 26) E Since temperature is proportional to pressure, pressure will initially increase to allow both gases to react. Now let us write out the reaction equation C₂H₄ + H₂  ->  C₂H₆ Using the equilibrium rules, we can see that moles of products is ½ of moles of reactants. […]
- [BMAT 2012 Section 2 Question 25](https://samiqamar.com/bmat-2012-section-2-question-25/): What is the minimum number of people shown in the family pedigree who must be heterozygous for the two situations described in the table in the absence of any new mutations? Answer: 25) E Let the dominant allele be: TLet the recessive allele be : t If only U has a recessive condition, their genotype must be tt. This means that S and T must be heterozygous.Since we want the minimum number of heterozygous people, we must assume that R has to be TT.In order for S to be Tt and R to be TT, only one of P and Q needs to heterozygous.This means that if only […]
- [BMAT 2012 Section 2 Question 24](https://samiqamar.com/bmat-2012-section-2-question-24/): The new sign for a local business contains two different sections. One of the sections will be produced from wood, while the other will be metal. Metal is three times as expensive as wood. The cost of metal needed for each sign is proportional to the diameter of the sign, while the cost of wood needed is proportional to the square of the diameter. If the diameter of the sign is doubled, then the total cost of the materials will be tripled. What percentage (to the nearest 1%) of the sign is metal? Answer: 24) A The explanation to this question […]
- [BMAT 2012 Section 2 Question 23](https://samiqamar.com/bmat-2012-section-2-question-23/): A cyclist and a bike have a combined mass of 100kg. The cyclist free-wheels (rolls without pedalling) at a constant speed of 0.8m/s down a 1 in 10 slope (this means that the cyclist descends 1.0m for each 10m travelled along the road, as shown in the diagram.) Calculate the loss in gravitational potential energy as he loses 100m in vertical height and hence calculate the total resistive force on the cyclist. Answer: 23) D Let us find the GPE when the cyclist is 100m in vertical height. Also, this is the amount of GPE that will be lost when the […]
- [BMAT 2012 Section 2 Question 22](https://samiqamar.com/bmat-2012-section-2-question-22/): Tritium, symbol T, is hydrogen with a mass number of 3. It is radioactive and undergoes βdecay.Which of the following could be the only product(s) after a quantity of HTO undergoes decay?1 He OH2 H2O, O2 and He3 H2O, H2 and He Answer: 22) B When an atom decays by ß decay, its mass number remains the same. Tritium beta decays into Helium-3 (isotope of Helium which has a mass number 3). You may have figured it out already as all three options have He as a product. It may seem that HTO will form HeOH as both are single molecules. […]
- [BMAT 2012 Section 2 Question 21](https://samiqamar.com/bmat-2012-section-2-question-21/): In a monohybrid genetic cross a ratio of phenotypes of 3:0 rather than the usual 3:1 ratio wasseen. This could be due to:1 offspring with both dominant alleles not surviving.2 only a small number of offspring being produced.3 chance. Answer: 21) D 1 – Since 1 of the phenotypes was not seen, it means that the offspring with both RECESSIVE alleles did not survive. 2 – For any scientific research, a large sample size is very important as it reduces the effect of chance. Therefore, this statement is correct. A small sample size could be the reason why a different ratio […]
- [BMAT 2012 Section 2 Question 20](https://samiqamar.com/bmat-2012-section-2-question-20/): In a fairground game there are two bags, each of which contains 4 coloured balls. There are a total of 4 red balls, 3 yellow balls and 1 blue ball. The player chooses one of the bags and removes two balls without replacing them. If the two balls are the same colour then the player wins. The player is equally likely to choose either bag and the balls are arranged to give the smallest possible probability for the player to win. What is the probability that the player wins? Answer: 20) B Since the balls are arranged in a way to […]
- [BMAT 2012 Section 2 Question 19](https://samiqamar.com/bmat-2012-section-2-question-19/): The circuit shows three lamps and two ammeters in a circuit. Lamp X ‘blows’ (the filament breaks).What happens to the reading on each ammeter, and to the total resistance of the circuit? Answer: 19) D Since the filament breaks, there is not pathway for current along the wire connected to lamp X. Current can only flow through the branch (which is now converted from parallel to series).We know that resistance in series is always greater than resistance in parallel.Therefore, overall resistance would increase.Since overall resistance increases and voltage remains the same, reading in ammeter 1 must decrease.R = V/I shows that […]
- [BMAT 2012 Section 2 Question 18](https://samiqamar.com/bmat-2012-section-2-question-18/): Vanadium is a metal that lies just above zinc in the reactivity series. Which one of the following could not be used to obtain the metal from its ore? Answer: 18) D A – WrongChlorine is above zinc and vanadium in the reactivity series. So no displacement. B – WrongSodium is above zinc and vanadium in the reactivity series. So no displacement. C – WrongAluminium is above zinc and vanadium in the reactivity series. So no displacement. D – CorrectVanadium is above iron in the reactivity series so it cannot be displaced by the iron. E – WrongMagnesium is above zinc […]
- [BMAT 2012 Section 2 Question 17](https://samiqamar.com/bmat-2012-section-2-question-17/): Consumption of alcohol leads to an increase in dilute urine production by reducing the level of the hormone ADH.Which of the following are correct statements about alcohol and/or ADH?1 ADH travels in the bloodstream.2 There is a positive correlation between the level of ADH and the production of dilute urine.3 Increased ADH leads to increased formation of dilute urine.4 A reduced level of ADH could lead to dehydration. Answer: 17) C 1 – Since ADH is a hormone, it has to travel in the bloodstream. So this is correct.  2 – ADH causes water to be reabsorbed into the bloodstream from the […]
- [BMAT 2012 Section 2 Question 16](https://samiqamar.com/bmat-2012-section-2-question-16/): In the triangle ABC shown below (not to scale): tanA=1/6 and tanB 2/3 M is the midpoint of AB. What is the value of tan θ Answer: 16) C This is a tricky question. First, draw a line perpendicular to AB from C. Label the line be CP. We have tan A = CP = 1AP 6 So, CP = 1, AP = 6 We have tan B = CP = 2BP 3 Since CP = 1, BP = (3 ÷ 2) = 1.5 Since BP = 1.5, then AP = 6 AB = (AP + BP) = (1.5 + 6) […]
- [BMAT 2012 Section 2 Question 15](https://samiqamar.com/bmat-2012-section-2-question-15/): The microwaves generated in a microwave oven travel through air at a speed of 3.0 x 10 8 m/s, with a wavelength of 12cm. They pass through plastic food containers, but at a reduced speed of 2.0 x 10 8 m/s. What are the wavelength and frequency of these microwaves as they pass through a plastic food container? Answer: 15) B We have been given the speed and wavelength of the microwave in air. When the microwave enter a plastic food container, the speed reduces. By using the formula, c = ƒ x λ, we know speed is directly proportional to wavelength. […]
- [BMAT 2012 Section 2 Question 14](https://samiqamar.com/bmat-2012-section-2-question-14/): Azurite is a mineral made up of a mixture of CuCO3 and Cu(OH) 2. Which one of the following is a possible formula of azurite? Answer: 14) F By looking at all the options, we can see that all of the formulae given have 3 copper atoms. This means that 1 of the molecules ; either CuCO3 or Cu(OH)2 have 2 moles and the other has 1 mole.  1st possibility – 2CuCO₃ + Cu(OH)₂ -> Cu₃C₂H₂O₈  2nd possibility – CuCO₃ + 2Cu(OH)₂ -> Cu₃CH₄O₇ The first possibility is correct as the option is given but the second possibility is not correct as the option is not given. 
- [BMAT 2012 Section 2 Question 13](https://samiqamar.com/bmat-2012-section-2-question-13/): The left diagram shows a plate containing a jelly with one species of bacterium evenly spread through it. Placed on the jelly are three discs called P, Q and R. They have been treated as in the key.The right diagram shows the plate 48 hours later.Key:P = disc with antibiotic at strength ¼XQ = disc with antibiotic at strength ½XR = disc with antibiotic at strength XWhich of the following is/are possible explanations for the result?1 Antibiotic at strengths X and ½X are equally as effective.2 Bacterial resistance to this antibiotic occurs at all three strengths.3 S may represent the maximum […]
- [BMAT 2012 Section 2 Question 12](https://samiqamar.com/bmat-2012-section-2-question-12/): Evaluate: 2 x 10⁵ = 0.08 x 10¹¹ = 8 x 10⁹25 x 10⁻⁶ Answer: 12) E Let us break up the problem into smaller pieces and solve them individually. (2 x 10⁵)(5 x 10⁻³)² = (25 x 10⁻⁶)  So,   2 x 10⁵      =    0.08 x 10¹¹   =   8 x 10⁹25 x 10⁻⁶ ³√(8 x 10⁹) = 2000 (4 x 10³) – (4 x 10²) = 4000 – 400 = 3600√3600 = 60 So 2000 – 60 = 1940
- [BMAT 2012 Section 2 Question 11](https://samiqamar.com/bmat-2012-section-2-question-11/): The diagrams show, not to scale, three different situations in which a force F acts. Also shown in each case is a distance d.Diagram 1:Person sitting on a chairDiagram 2:Wheelbarrow being liftedDiagram 3:Weight being lifted by a motorWhich line in the table shows whether or not work is being done by force F in each situation and, if so, whether the work done is equal to F x d? Answer: 11) D Work is only done when a force is applied and a body moves for a distance in the direction of the force. Diagram 1The person is siting on a […]
- [BMAT 2012 Section 2 Question 10](https://samiqamar.com/bmat-2012-section-2-question-10/): Inorganic builders are put into detergents to act as a buffer, i.e. to keep the pH close to 7. Sodium tripolyphosphate is a major one used. The equation for its formation is shown below:aNaH2PO4 + bNa 2HPO4 → cNa 5P3O10 + dH2OWhat are the values of a, b, c and d? Answer: 10) D The only way to solve this is to try all the options and see if they are correct.
- [BMAT 2012 Section 2 Question 9](https://samiqamar.com/bmat-2012-section-2-question-9/): In one type of neurological disease, neurons are unable to detect a certain stimulus which would normally cause pain. In a patient with this disease, which of the following would be true?1 The patient would not show a reflex action to the stimulus.2 The patient would be able to take appropriate action if they could also see the application of the stimulus.3 The patient would be able to sense pain but would not be able to respond to it.4 The patient would be able to sense pain but would not be able to communicate this to the brain. Answer: 9) A […]
- [BMAT 2012 Section 2 Question 8](https://samiqamar.com/bmat-2012-section-2-question-8/): A formula which connects the ‘going’, G, with the ‘rise’, R, of stairs in a staircase is below:G = 5 + √7 (9 – R)² + 9Rearrange the formula to give R in terms of G. Answer: 8) E G = 5 + √7 (9 – R)² + 9 G – 5 = √7 (9 – R)² + 9 Squaring both sides, (G – 5)² = 7 (9 – R)² + 9 (G – 5)² – 9 = 7 (9 – R)² (G – 5)² – 9 = (9 – R)²         7 Square Rooting on both sides,  √(G – […]
- [BMAT 2012 Section 2 Question 7](https://samiqamar.com/bmat-2012-section-2-question-7/): Students investigate a radioactive source. They place a detector close to a radioactive source and take 5 readings over 5 minutes. They then place a thin sheet of paper between the detector and the source, and again observe the counts over 5 minutes. Lastly they replace the paper sheet with an aluminium one and observe the counts over 5 minutes. Their results are shown below: What type(s) of radiation is being given off by the source. Answer: 7) D None of the radiation was stopped by paper, meaning no α radiation was present. Some of the radiation was stopped by aluminium […]
- [BMAT 2012 Section 2 Question 6](https://samiqamar.com/bmat-2012-section-2-question-6/): The diagram represents the molecule lecithin, a chemical that is added to chocolate drinks to prevent the oils separating out from water. Which row of the table below correctly identifies the characteristics of the molecule? Answer: 6) C This is rather a simple question. You must have seen a similar diagram in AS biology in the cell membrane topic. The tail is always hydrophobic (hydro-water and phobic-fear; so hydrophobic means it does not like water), meaning it does not like to get in contact with water. Hydrophilic means it can react with water. The head of the head of the molecule […]
- [BMAT 2012 Section 2 Question 5](https://samiqamar.com/bmat-2012-section-2-question-5/): The diagrams below show part of the breathing apparatus of a human. Which row of the table correctly identifies the locations affected by two chemicals found in cigarettes and by two diseases associated with smoking? Answer: 5) B Let us first name the areas first. Area 1 is the brainArea 2 is the bronchiArea 3 is alveoliArea 4 is the blood vessel We know bronchitis will occur in the bronchi. Therefore area 2 will be affected by bronchitis. We can eliminate option C, D, E and F. We know that nicotine which is present in cigarettes affects the brain which is […]
- [BMAT 2012 Section 2 Question 4](https://samiqamar.com/bmat-2012-section-2-question-4/): The design in the diagram is formed from four circles which all touch at the top of the shape (the diagram is not to scale).The diameter of the smallest circle is d, the second is 2d, the third is 3d and the largest is 4d. Find an expression for the area of the shading in the design. Answer: 4) A Radius of largest circle = 4d ÷ 2 = 2dArea of largest circle = π (2d)² = π 4d² Radius of third largest circle = 3d ÷ 2 = 1½dArea of third largest circle = π (1½ d)² = π 2¼d² […]
- [BMAT 2012 Section 2 Question 3](https://samiqamar.com/bmat-2012-section-2-question-3/): Nuclide XNR is an unstable isotope which decays in two stages into nuclide Z as shown:What are the values of P and Q? Answer: 3) B When an atom decays and its atomic number decreases by 2, we can conclude that it must have emitted α-particles which are helium atoms. If it emits a helium atom, its mass number must also decrease by 4. Therefore, P must equal to N – 4. We can eliminate options D, E and F. Now, we know that atom Y decays further and its mass number P remains the same but its has a new […]
- [BMAT 2012 Section 2 Question 2](https://samiqamar.com/bmat-2012-section-2-question-2/): 2.74g of 1-bromobutane is reacted with excess aqueous sodium hydroxide to produce 1.11g of butan-1-ol according to the equation below.C4H9Br + NaHO → C4 H9OH + NaBrWhat is the percentage yield of butan-1-ol? Answer: 2) D Mr of 1-bromobutane = (12×4) + (1×9) + 80 = 137Moles of 1-bromobutane = mass/Mr = 2.74/137 = 0.02 mol Molar ratio of 1-bromobutane and butan-1-ol = 1:1Moles of butan-1-ol = 0.02 molMr of butanol = (12×4) + (1×9) + (16) + (1) = 74Mass of butanol = moles x Mr = 0.02 x 74 = 1.48 gMass of butan-1-ol obtained = 1.11g Percentage yield […]
- [BMAT 2012 Section 2 Question 1](https://samiqamar.com/bmat-2012-section-2-question-1/): Which of the following could result in a homeostatic response?1 A rise in an internal condition.2 A reduction in an internal condition.3 A rise in an external condition.4 A reduction in an external condition. Answer: 1) F Be careful of what the question is saying. Which of the situations could RESULT in a homeostatic response. 1 – A rise in internal condition. An example could be increase in blood glucose level in the body 2 – A reduction in internal condition. An example of this could be decrease in water level in body 3 – An example could be increase in […]
- [BMAT 2011 Section 2 Question 27](https://samiqamar.com/bmat-2011-section-2-question-27/): At the front of a long column of soldiers is a man regularly hitting a drum 50 times a minute. The soldiers are told to place their left foot down on the ground when they hear the drum beat. The column is so long that the soldiers at the back put down their left feet at the same time as the soldiers in the front put down their right feet.What is the minimum length of the column of soldiers? [Speed of sound in air is 330m/s] Answer: 27) B 50 beats per minute means after every 60/50 seconds (1.2 seconds), there […]
- [BMAT 2011 Section 2 Question 26](https://samiqamar.com/bmat-2011-section-2-question-26/): An impurity in petroleum is dimethylsulphide, CH 3SCH3. When dimethylsulphide is burnt in an excess of air, which one of the following balanced equations represents the reaction that takes place? Answer: 26) E Reacting with air essentially means that it is reacting with oxygen. Different elements present in CH₃SCH₃: C, H and S Carbon will form its oxide, Hydrogen will form its oxide (water) and sulphur will form its oxide.There would be three products: CO₂, H₂O AND SO₂ Therefore, the answer could only be E.
- [BMAT 2011 Section 2 Question 25](https://samiqamar.com/bmat-2011-section-2-question-25/): The graph below shows how one factor in the internal environment in a person changes, and is returned to a normal level. If someone has a condition which makes their homeostatic system less responsive, how would the shape of the graph be altered? Answer: 25) D This is slightly tricky. It is important to realise which number indicates what. 1 on the graph indicates the change in internal environment.2 indicates the point at which the response to the change is initiated.3 indicates the time taken to bring the level back to normal. Since someone has a condition which makes their homeostatic […]
- [BMAT 2011 Section 2 Question 24](https://samiqamar.com/bmat-2011-section-2-question-24/): I have two six-sided dice, each with faces numbered from 1 to 6. One of the dice is fair, but the other is not – it will land on numbers 1 to 5 with equal probability, but lands on 6 with a different probability. When I roll the dice the probability that I get a total of 12 is 1/18.What is the probability that I get a total of 2 when I roll the dice? Answer: 24) B Only way to get a total of 12 is to get 6 on both dices.Since first die is fair, probability of getting a […]
- [BMAT 2011 Section 2 Question 23](https://samiqamar.com/bmat-2011-section-2-question-23/): A ray of orange light travelling through air has a speed of 3.0 x 10 8 m/s and a wavelength of600nm. (1nm = 10 -9m)What could be the speed, frequency and wavelength of this orange light when travelling through glass? Answer: 23) C When a wave travels from a less dense medium to a more dense medium (such as from air to glass), its speed decreases and it refracts. So, we can eliminate options E, F, G and H. Speed = wavelength x frequency FREQUENCY NEVER CHANGES DURING REFRACTION. Since frequency does not change but speed decreases, therefore, its wavelength must […]
- [BMAT 2019 Section 2 Question 6](https://samiqamar.com/bmat-2019-section-2-question-6/): A chemist used electrolysis to electroplate a pure copper rod with a layer of silver. The concentration of metal ions in the electrolyte was kept constant. Which row in the table identifies appropriate substances used as the anode (positive electrode), the cathode (negative electrode) and the electrolyte? Answer:
- [BMAT 2019 Section 2 Question 5](https://samiqamar.com/bmat-2019-section-2-question-5/): The labels 1, 2 and 3 in the following diagram represent cellular processes. The shaded areas represent processes that can happen without the use of energy provided by cellular respiration. Which processes could labels 1, 2 and 3 represent? Answer:
- [BMAT 2019 Section 2 Question 4](https://samiqamar.com/bmat-2019-section-2-question-4/): The non-zero numbers p and q are such that p + q = 3 ( p – q )What is the value of PQ /P2 +Q2 ? Answer: 4) B
- [BMAT 2019 Section 2 Question 3](https://samiqamar.com/bmat-2019-section-2-question-3/): The diagram shows the forces acting on a cyclist as she accelerates at 4.0 m s –2 on a straight, horizontal section of road. The constant resistive forces are air resistance and a 300 N force due to friction. The combined mass of the cyclist and bicycle is 50 kg. What is the value of the air resistance? Answer: 3) B We know that the cyclist is moving forwards with acceleration 4 m/s2. This means that the cyclist needs to overcome the resistive forces in order to move forwards. So we can conclude that 600 N > 300 N + air […]
- [BMAT 2019 Section 2 Question 2](https://samiqamar.com/bmat-2019-section-2-question-2/): A cleaning solution is used to remove limescale, CaCO 3, from bathroom surfaces. When the solution is sprayed onto the limescale, effervescence (fizzing) occurs and the solid limescale begins to disappear. This chemical reaction is needed because the limescale cannot be removed with water alone.Which of the following statements about this chemical reaction are correct?1 The cleaning solution is acidic.2 The effervescence (fizzing) is caused by the release of hydrogen gas.3 The pH of the reacting solution will go down as the reaction proceeds.4 The salt produced in the reaction is more soluble than CaCO 3. Answer: 2) C CaCO3 is […]
- [BMAT 2019 Section 2 Question 1](https://samiqamar.com/bmat-2019-section-2-question-1/): The diagram shows some stages involved in genetic engineering. Which row correctly identifies W, X, Y and Z? Answer: 1) E W is a section of the chromosome. It is not the entire chromosome, so it has to represent a gene.X represents restriction enzymes that cut DNA into smaller fragments at certain specific nucleotide sequences.Y represents plasmid which is circular DNA of bacteria.Z represents ligase which connects the DNA taken from the chromosome and the plasmid DNA.
- [BMAT 2018 Section 2 Question 27](https://samiqamar.com/bmat-2018-section-2-question-27/): The radioactive isotope carbon-14 is found in living material in small quantities. There areapproximately 1000 carbon-14 atoms for every 10 15 carbon-12 atoms. Whilst the material is stillliving this ratio remains constant, because even though the carbon-14 is decaying, it is beingconstantly replenished. When the material dies the carbon-14 decays and is not replaced. Thehalf-life of carbon-14 is about 6000 years.In a bone the ratio of carbon-14 to carbon-12 atoms is found to be 100 : 10 15 .Which of the following is the closest estimate of the age of the bone? Answer: 27) E When the material is living the […]
- [BMAT 2018 Section 2 Question 26](https://samiqamar.com/bmat-2018-section-2-question-26/): Xenon gas reacts with fluorine gas to form gaseous xenon hexafluoride at high temperatureand pressure. The overall energy change is − 330 kJ / mol.Under these conditions, the F – F bond energy of the fluorine gas is 158 kJ / mol.What is the Xe – F bond energy? Answer: 26) C Xenon hexafluoride has 1 xenon atom and 6 fluorine atoms. (The prefix hexa- means six) Fluorine is diatomic gas. In order to receive 6 fluorine atoms, we need to use three fluorine gas molecules (3F2) Xenon is a noble gas so it is present as an atom only. We […]
- [BMAT 2018 Section 2 Question 25](https://samiqamar.com/bmat-2018-section-2-question-25/): In a type of fruit fly the brown body colour allele is dominant to the black body colour allele. A male fruit fly heterozygous for body colour and a female fruit fly heterozygous for body colour were allowed to mate, producing offspring. What is the ratio, in its simplest form, of the maximum number of genotypes in the offspring to the maximum number of phenotypes in the offspring? Answer: 25) C Let dominant allele be BLet recessive allele be b Genotype of male fly = BbGenotype of female fly = Bb Simple monohybrid cross produces 3 genotypes: BB, Bb and bb (You should […]
- [BMAT 2018 Section 2 Question 24](https://samiqamar.com/bmat-2018-section-2-question-24/): Which one of the following is a simplification of x/x-1 – x2+3/ x2 +2x-3? Answer:
- [BMAT 2018 Section 2 Question 23](https://samiqamar.com/bmat-2018-section-2-question-23/): The radioactive isotope plutonium-244 becomes radon-220 after a succession of decays. The atomic number of plutonium is 94 and the atomic number of radon is 86. How many alpha particles and how many beta particles are emitted altogether during the decay of one nucleus of plutonium-244 to radon-220? Answer: 23) B Mass number only decreases by alpha decay. After each alpha decay, the mass number decreases by 4. Decrease in mass number = 244 – 220 = 24Number of alpha decays = 24 ÷ 4 = 6 After 6 alpha decays, the atomic number will decrease by 12.So atomic number would […]
- [BMAT 2018 Section 2 Question 22](https://samiqamar.com/bmat-2018-section-2-question-22/): A compound of oxygen and fluorine has a relative molecular mass which is twice that of its empirical formula mass. 105 g of the compound contains 57 g of fluorine. What is the molecular formula of the compound? (Ar values: O = 16; F = 19) Answer: 22) C Mass of oxygen = 105 – 57 = 48 To find the empirical formula, we divide the masses of the elements with their Ar. For fluorine, 57/19 = 3For oxygen, 48/16 = 3 Then, we divide all obtained values by the lowest value. In this case, we only receive one value, 3. So the empirical formula […]
- [BMAT 2018 Section 2 Question 21](https://samiqamar.com/bmat-2018-section-2-question-21/): An animal cell is surrounded by a very dilute glucose solution which has a lower concentration of glucose than the glucose solution in the cytoplasm of the cell. There is net movement of glucose molecules and water molecules into the cell.A second, identical cell is treated for a short time with a chemical which inhibits respiration. The cell is then surrounded by the same glucose solution.Which row in the table shows the effect of this chemical on the movement of glucose molecules into the cell and the movement of water molecules across the cell surface membrane immediately after it is surrounded […]
- [BMAT 2018 Section 2 Question 20](https://samiqamar.com/bmat-2018-section-2-question-20/): The mean mass of a sweet in a bag of 20 sweets must be greater than 10 grams but not greater than 10.5 grams. A bag is being filled with sweets. The mean mass of the first 16 sweets is exactly 9.5 grams. Four more sweets, each of mass x grams, are added to the bag to bring the mean mass of the 20 sweets into the correct range. What is the complete range of possible values of x ?/ Answer: 20) A We can find the total mass of the first 16 sweets. Total mass of 16 sweets = 16 […]
- [BMAT 2018 Section 2 Question 19](https://samiqamar.com/bmat-2018-section-2-question-19/): A circuit consists of a 10 Ω resistor and a variable resistor connected in series with a 6.0 V battery. The variable resistor has a minimum resistance of 2.0 Ω and a maximum resistance of 20 Ω. What is the difference between the largest and smallest currents possible in this circuit? Answer: 19) B Maximum current is when there is minimum resistance. The lowest value of resistance = 10 + 2 = 12 Ω I = V ÷ R = 6 ÷ 12 = 0.5 A Minimum current is when there is maximum resistance. The highest value of resistance = 10 […]
- [BMAT 2018 Section 2 Question 18](https://samiqamar.com/bmat-2018-section-2-question-18/): Which of the following shows the correct structure of part of the polymer formed by thepolymerisation of CH3 – CH = CH – CH3 ? Answer: 18) E The double bond between 2nd and 3rd carbon atom becomes a single bond. The carbon atoms that were part of the double bond will each have a methyl group attached (CH3). This is only shown by option E. In A, there are no methyl groups. In B, there are methyl groups on every alternate carbon atom. So this is wrong. In C, not all carbon atoms part of the polymer chain have a methyl group. […]
- [BMAT 2018 Section 2 Question 17](https://samiqamar.com/bmat-2018-section-2-question-17/): The diagram shows a simple piece of apparatus that can be used to demonstrate some of the events involved in human ventilation. Which events occurring during ventilation will be demonstrated by pulling the rubber diaphragm downwards, as shown by the arrow?1 diaphragm relaxes2 diaphragm contracts3 volume of thorax increases4 volume of thorax decreases5 pressure in thorax increases6 pressure in thorax decreases Answer: 17) F When diaphragm flattens, it contracts. So statement 2 is correct. Volume of thorax increases. So statement 3 is correct. Pressure decreases so statement 6 is correct. F is the answer.
- [BMAT 2018 Section 2 Question 16](https://samiqamar.com/bmat-2018-section-2-question-16/): The first four triangular numbers are:The difference between the first and second triangular numbers is 2.The difference between the second and third triangular numbers is 3.The difference between the third and fourth triangular numbers is 4.All the triangular numbers follow this pattern.The difference between the r th triangular number and the (r+3 )th triangular number is 126.What is the value of r ? Answer: 16) B Let difference between r and r + 1 = MLet difference between r + 1 and r + 2 = NLet difference between r + 2 and r + 3 = O The sum of […]
- [BMAT 2018 Section 2 Question 15](https://samiqamar.com/bmat-2018-section-2-question-15/): A champion weightlifter raises a 200 kg set of weights from the floor to above his head in one movement. The bar is lifted through a vertical distance of 1.8 m. When the lift is completed the weightlifter holds the weights stationary for 2.0 seconds and then drops them to the floor. At what speed do the weights hit the floor?(gravitational field strength = 10 N / kg) Answer: 15) E PE at the top of the lift = 200 x 10 x 1.8 = 3600 JAll PE is converted to KE just before contact with the ground.½ mv2 = 3600(200) v2 = […]
- [BMAT 2018 Section 2 Question 14](https://samiqamar.com/bmat-2018-section-2-question-14/): The masses of atoms and molecules can be determined using a mass spectrometer. The masses can be shown as a series of peaks. Element X exists as a diatomic molecule. The mass spectrum will show the mass of ions from individual atoms of X and from X2 molecules. The mass spectrum for element X is shown below:How many different isotopes of X can be determined from this spectrum Answer: 14) B The two spikes at 35 and 37 indicate two isotopes of element X. The spike at 70 is due to two isotopes of mass 35 existing as a diatomic molecule. […]
- [BMAT 2018 Section 2 Question 13](https://samiqamar.com/bmat-2018-section-2-question-13/): The diagram shows three different types of animal cell. 1 epithelial cell2 mature red blood cell3 muscle cellWhich of these cells is/are found as part of a tissue? Answer: 13) H All cells shown in the question form tissues. Epithelial cells together form epithelial tissue. Mature red blood cells form blood, which is a connective tissue. Muscle cells form muscle tissue.
- [BMAT 2018 Section 2 Question 12](https://samiqamar.com/bmat-2018-section-2-question-12/): All four corners of a rectangle are on the circumference of a circle.The rectangle has a perimeter of 24 cm.The ratio of length : width for the rectangle is 3 : 1What is the area of the shaded region in cm2 ? Answer: 12) F It is important for you to realise that the diameter of the circle is the diagonal of the rectangle. Let width of rectangle be W. So length is 3W 2(3W + W) = 24 cm8W = 24 cmW = 3 cmLength = 3 x 3 = 9 cm Diagonal = hypotenuse of one right-angled triangle.Diagonal2 = 32 + […]
- [BMAT 2018 Section 2 Question 11](https://samiqamar.com/bmat-2018-section-2-question-11/): Quantities associated with a moving vehicle include its velocity, speed, momentum and kinetic energy. Which of these quantities will always change if the vehicle changes direction? Answer: 11) E Speed does not necessarily change when a vehicle changes direction, as speed is a scalar quantity. So A, B and C are wrong. Velocity is a vector quantity so when a vehicle changes direction, its velocity changes. Momentum is a vector quantity as its equation is p = mv, it depends on velocity. If a vehicle changes direction, its velocity changes so its momentum also changes. Kinetic energy does not change, as […]
- [BMAT 2018 Section 2 Question 10](https://samiqamar.com/bmat-2018-section-2-question-10/): Iron is extracted from iron ore (which contains Fe2O3) using carbon monoxide. This overall reaction is slow and so must be heated. The chemical equation for this reaction under certain conditions is shown below:Fe2O3 + 3CO → 2Fe + 3CO2 ∆H = − 30 kJ / molWhich one of the following statements about this process is correct. Answer: 10) C In iron (III) oxide, iron has an oxidation state of +3. In iron (in products), iron has an oxidation state of 0. So iron is reduced, which means it has gained electrons. So A is wrong. The oxide ions in iron […]
- [BMAT 2018 Section 2 Question 9](https://samiqamar.com/bmat-2018-section-2-question-9/): A sample of healthy human cells contains 4 cells. After they were allowed to divide 5 times using the same type of cell division, there were 128 cells in the sample. Assuming that no mutations occur, which two of the following statements are correct?1 All the cells would have the same number of chromosomes.2 The cells were gametes.3 The cells would be clones of the original cells.4 This type of cell division is called meiosis. Answer: 9) B We must first identify the type of cell division that occurred. 4 cells divided 5 times to form 128 cells. Mitosis produces 2 […]
- [BMAT 2018 Section 2 Question 8](https://samiqamar.com/bmat-2018-section-2-question-8/): My wallet contains two 50p coins and five 20p coins only. I need 70p to buy an item. If I pick two coins at random from my wallet, what is the probability that I have picked the exact money to buy the item? Answer: 8) C We need exactly 70p worth of coins. So that is one 50p coin and one 20p coin. Best way to do this is to draw a tree diagram. We can only take the dashed paths shown above. 1st dashed path gives us = 2/7 x 5/6 = 10/42 = 5/212nd dashed path gives us = 5/7 x […]
- [BMAT 2018 Section 2 Question 7](https://samiqamar.com/bmat-2018-section-2-question-7/): A wave travelling through a material has a frequency of 50 Hz and a wavelength of 0.40 m. How long does it take the wave to travel 100 m through this material? Answer: 7) E Using c = f λ, Speed of wave in material = 50 x 0.4 = 20 m/s Time = Distance ÷ Speed = 100 ÷ 20 = 5 s
- [BMAT 2018 Section 2 Question 6](https://samiqamar.com/bmat-2018-section-2-question-6/): The diagram below shows the apparatus that can be used in fractional distillation. Which of the following statements is/are correct about the process shown in the diagram?1 Covalent bonds between atoms are broken at position 1 and have reformed at position 3.2 The particles are closer together at position 3 than at position 2.3 The physical process at position 1 involves an exothermic change. Answer: 6) C 1 – Wrong. Covalent bonds in position 1 are between one liquid and the other liquid. However, in position 3, only one of the liquids is obtained so the same covalent bonds are not formed. 2 – Correct. […]
- [BMAT 2018 Section 2 Question 5](https://samiqamar.com/bmat-2018-section-2-question-5/): The diagram shows part of the nitrogen cycle. Which of the numbered arrows represent(s) denitrification? Answer: 5) A In Denitrification, nitrate ions are reduced to produce nitrogen gas (N2). This is only shown by process 1. So the answer is A.
- [BMAT 2018 Section 2 Question 4](https://samiqamar.com/bmat-2018-section-2-question-4/): Which one of the following is a simplification of 48 m5 p / 40m2 p3 ? Answer: 4) B 48/40 = 6/5 m5 ÷ m2 = m3p ÷ p3 = p-2 The simplification is 6/5 m3 p-2 So the answer is B
- [BMAT 2018 Section 2 Question 3](https://samiqamar.com/bmat-2018-section-2-question-3/): Here are four statements about light:1 In a vacuum, green light travels faster than blue light.2 In a vacuum, the wavelength of red light is greater than the wavelength of green light.3 In water, red light travels faster than it travels in a vacuum.4 In water, the frequency of blue light is greater than the frequency of red light.Which pair of statements is correct? Answer: 3) E 1 – False. All light travel at the same speed in vacuum. 2 – True. Red light always has a larger wavelength than green light. 3 – False. All light travel faster in vacuum […]
- [BMAT 2018 Section 2 Question 2](https://samiqamar.com/bmat-2018-section-2-question-2/): Elements Q and Z are shown in the Periodic Table as: What is the empirical formula and bonding type of the compound formed between these elements? Answer: 2) C Q has electronic configuration of 2, 8, 2Z has electronic configuration of 2, 7 Q needs to lose 2 electrons to have full outer shell and Z needs 1 electron to have full outer shell. Q has a valency of 2 and Z has a valency of 1. (two Z atoms are needed for each Q atom) So the Empirical formula would be QZ2 The bonding would be ionic because Q loses […]
- [BMAT 2018 Section 2 Question 1](https://samiqamar.com/bmat-2018-section-2-question-1/): People with cystic fibrosis may be unable to digest their food fully because of thick sticky mucus. This prevents the secretion of pancreatic juices. Doctors sometimes prescribe enzyme supplement medication to improve digestion. Which of the following enzymes should be included in the medication?1 amylase2 lipase3 protease Answer: 1) H Pancreatic juices contain amylases, lipases and proteases. Since cystic fibrosis prevents the secretion of pancreatic juices, the medication must contain amylases, lipases and proteases
- [BMAT 2017 Section 2 Question 27](https://samiqamar.com/bmat-2017-section-2-question-27/): A graph of kinetic energy, in joules ( y – axis) against the square of the speed in (m / s) 2 (x – axis) is plotted for an object of mass 2.5 kg travelling along the surface of the Earth. The result is a straight line. What is the numerical value of the gradient of this line? Answer: 27) C We know that KE = 0.5mv² We first need to find out whether the graph will go through zero or not.Using the eqaution above, we can see that if v² = 0, then K.E. will also be equal to 0.So […]
- [BMAT 2017 Section 2 Question 26](https://samiqamar.com/bmat-2017-section-2-question-26/): What is the volume of hydrogen gas formed (measured at room temperature and pressure)when 0.23 g of pure sodium reacts completely with an excess of water?(Ar values: H = 1.0; Na = 23.Assume that the molar volume of gas at room temperature and pressure is 24 dm3.) Answer: 26) B Let us first write down the reaction equation. 2Na + 2H2O  –>  2NaOH + H₂ We have the Mr of Sodium = 23 and its mass = 0.23g Moles = Mass / Mr = (0.23 / 23) = 0.01 mol Molar ratio (Na : H) = 2 : 1 So moles […]
- [BMAT 2017 Section 2 Question 25](https://samiqamar.com/bmat-2017-section-2-question-25/): The picture shows a Siamese cat. This type of cat has a gene which is sensitive to temperature. When this gene is inactive in the cells, the coat colour is pale. When the gene is active, it produces an enzyme which causes the coat colour to be darker. If this cat had grown up in a warmer environment its ears, front of face, paws and tail would be paler than those shown in the picture below.A student wrote the following statements using this information.1 The enzyme is denatured at the internal body temperature of the cat so the coat colour is […]
- [BMAT 2017 Section 2 Question 24](https://samiqamar.com/bmat-2017-section-2-question-24/): The diagram shows a shape made from a quarter circle of radius 6 cm and a right-angled triangle with a hypotenuse of length 9 cm. Which of the following expressions gives the area, in square centimetres, of the shape? Answer: 24) C Area of the quarter of circle = 0.25 π r² 0.25π(6)²0.25 π 369π In order to find the area of the triangle, we first need to find the base (B). We need to use Pythagoras for this.  (9)² = (6)² + (B)²81 = 36 + B²45 = B²B = √45 = √(3 x 3 x 5) = 3√5 Area of triangle = 0.5 x 6 x […]
- [BMAT 2017 Section 2 Question 23](https://samiqamar.com/bmat-2017-section-2-question-23/): A book rests on a table, which in turn rests on the floor. The floor exerts a force P on the table. Force P and one other force constitute a Newton’s Third Law interaction pair of forces. What is the other force? Answer: 23) F Newton’s Third Law:If a body A exerts a force on body B, then B will exert an equal and opposite force on A. The information given to us says that the floor (body A) exerts a force on the table (B). So the table must also exert an equal and opposite force on the floor.
- [BMAT 2017 Section 2 Question 22](https://samiqamar.com/bmat-2017-section-2-question-22/): Hydrated copper(II) sulfate has the formula CuSO4·5H2O. 100 cm3 of a solution contained 10 g of hydrated copper(II) sulfate. What is the concentration, in mol / dm3, of this solution? (Ar values: H = 1.0; O = 16; S = 32; Cu = 64) Answer: 22) B Mr of hydrated copper (II) sulfate = (64) + (32) + (16 x 4) + (10 x 1) + (16 x 5) = 250Mass of hydrated copper (II) sulfate = 10 g Moles = Mass / Mr = 10 / 250 = 0.04 mol We know moles = concentration x volumeWe have the volume […]
- [BMAT 2017 Section 2 Question 21](https://samiqamar.com/bmat-2017-section-2-question-21/): The family tree shows the inheritance of freckles. Which row in the table shows the probability that the next child produced by parents 1 and 2, and the probability that the next child produced by parents 5 and 6 will have freckles? Answer: 21) D We first need to figure out whether the freckles are caused by a recessive allele (let us say ‘f’) or a dominant allele (let us say ‘F’). Let us start with individuals 5 and 6. Assuming that the condition is caused by recessive allele, then both 5 and 6 must be ff. If they are both ff, then […]
- [BMAT 2017 Section 2 Question 20](https://samiqamar.com/bmat-2017-section-2-question-20/): Express 1 + 1 – 12x x-1 x as a single algebraic fraction. Answer: 20) E 1 + 1 – 12x x-1 x Let us do the first part of the problem. 1 + 1 = x – 1 + 2x = 3x-12x x-1 2x(x-1) 2x(x-1) 3x-1 – 1 = x(3x-1) – [2x(x-1)]2x(x-1) x x (2x) (x-1) 3x² – x – 2x² + 2x = x² + x = x (x + 1)x (2x) (x-1) x (2x) (x-1) x (2x) (x-1) (x+1)(2x) (x-1)
- [BMAT 2017 Section 2 Question 19](https://samiqamar.com/bmat-2017-section-2-question-19/): A swimming pool is 10 m wide. A loud sound is made in the water 2.0 m from one wall and the reflected sounds are detected with a microphone placed next to the sound source. The reflection from the wall 8.0 m away arrives 0.010 s after the reflection from the wall 2.0 m away. What is the speed of sound in water? Answer: 19) E It is important to understand the situation. The last line states that the reflected sound from the 8m wall reflects from the 2m wall and is then detected by the microphone.So the waves cover the […]
- [BMAT 2017 Section 2 Question 18](https://samiqamar.com/bmat-2017-section-2-question-18/): Propanoic acid is a monoprotic acid. Magnesium is a Group 2 metal. Which of the following chemical equations is correct for the reaction between magnesium carbonate and propanoic acid? Answer: 18) C A monoprotic acid is an acid which gives a single proton or hydrogen ion in aqueous solution.Since magnesium is in group 2, its valency would be 2. Therefore, the product of magnesium and propanoic acid would be Mg(C₃H₅O₂)₂.So, we can eliminate options B, D and E. Since the other reactant is MgCO₃ and not just Mg, carbon dioxide will also be produced as one of the products. Therefore, A […]
- [BMAT 2017 Section 2 Question 17](https://samiqamar.com/bmat-2017-section-2-question-17/): The diagram shows an external view of the human heart. Which of the following statements about the artery shown on the diagram is/are correct?1 It is the site of diffusion of glucose and oxygen into the muscle cells of the heart.2 It transports blood at high pressure.3 It contains muscle cells. Answer: 17) G You will need to identify that the artery is coronary artery. The coronary artery supplies the muscles of the blood with oxygen and nutrients. 1 – WrongThe coronary artery supplies the muscles of the blood with oxygen and nutrients. HOWEVER, the site of diffusion of glucose and […]
- [BMAT 2017 Section 2 Question 16](https://samiqamar.com/bmat-2017-section-2-question-16/): The acceleration due to gravity at the surface of a planet is given by 2RGMg = , where M and Rare the mass and radius of the planet respectively, and G is the gravitational constant.It is given thatg = 10 N / kgG = 7 × 10 –11 N m2 / kg 2R = 6 × 10 6 mWhat is M, correct to one significant figure? Answer: 16) A g = GMR² gR² = GM M = gR²G Substituting the values, M = 10 x (6 x 10⁶)²7 x 10⁻¹¹ M = 10 x 36 x 10¹7 x 10⁻¹¹ M = […]
- [BMAT 2017 Section 2 Question 15](https://samiqamar.com/bmat-2017-section-2-question-15/): Uranium-238 is a naturally-occurring alpha emitter. It can be used in the manufacture of the isotope plutonium-239, during which it is bombarded by neutrons. The process of converting a nucleus of uranium-238 to a nucleus of plutonium-239 is a three-stage sequence of nuclear reactions.What is this sequence?(Atomic numbers: uranium = 92; plutonium = 94) Answer: 15) F The question clearly says that Uranium-238 is bombarded by neutrons. So the 1st stage would involve absorption of a neutron. This would cause the mass number to increase from 238 to 239, forming Plutonium-239. The following stages must involve ß-decay as the atomic number increases from […]
- [BMAT 2017 Section 2 Question 14](https://samiqamar.com/bmat-2017-section-2-question-14/): Disproportionation is the simultaneous oxidation and reduction of the same species in areaction.In which of the following chemical equations does disproportionation occur?1 Fe + CuCl2 → FeCl2 + Cu2 Cu 2O → Cu + CuO3 Cl2 + H2O → HCl + HClO4 BaCl2 + Na2SO4 → BaSO 4 + 2NaCl5 Hg 2Cl2 → Hg + HgCl2 Answer: 14) E In order for a species to disproportionate, the species must occur twice in the products. In reactions 1 and 4, all species occur only once in the products. In reaction 2,Cu appears twice in the products.Oxidation state of Cu in Cu₂O in […]
- [BMAT 2017 Section 2 Question 13](https://samiqamar.com/bmat-2017-section-2-question-13/): Dolly the sheep was born in 1996. She was unusual because she had no biological father. Sheep have a diploid number of 54 chromosomes in their body cells. The diagram shows the process of how she was produced.Which of the following statements about this process is/are correct?1 The gamete cell nucleus contained 27 chromosomes.2 The cells produced in step 4 had the same properties as stem cells.3 None of the cells involved in the process were produced by meiosis. Answer: 13) E 1 – CorrectThe gamete is always haploid meaning it would contain half the number of chromosomes as other body […]
- [BMAT 2017 Section 2 Question 12](https://samiqamar.com/bmat-2017-section-2-question-12/): In triangle PRS, line QT is parallel to side RS.RS = 1.5 cmTS = 1.8 cmQT = 0.3 cmWhat is the length of PS? Answer: 12) F To solve this question, we need to use the similarity rules. You need to identify that triangles PQT and PRS are similar.  QT   =       RS PT         PT + TS  0.3    =       1.5 PT          PT + 1.8 0.3 (PT + 1.8) = 1.5PT0.3PT + 0.54 = 1.5PT0.54 = 1.2PTPT = 0.54 ÷ 1.2 = 0.45 PS = PT + TSPS = 0.45 + 1.80 […]
- [BMAT 2017 Section 2 Question 11](https://samiqamar.com/bmat-2017-section-2-question-11/): Two resistors R1 and R2 are connected in series with a cell. Resistor R1 has twice the resistance of resistor R 2. Six statements about this circuit are given below.1 The voltage across each resistor is the same.2 The voltage across R1 is twice that across R 2.3 The voltage across R2 is twice that across R 1.4 The current is the same in both resistors.5 The current in R1 is twice the current in R 2.6 The current in R2 is twice the current in R 1.Which pair of statements is correct? Answer: 11) C The resistors are in series. […]
- [BMAT 2017 Section 2 Question 10](https://samiqamar.com/bmat-2017-section-2-question-10/): A piece of magnesium ribbon is dropped into a beaker of dilute aqueous hydrochloric acid at room temperature. After a while the production of bubbles of gas slows down. Which of the following statements can correctly explain this observation?1 The particles have less energy.2 The concentration of hydrochloric acid decreases.3 The activation energy for the reaction increases. Answer: 10) C If it helps, you can write down the reaction equation. This will show you that hydrogen gas will be produced. Mg + 2HCl → MgCl₂ + H₂ 1 – WrongDecrease in energy does not decrease the amount of gas produced. 2 […]
- [BMAT 2017 Section 2 Question 9](https://samiqamar.com/bmat-2017-section-2-question-9/): The diagram shows four experiments used to investigate movement of substances across dialysis tubing. This tubing is a partially permeable membrane which allows both glucose and water to pass through it. Which row in the table shows the experiment(s) where there will be movement of glucose through the partially permeable membrane and the experiment(s) where there will be movement of water through the partially permeable membrane? Answer: 9) E Experiment 1 – Movement of water but no movement of glucoseThere is distilled water in both the tubing and in the test tube. Even though there is no concentration gradient, water molecules […]
- [BMAT 2017 Section 2 Question 8](https://samiqamar.com/bmat-2017-section-2-question-8/): In a group of 20 patients at a medical centre, 5 suffered from migraines. Two patients from the group of 20 were picked at random for a survey on the use of painkillers. What is the probability that both of the patients picked suffered from migraines? Answer: 8) A Out of 20 patients, 5 have migraine.Probability of the first patient having migraine = ⁵⁄₂₀ = ¼ Since 1 patient with migraine is already picked, number of patients left with migraine = 5 – 1 = 4Total number of patient remaining = 20 – 1 = 19Probability of the second patient having […]
- [BMAT 2017 Section 2 Question 7](https://samiqamar.com/bmat-2017-section-2-question-7/): A puddle is left on a road after a rain shower. The water in the puddle slowly disappears by evaporation. Three statements about the effect of changing different conditions on this process are given below.1 The rate of evaporation is greater at higher temperatures.2 The rate of evaporation is greater when the air above the puddle is still.3 The rate of evaporation is greater when the puddle has a larger surface area.Which of the statements is/are correct?(Assume for each statement that all other conditions remain the same.) Answer: 7) F 1 – CorrectAt higher temperatures, there will be more heat energy. […]
- [BMAT 2017 Section 2 Question 6](https://samiqamar.com/bmat-2017-section-2-question-6/): Which of the following atoms and ions contain(s) 20 neutrons and 18 electrons? 1 –23416 S2 –lC37173 Ar40184 +K39195 Ca Answer: 6) D Remember mass number = no. of protons + neutrons 1 – WrongThis ion contains 16 protons.No. of neutrons = 34 – 16 = 18. We need 20 neutrons. 2 – CorrectThis ion contains 17 protons.No. of neutrons = 37 – 17 = 20.Number of electrons in a Cl atom = 17Since this ion has a charge of (-1), number of electrons = 17 + 1 = 18 3 – WrongThis atom contains 18 protons.No. of neutrons = 40 – 18 […]
- [BMAT 2017 Section 2 Question 5](https://samiqamar.com/bmat-2017-section-2-question-5/): SCID is an inherited condition in humans. People with some types of SCID are unable to make a functional enzyme necessary for the production of healthy white blood cells. A scientist studying these types of SCID compared features of the DNA and the structure of the enzyme in people who have this condition and people without SCID.Which of the following features may have been different?1 the allele of the gene coding for the enzyme2 the order of amino acids in the enzyme3 the order of bases in the gene coding for the enzyme4 the shape of the active site of the […]
- [BMAT 2017 Section 2 Question 4](https://samiqamar.com/bmat-2017-section-2-question-4/): Which one of the following is equivalent to (√5 – 2)²? Answer: 4) F (√5 – 2)²Using the (a – b)² = (a² + b² – 2ab) rule, (√5)² + (2)² – (2 x √5 x 2) 5 + 4 – 4√5 = 9 – 4√5
- [BMAT 2017 Section 2 Question 3](https://samiqamar.com/bmat-2017-section-2-question-3/): Below are four statements about electromagnetic waves.1 Microwaves have a smaller wavelength than visible light.2 The speed of visible light in a vacuum is higher than the speed of other types of electromagnetic wave.3 Gamma rays have the largest wavelength of any electromagnetic wave.4 Radio waves are used in hospital radiography to look for broken bones.Which of the statements are correct? Answer: 3) D We need to calculate the difference in mass numbers and atomic numbers. Mass number of U = 238Sum of mass number of products Sr and Xe = 95 + 139 = 234 Atomic number of U = […]
- [BMAT 2017 Section 2 Question 2](https://samiqamar.com/bmat-2017-section-2-question-2/): The diagram shows an electrolysis experiment. Which reaction occurs at the anode and which reaction occurs at the cathode for this experiment? Answer: 2) E You must first know what anodes and cathodes are. The anode which is made out of copper, will form positive copper ions. So the reaction at the anode would be:Cu → Cu²⁺ + 2e⁻ These positive copper ions will then travel to the cathode and form copper atoms. The reaction would be:Cu²⁺ + 2e⁻ → Cu
- [BMAT 2017 Section 2 Question 1](https://samiqamar.com/bmat-2017-section-2-question-1/): The diagram shows a section through part of a healthy human. Which row in the table shows the correct secretions from P, Q and R? Answer: 1) A P is the gall bladder which secretes only bile. Q is the stomach. In the stomach, proteins are broken down. So proteases must be secreted. Also, hydrochloric acid is also secreted. This means that it has a high hydrogen ion (H⁺) concentration. R is the pancreas which secretes all of the three enzymes: protease, lipase and amylase. Also, the pancreas secretes insulin to control blood glucose concentrations. So A is the answer
- [BMAT 2016 Section 2 Question 27](https://samiqamar.com/bmat-2016-section-2-question-27/): Light travels through glass at a speed which is 2/3 of its speed through air.Light travels through water at a speed which is 3/4 of its speed through air.A ray of light has a wavelength of 360 nm when travelling through water.What is the wavelength of this ray of light when travelling through glass? Answer: 27) C REMEMBER: From the equation c = ƒ x λ, we know speed is directly proportional to wavelength. Speed of light in glass is 2/3 that of speed of light in air.Hence, wavelength of light in glass will also be 2/3 that of wavelength of […]
- [BMAT 2016 Section 2 Question 26](https://samiqamar.com/bmat-2016-section-2-question-26/): The gases X and Y react with each other to produce gas Z according to the equation: 2X(g) + Y(g) → 2Z(g) 100 cm3 of X was mixed with 10 cm3 of Y, in a freely moving gas syringe sealed with a rubber cap. The reaction went to completion. All volumes were measured at the same temperature and pressure. What is the final volume of gas in the syringe? Answer: 26) D From the equation given, amount of gas X used will be equal to the amount of Z produced. Since the reaction occurred in a tightly sealed syringe under exclusion […]
- [BMAT 2016 Section 2 Question 25](https://samiqamar.com/bmat-2016-section-2-question-25/): An experiment was carried out to investigate a gene for coat colour in mice. The diagram shows the results of three crosses between different mice, producing three different families, P, Q and R. What is the maximum possible number of heterozygous mice shown in the diagram? Answer: 25) H In family P, a grey mouse was mated with a white mouse. Since all 4 offsprings were grey, we can conclude that the white coat must be recessive. Therefore, all of the grey mice can be heterozygous. Since there are 12 mice in the diagram, all of them could potentially be heterozygous. […]
- [BMAT 2016 Section 2 Question 24](https://samiqamar.com/bmat-2016-section-2-question-24/): Some blood is found at a crime scene. The police know that it belongs to the one criminal involved. A person’s red blood cells can have type A antigens, type B antigens, both types or neithertype.In a population:45% of people have type A antigens but not type B9% of people have type B antigens but not type A43% of people have neither type of antigen3% of people have both types of antigenAn antibody test shows that there are type B antigens present in the red blood cells at the crime scene. What is the probability that the criminal’s red blood cells […]
- [BMAT 2016 Section 2 Question 23](https://samiqamar.com/bmat-2016-section-2-question-23/): An object that has a weight of 15 N on Earth is taken to a planet where it has a weight of 3.0 N.The planet has no atmosphere. Which line in the table correctly shows the mass of the object on the planet, and the kinetic energy it gains after falling from rest near the surface of the planet through a vertical distance of 10 m? Answer: 23) E No matter which planet you take the object to, the MASS will remain the same as it is on Earth.Mass of object on Earth = 15N/10 = 1.5 kg Kinetic energy = […]
- [BMAT 2016 Section 2 Question 22](https://samiqamar.com/bmat-2016-section-2-question-22/): Calcium carbonate reacts with hydrochloric acid. The reaction gives off carbon dioxide gas. Line X on the graph shows the volume of carbon dioxide formed against time when 100 cm3 of 1.0 mol dm–3 of hydrochloric acid reacts with calcium carbonate chips at C.20° There was an excess of calcium carbonate chips.CaCO3 + 2HCl → CaCl2 + CO2 + H2O(l)Which line best represents the volume of carbon dioxide formed against time when the reaction is repeated with 50 cm3 of 2.0 mol dm–3 of hydrochloric acid reacting with excess calcium carbonate chips at C? Answer: 22) B A higher concentration of […]
- [BMAT 2016 Section 2 Question 21](https://samiqamar.com/bmat-2016-section-2-question-21/): Which statements describe a role of mitosis?1 asexual reproduction2 growth of a cell3 repair of cells4 stem cell division Answer: 21) A 1 – mitosis does not involve a mate. So 1 is correct 2 – mitosis involves replication of cells not growth of cell. 2 is wrong 3 – mitosis only involves replication of cells not repair of cells. 3 is wrong 4 – all cells except gametes undergo mitosis, meaning that stem cells also undergo mitosis. 4 is correct. Only statement 1 and 4 are correct. So A is the correct answer.
- [BMAT 2016 Section 2 Question 20](https://samiqamar.com/bmat-2016-section-2-question-20/): Rearrange the formula = a/b=c/d+e/f e to make f the subject? Answer: 20) C a = c + eb d f Let us first solve the right hand side (RHS). c + ed f cf + eddf a = cf + edb df adf = b (cf + ed) adf = bcf + bed adf – bcf = bedf (ad – bc) = bed f = bdead – bc
- [BMAT 2016 Section 2 Question 19](https://samiqamar.com/bmat-2016-section-2-question-19/): A defibrillator provides an electric shock to a heart to restore its normal rhythm. The energy to do this is 125 J, at a steady voltage of 500 V, for a time of 10 milliseconds. What is the current during this process? Answer: 19) D Power = Energy/time Time = 10 milliseconds = 0.01 secondsEnergy = 125J Power = 125/0.01 = 12500 Watts We know the voltage = 500V and that Power = Current x voltageCurrent = Power ÷ VoltageCurrent = 12500 ÷ 500 = 25 A
- [BMAT 2016 Section 2 Question 18](https://samiqamar.com/bmat-2016-section-2-question-18/): What volume of a 0.10 mol dm–3 solution of NaOH is needed to neutralise 30 cm3 of a 0.20 mol dm–3 aqueous solution of a diprotic acid? Answer: 18) C Firstly, we need to know what a diprotic acid is. A diprotic acid is an acid that can donate two protons per molecule to an aqueous solution.We know the acid can donate 2 protons. We know NaOH is only able to accept 1 proton. So we need twice the volume of NaOH to neutralise the acid. We know that the concentration of NaOH is half that of the acid. In order […]
- [BMAT 2016 Section 2 Question 17](https://samiqamar.com/bmat-2016-section-2-question-17/): Which of the following statements could describe the result of a single mutation of a gene coding for a protease enzyme in a fertilised human egg cell?1 A new allele is formed coding for a protease enzyme that works more efficiently.2 A new allele is formed coding for a protease enzyme that works less efficiently.3 A new allele is formed coding for a non-functional protein that has no effect on the cell.4 A new allele is formed coding for a non-functional protein that has a negative effect on the cell. Answer: 17) G Statements 1 and 4 are termed gain of […]
- [BMAT 2016 Section 2 Question 16](https://samiqamar.com/bmat-2016-section-2-question-16/): The diagram shows a quadrilateral PQRS. Given that θtan,4/3. what is the area of the quadrilateral PQRS Answer: 16) C Split the trapezium into a triangle and a square. Draw a perpendicular line from PS to the point Q.Let the point on PS be A. So AQ is perpendicular to PS. Since QR will be equal to AS, AS = 5cmPA + AS = PSPA = PS – ASPA = 11 – 5 = 6cm tanθ = ⁴⁄₃ and tanθ = AQ / PA = AQ/6 tanθ = ⁴⁄₃ = AQ / 6²⁴⁄₃ = AQAQ = 8cm AQ = RS = […]
- [BMAT 2016 Section 2 Question 15](https://samiqamar.com/bmat-2016-section-2-question-15/): The diagram represents a satellite communication link between two points on Earth. Thedistances between the transmitting station, the satellite and the receiving station are shown.The frequency of the waves used for the link can be taken as 1.5 × 1010 Hz, and the speed oflight as 3.0 × 108 m / s.What type of wave is used in such a link, and what is the time delay between a signal beingtransmitted and then being received at the receiving station? Answer: 15) D Let us start by calculating the time delay first. Total distance = 45000 + 45000 = 90000 Km Speed […]
- [BMAT 2016 Section 2 Question 14](https://samiqamar.com/bmat-2016-section-2-question-14/): Identify the correct products of electrolysis of the following electrolytes Answer: 14) C A important aspect you have to take into consideration before answering this question is the terms being used in the electrolytes: ‘aqueous’ and ‘molten’ Aqueous means that it is in solution water, meaning it will react with water. Molten means the pure compound is being electrolysed. A – The compound is aqueous. Calcium is more reactive than hydrogen, meaning hydrogen would be the product at the cathode  B – Oxygen would be the product at the anode C – This is correct. Potassium is more reactive than hydrogen, […]
- [BMAT 2016 Section 2 Question 13](https://samiqamar.com/bmat-2016-section-2-question-13/): Which of the following molecules are involved in both aerobic and anaerobic respiration in ahealthy human?1 carbon dioxide2 glucose3 lactic acid Answer: 13) B 1 – carbon dioxide is produced as a waste product of aerobic respiration but is not involved in anaerobic respiration. So this is incorrect.  2 – glucose is produced in both types of respiration.  3 – lactic acid is produced as a waste product in anaerobic respiration but is not involved in aerobic respiration.  Hence, only 2 is correct which corresponds to option B. 
- [BMAT 2016 Section 2 Question 12](https://samiqamar.com/bmat-2016-section-2-question-12/): The diagram represents the circular cross-section of an artery with external diameter d of 1.6 cm. The thickness t of the artery wall is 1 mm. What is the internal cross-sectional area of the artery (shaded in the diagram)? Answer: 12) D There are two circles in this diagram. The grey circle and the outer circle. In order to get the diameter of the grey circle, we need to subtract 2mm (2 x 1mm) from 1.6 cm. Diameter of grey circle = 1.6 – 0.2mm = 1.4cm Radius = 0.7cm = 7mm Area of a circle = πr² Area of internal cross […]
- [BMAT 2016 Section 2 Question 11](https://samiqamar.com/bmat-2016-section-2-question-11/): An AC voltage is induced in a coil of wire when it is rotated in a magnetic field. This voltage can be displayed on the screen of an instrument called an oscilloscope, which shows the variation of the induced voltage on the y-axis plotted against time on the x-axis. The oscilloscope trace below is the result of rotating a coil at a constant speed in a uniform magnetic field. Which one of the following traces would result from rotating the coil at a faster constant speed, whilst keeping all other conditions unchanged? (The scales on the axes do not change. Answer: […]
- [BMAT 2016 Section 2 Question 10](https://samiqamar.com/bmat-2016-section-2-question-10/): Mohr’s Salt is a common laboratory reagent. Use the information of the most abundantisotopes below to calculate the formula mass, Mr , of the hydrated salt.Formula of Mohr’s Salt: (NH4)2Fe(SO4)2.6H2OMost abundant isotopes: ,H, N, O, S, Fe Answer: 10) F This is a simple addition question. No. of N = 2Mass number of N = 14Total mass of N = (14 x 2) = 28 No. of H = 20Mass number of H = 1Total mass of H = (20 x 1) = 20 No. of Fe = 1Mass number of Fe = 56Total mass of Fe = (56 x 1) […]
- [BMAT 2016 Section 2 Question 9](https://samiqamar.com/bmat-2016-section-2-question-9/): The following statements are features of an enzyme from a healthy human.1 It works at an optimum pH below 4.2 It digests a substrate into amino acids.3 It works at an optimum temperature of approximately C.37°Which enzyme has these features? Answer: 9) F Sentence 2 helps us to identify the type of enzyme. Amylase breaks starch into glucoseLipase breaks lipids into fatty acids and glycerolProteases breaks proteins into amino acidsHence, the enzyme is protease. This rules out options A, B, C and D. Sentence 1 helps us to know that pH is acidic. We know that the stomach secrets hydrochloric acid. […]
- [BMAT 2016 Section 2 Question 8](https://samiqamar.com/bmat-2016-section-2-question-8/): The mean mass of a group of N people is 75 kg.Jim, Karen and Leroy join this group, without anyone leaving; the new mean mass is 78 kg.The mean mass of Jim, Karen and Leroy is 90 kg.What is the value of N? Answer: 8) B Average mass of first group = 75 kgTotal mass if group of N people = 75 x N = 75N Three people join the group. Total number of people now = N + 3Average mass now = 78Total mass now = 78 (N + 3) = 78N + 234 Average mass of the three people […]
- [BMAT 2016 Section 2 Question 7](https://samiqamar.com/bmat-2016-section-2-question-7/): Nickel has an atomic number of 28. The mass numbers of four of its isotopes are 58, 60, 61and 62.Below are three statements about these isotopes of nickel.1 All of them have the same chemical properties.2 All of them have nuclei containing 28 protons.3 One of them has a nucleus that contains 62 neutrons.Which statement(s) is/are correct? Answer: 6) E A – calcium carbonate is the solute whilst water is the solvent. Water can evaporate, leaving the solute behind in the container. B – pentane and octane have different number of carbon atoms, and hence different chain lengths. Octane has 8 […]
- [BMAT 2016 Section 2 Question 6](https://samiqamar.com/bmat-2016-section-2-question-6/): Which one of the following mixtures could not be separated using the technique given? Answer: 5) B It is easy to identify W as a chromosome. This rules out options D, E and F. X and Y are substances which cut out a length of DNA. Therefore, they must be restriction enzymes. Z is a substances which fuses DNA strands. Only ligase enzyme is capable of doing so.Even if you did not know the theory, the answer could have been obtained by process of elimination. We know the function of X and Y is the same so they must also be […]
- [BMAT 2016 Section 2 Question 5](https://samiqamar.com/bmat-2016-section-2-question-5/): The diagram shows some of the stages of how a length of DNA can be removed from one organism and introduced into another organism. Which row is correct? Answer: 4) A The only thing that can determine whether two lines are parallel is if they have the same gradient.  The line that crosses the two points will have the gradient: m = (y2 – y1) / (x2 – x1) = (9 – 3) / [6 – (-3)] = 6 / 9 = 2 / 3 Using y = mx + c, the only equation in the options which has the gradient […]
- [BMAT 2016 Section 2 Question 4](https://samiqamar.com/bmat-2016-section-2-question-4/): A straight line passes through the points P ( 3,− 3) and Q (6, 9). Which one of the following is an equation of a straight line which is parallel to PQ? Answer: 3) D Mass of cylinder with 250cm³ = 170gThen, the mass is increased to 470g when the object is submerged.Mass of object = 470-170 = 300g. When two objects are placed in the measuring cylinder, volume increases from 250 to 350.Volume of two objects = 350-250 = 100cm³Volume of 1 object = 100/2 = 50cm³Density = Mass/Volume = (300/50) g/cm³
- [BMAT 2016 Section 2 Question 3](https://samiqamar.com/bmat-2016-section-2-question-3/): A student carries out an experiment to determine the density of the material from which two identical solid objects are made. She uses a balance and a measuring cylinder containing a fixed volume of liquid. The diagrams show different stages of her experiment, with some of the readings on the balance and some on the measuring cylinder. Which calculation should be used to determine the density of the material from which the objects are made? Answer: 3) D Mass of cylinder with 250cm³ = 170gThen, the mass is increased to 470g when the object is submerged.Mass of object = 470-170 = […]
- [BMAT 2016 Section 2 Question 2](https://samiqamar.com/bmat-2016-section-2-question-2/): Element X has the electronic structure 2, 8, 3.Which of the following statements about this element are correct?1 The element is in Group 12, Period 3 of the Periodic Table.2 The element reacts with oxygen to form a compound with the formula X2 O3.3 The element reacts with bromine to form a compound with the formula XBr 3.4 The atomic number of the element is 13.5 The element is an alkali metal. Answer: 2) F 1 – there is no element in group 12 and period 3 2 – X has 3 electron in its outermost shell and so has a […]
- [BMAT 2016 Section 2 Question 1](https://samiqamar.com/bmat-2016-section-2-question-1/): The diagram shows a kidney and its associated vessels from a healthy individual. Which row correctly identifies the vessels along with the concentration of urea they contain. Answer: 1) D This is rather a simple question. The two large blood vessels are the vena cava and the aorta. We can distinguish between 1 and 2 by their lumen size. The blood vessel with the larger lumen is the vena cava and the one with the smaller lumen is the aorta.Therefore, 1 is the vena cava and 2 is the aorta. The blood vessel coming out of the aorta (4) is the […]
- [BMAT 2015 Section 2 Question 27](https://samiqamar.com/bmat-2015-section-2-question-27/): Consider the following three statements:1 A mass of 4.0 kg requires a resultant force of 5.0 N to act on it in order toaccelerate it at 1.25 m / s 2.2 A wave of frequency 4.0 Hz travelling at a speed of 5.0 m / s has a wavelength of1.25 m.3 A voltage of 4.0 V applied across a 5.0 Ω resistor causes a current of 1.25 A toflow.Which statement(s) is / are true? Answer: 27) D 1 – Force = mass x acceleration (F = ma)Force required = 4kg x 1.25 = 5N.Hence statement 1 is correct. 2 – Speed […]
- [BMAT 2015 Section 2 Question 26](https://samiqamar.com/bmat-2015-section-2-question-26/): The equation for the complete combustion of methane is:CH4(g) + 2O2(g) CO2 (g) +2H2O (g)If 1.60 g of methane were completely burned in 8.00 g of oxygen (an excess) to produce 4.40 gof carbon dioxide, what mass of oxygen is left unreacted?(Ar: H = 1 ; C = 12 ; O = 16) Answer: 26) B The main formula that needs to be used is: moles = (mass ÷ Mr) n = m ÷ Mr Mr of CH₄ = 12 + (1 x 4) = 16Mr of CO₂ = 12 + (16 x 2) = 44Mr of O₂ = 16 x […]
- [BMAT 2015 Section 2 Question 25](https://samiqamar.com/bmat-2015-section-2-question-25/): The sex of a species of fruit fly is determined by the number of X chromosomes relative to the number of non-sex chromosomes (A) in a cell. This is called the X : A ratio. A fruit fly will be male if X : A = 0.5 : 1 and female if X : A = 1 : 1. The Y chromosome contains genes necessary for making sperm. Which row of the table correctly shows the sex of the five fruit flies with different numbers of these chromosomes? Answer: 25) G For this question, it is important to ignore the mention […]
- [BMAT 2015 Section 2 Question 24](https://samiqamar.com/bmat-2015-section-2-question-24/): Simplify:2x + 3     +      2x – 3 -2 2x – 3             2x + 3 Answer: 24) D Let us first solve the first part of the problem 2x + 3 + 2x – 32x – 3 2x + 3 (2x + 3)² + (2x – 3)²(2x – 3) (2x + 3) (4x² + 6x + 9) + (4x² – 6x + 9)4x² – 9 8x² + 184x² – 9 Let us now solve the second part of the problem 8x² + 18 – 24x² – 9 1 8x² + 18 – 8x² – 184x² […]
- [BMAT 2015 Section 2 Question 23](https://samiqamar.com/bmat-2015-section-2-question-23/): A car is being driven at 20 m / s when the driver sees a child run into the road. The driver’s usual reaction time is 0.70 s, but this is doubled because the driver is tired. Once the driver applies the brakes, the car is brought uniformly to rest in a further 3.3 s. What is the total distance travelled by the car between when the driver first sees the child to when the car stops? Answer: 23) D We know the initial velocity (u) = 20m/s Final velocity (v) = 0 m/s (driver comes to a rest) It is […]
- [BMAT 2015 Section 2 Question 22](https://samiqamar.com/bmat-2015-section-2-question-22/): Which of the following have the same electron arrangement? Answer: 2) C In order to answer the question, we only need to find out how many electrons each of the species have in their atom. The (₁₇ Cl⁻) has 17 protons. Since it has a charge of (-1), it must have one more electron than proton.Therefore it has 18 electrons. The (₁₇ Cl⁺) has 17 protons. Since it has a charge of (+1), it must have one more proton than electron.Therefore it has 16 electrons. The (₁₈ Ar) has 18 protons. Since it has no charge, it must have equal number […]
- [BMAT 2015 Section 2 Question 21](https://samiqamar.com/bmat-2015-section-2-question-21/): Mitochondria are the site of aerobic respiration in animal cells. A theory of the evolution of animal cells states that these mitochondria may once have been aerobic bacteria that were taken into the cytoplasm of a cell in an early ancestor of the animals, allowing the cells to gain the ability to respire using oxygen. Assuming this theory is correct, which of the following statements are true of these aerobic bacteria and human white blood cells?1 The structure of their DNA is a double helix.2 They would both possess a cell wall.3 They would both possess a nucleus.4 They would both […]
- [BMAT 2015 Section 2 Question 20](https://samiqamar.com/bmat-2015-section-2-question-20/): A class of݊ n pupils takes a spelling test. Their mean score for the test is݉ m. Another pupil takes the test and scores݊ n. When this pupil’s result is included with the other results it is found that the mean has decreased by 2. Which equation below gives the correct expression for݊ n in terms of݉ m? Answer: 20) D Number of pupils in first group = nMean of first group = mTotal sum of scores for the first group = nm A new score of another pupil is added.Total number of pupils now = n + 1Mean score now […]
- [BMAT 2015 Section 2 Question 19](https://samiqamar.com/bmat-2015-section-2-question-19/): Part of a radioactivity decay series is represented below. It involves the change of a nucleus M into a nucleus N by the emission of a beta-particle, followed by a further change into a nucleus Q by the emission of an alpha particle. Four quantities V, W, X and Y are shown What are the expressions for X and Y? Answer: 19) G When a ß-paricle is emitted, an electron is emitted. This means that the proton number (atomic number) increases by 1. The mass number DOES NOT change when a ß-particle is emitted.Therefore, X = W+1 When an α-particle is […]
- [BMAT 2015 Section 2 Question 18](https://samiqamar.com/bmat-2015-section-2-question-18/): The reaction between the gases S and T occurs according to the following equation. Which statement about this reaction is correct? Answer: 18) C A – a catalyst would increase the rate of reaction rather than decrease it. A is wrong B – This is not true as gases have larger surface area than solid and we know that the higher the surface area, the higher the rate of reaction. B is wrong C – this is true because activation energy is the energy required to start a reaction. If the activation energy is high, there will be lesser successful collisions. […]
- [BMAT 2015 Section 2 Question 17](https://samiqamar.com/bmat-2015-section-2-question-17/): The diagram shows part of the carbon cycle. Which row shows the numbered processes that use digestive or respiratory enzymes? Answer: 17) H In order to convert carbon in plants into carbon in animals, animals need to use digestive enzymes. So process 2 would use digestive enzymes. Same principle applies to process 3. Decomposers digest carbon in animals. So process 3 uses digestive enzymes.During respiration, carbon in decomposers is converted to carbon dioxide in air. So 4 uses respiratory enzymes. In order to convert carbon dioxide in air to carbon in plants, plants use photosynthesises. This neither involves digestive enzymes nor […]
- [BMAT 2015 Section 2 Question 16](https://samiqamar.com/bmat-2015-section-2-question-16/): A city football club collected money for charity at all of its matches for a year. At the end of the year the total collected was divided among three charities, A, B and C, in the ratio 1:2/3:4/5. Charity C received £3 000. What was the total amount collected for charity during the year? Answer: 16) E Ratio = 1: 2/3 : 4/5In order to find 1, we need to use Charity C’s value 4/5 = 3000(We can make the equation so we have 1 on the left hand side)4/5 x 1 = 30001 = (3000 x 5)/4 = £3750So charity […]
- [BMAT 2015 Section 2 Question 15](https://samiqamar.com/bmat-2015-section-2-question-15/): The diagram shows the only four forces acting on a model aircraft of mass 2.0 kg whilst flying. Which line in the table states the horizontal and vertical accelerations of the aircraft at this instant? Answer: 15) A ∑F (horizontal direction) = 50-40 = 10 N to the rightWe know the mass = 2kgForce = mass x acceleration Acceleration = force/mass = 10/2 = 5.0m/s2 to the right  ∑F (vertical direction) = 25N-20N = 5N upwardsAcceleration = force/mass = 5/2 = 2.5 m/s2 upwards Hence, the answer is A
- [IMAT Past Papers Free Download pdfs (2011 to 2025)](https://samiqamar.com/imat-past-papers-free-download-pdfs/): Here are the IMAT past papers FREE download pdfs with solution keys. Although getting ready for the IMAT test is difficult, with the correct tools you may maximize your study time and increase your confidence. IMAT previous papers are among the best tools you could employ. I’ll walk you through where to locate free IMAT past papers PDFs, how to make best use of them, and some pointers on how to maximize these practice tests in this post Here are the IMAT Past Papers: Sometimes it can be difficult to find consistent IMAT past papers. I have collected a list of all […]
- [IMAT 2026 Syllabus](https://samiqamar.com/imat-2026-syllabus/): Want IMAT 2026 syllabus? I’ll cover everything you need to know about the IMAT 2026 syllabus in this post. I know you are getting ready for the IMAT in 2026, and the first step in your preparation should be to review the IMAT curriculum. Without one, it will be difficult to categorize what you should and shouldn’t be studying. I got you. Before wasting your time, let me provide you with all the details. Please take time to read it carefully, as I will address many of your questions in addition to sharing the syllabus. If you want to watch, the […]
- [Regional Scholarships in Italy Fully Funded 2026](https://samiqamar.com/regional-scholarships-in-italy/): There are a range of fully funded regional scholarships in italy designed to support international students pursuing higher education. These scholarships are primarily need based in the first year, with subsequent renewals considering both merit and financial need. Each Italian region administers its own scholarship program, providing benefits such as tuition fee waivers, free accommodation, meals, and additional financial assistance. Below is an overview of some prominent regional scholarships available in Italy: Regional Scholarships in italy 1. LazioDisco Regional Scholarship LazioDisco offers scholarships to students who are enrolled in universities within the Lazio region.The scholarship covers tuition fees, accommodation, and provides […]
- [My First Time in the Operating Theatre - 5 Hour Cervical Spine Surgery](https://samiqamar.com/my-first-time-in-the-operating-theatre-a-5-hour-cervical-spine-surgery/): Hey friends, welcome back to the blog. If you’ve been following me for a while, you know I usually talk about the IMAT exam, registration processes, and how to get into medical school in Italy. But today, I want to switch gears. I’m currently a 3rd-year medical student, and we are finally moving from textbooks to the real world. I recently started my clinical rotations, and I want to take you with me inside the hospital. Specifically, I want to talk about my very first experience inside the Operating Theatre (OT). It was a 5-hour long surgery for a Cervical Vertebrae […]
- [2025 IMAT Rankings and Cut Offs](https://samiqamar.com/2025-imat-rankings-and-cut-offs/): 2025 IMAT rankings and cut offs for all universities are going to be published on 13th October 2025, and most universities are going to stand at 65+, but some will get the merit around 55-60, most probably those universities which are located in the North. But the detailed tables with all the cutoffs will be mentioned below. If you want to see the detailed ranking of:IMAT 2024 for both Europeans and Non Europeans with number of seats at each university click hereIMAT 2023 for both Europeans and Non Europeans with number of seats at each university click here IMAT 2025 Results […]
- [IMAT 2025 Ranking List (Anonymous)](https://samiqamar.com/imat-2025-ranking-list/): Here’s the IMAT 2025 Ranking List (anonymous). This list won’t tell you you the exact merit, if you remember your barcode number then you can get your result but the offcial result with you name will publish in your portal on 6 october and then the final merit lists with names and seats will publish on 13 october. Download Anonymous Ranking List from below.
- [IMAT 2025 Past Paper with Key](https://samiqamar.com/imat-2025-past-paper-with-key/): Heres the IMAT 2025 Paper that took place on 17th Spetember 2025 is here. Download from here
- [IMAT 2025 SEATS ARE FILLING FAST! (email authorities)](https://samiqamar.com/imat-2025-seats-are-filling-fast/): Hey guys, Sami here 👋 as I mentioned in the video, seats for IMAT 2025 are already fully booked in India, Pakistan, Brazil, Turkey, and Dubai. They are not adding new seats for now, but here’s the 3 authorities I mentioned in the video to email: 1. Selexi (ilimiotest): https://admission-imat.ilmiotest.it/support 2. Cineca: https://accessoprogrammato.cineca.it/support.php 3. Selexi (own website) https://www.selexi.it/contatti 4. Recrytera https://recrytera.com/imat2025/#1755848651458-3c2038f2-9168 If you don’t understand, watch below video from 10:00 minutes onward (I’ve explained on screen).
- [IMAT 2025 Updates - Registration, Centers, Syllabus](https://samiqamar.com/imat-2025-registration-centers-syllabus-preparation/): Hey friends 👋Big news IMAT 2025 registration is officially going to start from 26th August 2025. If you’re planning to study medicine in Italy, this is your moment.I know a lot of you have been DM-ing me asking “Sami, when can we finally register?” I made the short video telliing you when it will open, and I had clearly said last week of August or Start of September (see my prediction is always right:) spam W sami)Let’s go through dates and deadline, seats, centers, syllabus, how to register, what you need to prepare, and how to make the most of the […]
- [IMAT Preparation Course You’ll Ever Need (500+ Lectures + 6 Mocks)](https://samiqamar.com/imat-preparation-course/): Hey friends 👋 So I’ve been getting a lot of questions lately like-“Sami, is there one course where everything is organized for IMAT?”Like lectures, mocks, past papers, quizzes… all in one place? The answer is: yes. I’ve made it. This is the IMAT crash course I wish I had when I was preparing.Built from scratch. Organized in an LMS. Affordable. Focused. And no BS. Whether you’re just starting out or already halfway through your prep, this course is built to give you real structure, with daily lectures, real IMAT-style practice, and full mock exams that simulate the actual test. Let me […]
- [IMAT 2025 Syllabus: What You Actually Need to Study](https://samiqamar.com/imat-2025-syllabus/): IMAT 2025 syllabus breakdown with free PDF. Learn what to study for biology, chemistry, logical Reasoning, Physics, Maths and General Knowledge. Hey, I’m Sami Qamar and if you’re preparing for IMAT 2025, you’re probably wondering…What exactly should I study?Where can I find the syllabus?And most importantly: How do I cover everything without wasting time on useless stuff? Let’s break it down together. IMAT 2025 Syllabus PDF Let’s start with what you’re really here for the official syllabus. 👉 Download the Official IMAT 2025 Syllabus PDF here (I’ll update the link as soon as it’s officially released by MUR the Italian Ministry […]
- [How to Start IMAT 2025 Preparation](https://samiqamar.com/how-to-start-imat-2025-preparation/): To kickstart your IMAT 2025 preparation, here’s a clear path with the best resources for each key area. Here’s how you can make the most of each: Best IMAT Books: Pick books that cover the essentials without overloading. Stick to those that focus on IMAT-style questions, and avoid lengthy explanations. Watch this video containing the best IMAT preparation books with free pdfs. Best IMAT Lectures Lectures are essential for clarity. I recommend watching targeted ones on tricky topics. Watch this video containing the best IMAT preparation FREE lecture resources. IMAT Past Papers: Past papers are your best friend. Go over them […]
- [2024 IMAT Rankings and Cut Offs](https://samiqamar.com/2024-imat-rankings-and-cut-offs/): 2024 IMAT rankings and cut-offs for all universities are going to be published on 10th October 2024, and most universities are going to stand at 70+, but some will get the merit around 60, most probably those universities which are located in the North. But the detailed tables with all the cutoffs will be mentioned below. If you want to see the detailed ranking of IMAT 2023 for both Europeans and Non Europeans with number of seats at each university click here IMAT 2024 Results Summary: IMAT 2024: Total Number of Seats Medicine: Dentistry: IMAT 2024 Non-Eu Ranking list: (Updating CutOffs […]
- [IMAT Physics Formulas for Quick Revision](https://samiqamar.com/imat-physics-formulas-for-quick-revision/): Preparing for the IMAT exam can be hard, especially when it comes to physics. That’s why I’ve compiled a list of the most important IMAT physics formulas to help you with quick revision. This list is meant to provide you a clear and quick review whether your goal is a refresher or just to make sure you have all the important formulas committed. Why Prefer IMAT Physics Formulas? Although IMAT physics section is not that big but now due to competetion Your whole score may be much influenced by the IMAT physics part. Knowing the fundamental formulas by memory will help […]
- [How to Prepare for IMAT Exam](https://samiqamar.com/how-to-prepare-for-imat-exam/): Let’s see how to prepare for IMAT exam? Although preparing for the IMAT test seems like a large chore, with the correct strategy you will be able to manage it easily. This is a basic guide to enable your efficient preparation. For Comprehensive guide you can watch below video This video will give you a complete road map to prepare for IMAT exam and achieve 50+ marks Make Planar First, make a daily plan noting the subjects you should study every day. Schedule time for reviewing your notes, reading your textbooks, and working through questions. As much as you can, follow […]
- [5 Benefits of Listening to Music While Studying](https://samiqamar.com/5-benefits-of-listening-to-music-while-studying/): Studying can be a challenge, especially when you’re trying to stay focused and motivated. One simple way to make your study sessions more effective is by listening to music. But what exactly are the benefits of listening to music while studying? Research shows that the right kind of music can help you concentrate, relax, feel motivated, improve memory, and make studying more enjoyable. Let’s explore how music can boost your academic performance and what types of music work best for different study needs. “Listening to music while studying can transform tedious revision into an enjoyable experience, making it easier to stick […]
- [How to Use Anki Flashcards for Effective Active Recall](https://samiqamar.com/active-recall-with-anki-flashcards/): Wondering how to increase your study sessions with active recall with Anki flashcards? Don’t worry—I’ve got you. Let’s dive into it. Many of us believe that reading the information repeatedly until it sticks is the best way to approach our studies. What if I told you that there is a far more efficient approach to learning, including less repetition and more active involvement? Now enter active recall, a potent method that will change your study sessions—particularly when used with Anki flashcards. Active recall: Using active recall—a learning technique—, you deliberately strive to remember material without consulting your notes or textbook. You […]
- [Active Recall: The Most Effective Study Technique](https://samiqamar.com/active-recall-study-technique/): As a first-year medical student, I learned that studying effectively is crucial to success. But did you know that traditional learning methods like rereading, highlighting, and summarizing aren’t the most effective? In fact, research shows that active recall is the game changer you need to boost your memory retention and exam performance. If rereading, highlighting, and summarizing don’t produce results in your study sessions, What actually works? The most effective methods I’ve discovered are active recall and the Feynman technique. Together, they can transform your study routine into something far more efficient and rewarding. I’ve already written about the Feynman technique, […]
- [How to Study Effectively with the Feynman Technique](https://samiqamar.com/feynman-technique/): I don’t know what’s the matter with people: they don’t learn by understanding; they learn by some other way – by rote, or something. Their knowledge is so fragile! Richard Feynman Richard Feynman was a Nobel Prize-winning physicist who significantly contributed to quantum mechanics and particle physics. He also pioneered quantum computing and introduced the concept of nanotechnology. As a renowned lecturer, he taught at Cornell and Caltech. Despite his numerous accomplishments, Feynman considered himself “an ordinary person who studied hard.” He believed that with enough effort, anyone could learn even the most complex subjects, like quantum mechanics and electromagnetic fields. […]
- [Best note taking app in 2024](https://samiqamar.com/best-note-taking-app/): Note taking is one of those things we all do, but how we do it is uniquely personal. Whether it’s scribbling down a quick grocery list or meticulously transcribing meeting minutes, notes are as varied as the individuals who create them. Some prefer straightforward text with a few bullet points, while others turn their notes into colorful scrapbooks filled with doodles and images. Whatever your style, there’s an app out there that can accommodate your quirks and preferences. It might just take a bit of searching to find the perfect fit. The best and all in one app for note taking […]
- [The Best Flashcard App for Medical Students](https://samiqamar.com/the-best-flashcard-app-for-medical-students/): Let me tell you what is the best flashcard app for medical students. Anki is… Yup with powerful features like spaced repetition, cloze deletion, and image occlusion, Anki is a must-have tool for mastering anatomy, physiology, and more. Learn how this free app can revolutionize your study routine and boost your exam scores. Hey there, fellow medical students! Let me introduce you to the best flashcard app in town: Anki. Trust me, I’ve tried them all, and nothing comes close to the effectiveness of Anki when it comes to mastering complex subjects like anatomy, physiology, and biochemistry. You will love to […]
- [How Stress Kill the Grades](https://samiqamar.com/how-stress-kill-the-grades/): Stress can be a real game-changer when it comes to exams. It’s like this invisible force that sneaks up on you and messes with your focus and concentration. When you’re feeling stressed, it’s hard to think clearly and recall the information you’ve studied. It’s like your mind goes blank at the most crucial moments. And that can definitely lead to not-so-great results and all that hard work feels like it’s slipping away. Stress can also lead to poor decision-making. We may rush through questions without fully understanding them or make careless mistakes. It’s like our brains are on overdrive, and it’s […]
- [How I am Building Confidence in Medical School](https://samiqamar.com/how-i-am-building-confidence-in-medical-school/): My successful try to build confidence in medical school but let’s go into flashback, I’m not sure if it was a dream or reality, but something happened to me when I was little and it gave me a great deal of anxiety. One night, as I was sleeping in my father’s bedroom, I heard someone knocking at a small cupboard. When I opened my eyes, I saw someone wearing an all-white outfit—completely white, much like a mummy—with nothing black at all. I genuinely don’t know if it’s true or not, but that experience left me feeling extremely afraid. I didn’t go […]
- [IMAT Syllabus Explained](https://samiqamar.com/imat-syllabus-explained/): Ultimate IMAT syllabus masterclass series! If you’re gearing up for the IMAT 2024, you’re in the right place. In this blog post, I’ll explain the simplified complexities of the IMAT syllabus, providing a thorough understanding of what to expect in the exam. This masterclass series covers Biology, Chemistry, Physics, and Math, each session packed with 5+ hours of insightful content. Firstly I have simplified the syllabus for each subject into a simple table of contents, As you know what the Italian ministry publishes in PDF form is not classified according to chapters, there are just random topics mentioned. So for your […]
- [Best IMAT WhatsApp Community - IMAT nerd](https://samiqamar.com/best-imat-whatsapp-communitry-imat-nerd/): Introduction: Are you preparing for IMAT 2024? Preparing for the IMAT is a significant, best, and a supportive IMAT Whatsapp community. In this video, we introduce the IMAT WhatsApp Community, a thriving space designed to facilitate collaborative learning and comprehensive IMAT preparation. Understanding IMAT Nerd WhatsApp Community: Named the “IMAT Nerd,” this WhatsApp community boasts three dynamic groups to cater to different aspects of IMAT preparation: 1. Daily Questions Group: Access daily IMAT-related questions for consistent practice. 2. Discussion Group: Engage in real-time discussions, share problems, and collectively find solutions. 3. IMAT Notes Group: Access a treasure trove of notes and […]
- [BMAT 2021 Section 2 Question 27](https://samiqamar.com/bmat-2021-section-2-question-27/): A train is sounding its horn as it approaches a station. The engine driver hears a note of frequency f0 and of constant amplitude as the train slows down and stops next to a platform. A person standing at the end of the platform ahead of where the train stops also hears the sound produced by the horn. What happens to the amplitude and to the frequency of the sound heard by the person as the train slows down and stops? Answer: 27) F In this case, the source of sound is the train and the observer is the person. As […]
- [BMAT 2021 Section 2 Question 26](https://samiqamar.com/bmat-2021-section-2-question-26/): Calcium nitride, Ca 3N2 , reacts with water to form calcium hydroxide and molecule X. No other products are formed, and molecule X contains only nitrogen and hydrogen atoms. What is the empirical formula of X? Answer:
- [BMAT 2021 Section 2 Question 25](https://samiqamar.com/bmat-2021-section-2-question-25/): The family tree shows the inheritance of a recessive condition. Which of the following statements is/are correct?1 Individuals 1 and 2 are both heterozygous for this condition.2 Individuals 3 and 4 are both heterozygous for this condition.3 Individuals 5 and 6 each have a 50% chance of being heterozygous for this condition. Answer: 25) E Please remember that the condition is RECESSIVE. Therefore, an individual needs to be homozygous recessive to have the condition. One offspring out of the four offspring of 1 and 2 has the condition. This is only possible when both 1 and 2 are heterozygous. If even […]
- [BMAT 2021 Section 2 Question 24](https://samiqamar.com/bmat-2021-section-2-question-24/): A circle is drawn with centre (3, 5). A tangent is drawn to the circle. The tangent touches the circle at the point (6, 7). What is the gradient of this tangent to the circle? Answer:
- [BMAT 2021 Section 2 Question 22](https://samiqamar.com/bmat-2021-section-2-question-22-2/): A high-voltage dc overhead cable carries a current of 2000 A. One 20 m section of the cable has a mass of 120 kg. This cable section is supported so that it is horizontal, with the current in the direction from west to east. The Earth’s magnetic field in this location is 5.0 × 10 –5 T due north and is horizontal. What is the magnitude of the total force exerted by the support on this section of cable? (gravitational field strength = 10 N kg –1) Answer: 23) D F = BilsineF = force = ?B = magnetic field = […]
- [BMAT 2021 Section 2 Question 22](https://samiqamar.com/bmat-2021-section-2-question-22/): Three elements from Group 1 and three elements from Group 17 are given in the table with their relative atomic masses.Group 1 Group 17lithium (7) fluorine (19)sodium (23) chlorine (35.5)potassium (39) bromine (80)Of the elements in the table, one mole of the most reactive Group 1 element is reacted with one mole of the Group 17 element with the highest boiling point. What is the maximum mass of the salt formed by this reaction? Answer: 22) D Out of the Group 1 elements shown, potassium is the most reactive.Out of the group 17 elements shown, bromine has the highest boiling point.PotassiumMoles […]
- [BMAT 2021 Section 2 Question 21](https://samiqamar.com/bmat-2021-section-2-question-21/): A nucleotide consists of three different sub-units. A section of double-stranded DNA consists of 600 of these sub-units in total. Of these sub-units, 28 are the base adenine. What percentage of the sub-units of this section of DNA is guanine? (Assume no mutations.) Answer: 21) C The piece of DNA has 600 sub-units and 28 are adenines. Therefore, nucleotides containing adenine283 subunits make up one nucleotide. Nucleotides containing adenine will have a total of = 28 x 384 sub-unitsRemaining sub-units 600 – 84 = 516Adenine binds with thymine, so there will be equal amounts of both. There are 28 Adenine nucleotides, […]
- [BMAT 2021 Section 2 Question 20](https://samiqamar.com/bmat-2021-section-2-question-20/): The area of triangle PQR is 42 cm 2 .The length of PR is 8 cm.cos ș = 3/4What is the length of QR, in cm? Answer:
- [BMAT 2021 Section 2 Question 19](https://samiqamar.com/bmat-2021-section-2-question-19/): An electric shower heater is rated at 8.4 kW and raises the temperature of flowing water from 16 °C to 36 °C. What is the mass of water passing through the shower in a time of 1.0 second? (specific heat capacity of water = 4200 J kg –1 °C–1 ; assume that all the electrical energy is used to raise the temperature of the water; assume no heat is transferred to the surroundings) Answer: 19) E Q = mcATQ is basically the amount of heat lost or gained (in joules).We have been given the power as 8.4 kW = 8400 WPower […]
- [BMAT 2021 Section 2 Question 18](https://samiqamar.com/bmat-2021-section-2-question-18/): Dry air can be cooled and then fractionally distilled to separate its components. What is the minimum volume of dry air needed to prepare a 25 dm3 sample of oxygen using this method? (Assume that all volumes are measured at room temperature and pressure, and that all gases are ideal.) Answer: 18) D Air has 21% oxygen. We need to prepare 25 dm3 of oxygen.So we know that 21% = 25 dm31% = 25/21100% = 25/21x 100 = 119 dm3
- [BMAT 2021 Section 2 Question 17](https://samiqamar.com/bmat-2021-section-2-question-17/): A scientist studying the blue-ringed octopus made the following observations. Answer: 17) C Temperature is an ABIOTIC factor, not a biotic factor that affects where the octopus can live. So 1 is wrong.The relationship between bacteria and the octopus is in fact mutualism. Both benefit from each other. Bacteria survive in the octopus’ salivary glands and the octopus, in turn, uses the toxin produced by the bacteria to catch prey. So 2 is correct.Populations are groups of organisms of the same species living in the same area at the same time. Therefore, crabs, shrimp and fish cannot make up a population. […]
- [BMAT 2021 Section 2 Question 16](https://samiqamar.com/bmat-2021-section-2-question-16/): The line with equation y = – 2 x + 1 is reflected in the line with equation x = 2 Which of the following is the equation of the new line? Answer:
- [BMAT 2021 Section 2 Question 15](https://samiqamar.com/bmat-2021-section-2-question-15/): An escalator between two floors in a shop consists of steps that are each 30 cm high and 40 cm deep.There are 20 steps between the floors.The escalator moves a person of mass 80 kg upwards from the lower floor to the upper floor.How much work is done by the escalator on the person?(gravitational field strength = 10 N kg–1) Answer: 15) D Weight of person = mass x gravitational field strength = 80 x 10 = 800 NHeight of each step = 30 cm = 0.3 mHeight of escalator = number of steps x height of each step = 20 […]
- [BMAT 2021 Section 2 Question 14](https://samiqamar.com/bmat-2021-section-2-question-14/): Carboxylic acids react with alcohols to make esters. A small amount of concentrated sulfuric acid is used as a catalyst. Consider the following ester: What is the name of the alcohol that was used to form this ester? Answer: 14) H The part of the ester molecule highlighted in the green square represents the alcohol used to make the ester. It has 3 carbon atoms and the oxygen atom (part of the hydroxyl group of alcohol) is on the second carbon.So the answer would be propan-2-ol.
- [BMAT 2021 Section 2 Question 13](https://samiqamar.com/bmat-2021-section-2-question-13/): The diagram shows changes in the structure of the uterus lining during the menstrual cycle in a healthy female. Two regions are labelled Q and R. S shows when ovulation occurs Which row shows the change in hormone levels responsible for the changes shown in the diagram during Q, during R, and for ovulation at S? Answer: 13) A During menstruation (Q), progesterone decreases and the uterus lining sheds. R shows when uterus lining builds up. This is when oestrogen increases. S shows ovulation. During ovulation, LH is at its peak.So the answer is A.
- [BMAT 2021 Section 2 Question 12](https://samiqamar.com/bmat-2021-section-2-question-12/): Five congruent small rectangles are joined, as shown, to form one large rectangle. The large rectangle is mathematically similar to each of the small rectangles. For each small rectangle, find the ratio length of the shorter side : length of the longer side Answer: 12) A Let length (longer side) of large rectangle = L Let width (shorter side) of large rectangle = WLet length (longer side) of small rectangle = | Let width (shorter side) of small rectangle = wFrom the diagram, we can see that:L = 5wW = IWe wish to work out the ratio ‘w: I’We know that […]
- [BMAT 2021 Section 2 Question 11](https://samiqamar.com/bmat-2021-section-2-question-11/): A solid cuboid has dimensions 0.20 m × 0.10 m × 0.10 m and density 2000 kg m–3. What pressure is exerted by the weight of the cuboid when it rests with the whole of one of its largest faces on horizontal ground?(gravitational field strength = 10 N kg–1 . Answer: 11) E Volume of the cuboid = 0.2 x 0.1 x 0.1 = 0.002 m3Density = 2000 kg m-3Mass of cuboid = density x volume = 2000 x 0.002 = 4 kgWeight = mass x gravitational field strength = 4 x 10 = 40 NThe cuboid is resting on its […]
- [BMAT 2021 Section 2 Question 10](https://samiqamar.com/bmat-2021-section-2-question-10/): An inorganic salt was analysed to determine its composition. The compound gave a lilac flame in a flame test. After dissolving in water and adding sodium hydroxide solution, a green precipitate was formed. After dissolving in water, acidifying with dilute hydrochloric acid and adding barium chloride solution, a white precipitate was formed. Which of the following could be the formula of the salt? Answer: 10) H Potassium gives a lilac flame in a flame test.Iron (II) gives green precipitate when added to sodium hydroxide solution.A white precipitate in the barium chloride test indicates the presence of sulphate ions.Options F and H […]
- [BMAT 2021 Section 2 Question 9](https://samiqamar.com/bmat-2021-section-2-question-9/): A mature active cell in a healthy human has the following features: Answer: 9) E The mature, active cell in question is a red blood cell.A red blood cell has a cell membrane, no nucleus (hence no nuclear DNA) and has molecules that bind with oxygen (haemoglobin).1 – correct. Red blood cells are transported in blood which is a solution of plasma, white blood cells and red blood cells.2- correct. Red blood cells’ function is to transport oxygen around the body to active tissues.3- wrong. Red blood cells do not have organelles and hence, no mitochondria.
- [BMAT 2021 Section 2 Question 8](https://samiqamar.com/bmat-2021-section-2-question-8/): What is the mean of 12 , 27 and 147 ? Answer: 8) B /12 = √√2 x 2 x 3 = 2√3√27 = 3x3x3 = 3√3147 = √7x7x3 = 7√3For mean, we add these up and divide by 3 2√3 + 3√3 +7√3 = 12√3Divide by 3, we get:12√33= 4√√34√3= √4x4x3 = 48
- [BMAT 2021 Section 2 Question 7](https://samiqamar.com/bmat-2021-section-2-question-7/): A radiation detector on a laboratory bench is switched on when there are no radioactive samples in the laboratory. The count rate displayed by the detector is 24 counts per minute. A radioactive sample is now placed next to the detector and the count rate displayed is 248 counts per minute. The sample is left next to the detector for 48 hours, after which time the count rate displayed is 31 counts per minute. Based on this information, what is the half-life of the sample? Answer: 7) D When no radioactive sample was present, the count was 24 per minute. Therefore, […]
- [BMAT 2021 Section 2 Question 6](https://samiqamar.com/bmat-2021-section-2-question-6/): The industrial manufacture of ethanol from ethene is a catalysed reversible reaction. The equation for this reaction is:C2H4(g) + H2O(g)֖ C2H5OH(g) ΔH = – 46 kJ mol –1Which of the following changes in conditions, when made independently, would increase the number of moles of ethanol present at equilibrium?1 increasing the overall pressure2 increasing the temperature3 the addition of more catalyst. Answer: 6) B Increasing the overall pressure results in the position of equilibrium moving in the direction of the fewest moles of gas. In the reaction, there are 2 moles of gases on the left (reactants) and 1 mole of the […]
- [BMAT 2021 Section 2 Question 5](https://samiqamar.com/bmat-2021-section-2-question-5/): The browning of fruit involves enzymes. The time taken for slices of apple kept in different solutions to turn brown is shown in the table. The effect of pH and sodium chloride concentration was investigated. All other variables were kept constant.A student used the data to make the following statements about these enzyme-catalysed reactions.Which of these statements is/are correct?1 The enzymes involved in browning are denatured in weakly alkaline conditions.2 The optimum pH for the enzymes is pH 7.0.3 The enzymes are activated by sodium chloride. Answer: 5) A Let us first identify the most favourable conditions for the enzymes. To […]
- [BMAT 2021 Section 2 Question 4](https://samiqamar.com/bmat-2021-section-2-question-4/): Express the following in its simplest form : 3xy (x3 / y4 )2 Answer:
- [BMAT 2021 Section 2 Question 3](https://samiqamar.com/bmat-2021-section-2-question-3/): An object of mass 5.0 kg falls vertically through still air. The air resistance acting on the object has a constant value of 50 N. Which of the following statements about the object is/are correct?1 The acceleration of the object is 10 m s –2.2 There is no resultant force on the object.3 The object is travelling at its terminal velocity. (gravitational field strength = 10 N kg –1)/ Answer: 3) G 1 – wrong. Let us calculate the weight of the object. Please remember, weight = mass x gravitational field strength = 5 kg x 10 = 50 N. The […]
- [BMAT 2021 Section 2 Question 2](https://samiqamar.com/bmat-2021-section-2-question-2/): Element Z forms a stable ion Z3– which has the electron configuration 2,8,8. To which Group and Period of the Periodic Table does Z belong? Answer: 2) D The ion has a charge of 3-, which means that it has gained 3 extra electrons. The ion’s electronic configuration (EC) is 2,8,8 and since we know that it has gained 3 electrons, we can deduce that the element Z has a normal EC of 2,8,5.The number of electrons in the last shell (in this case, 5), show which group the element is in. Z is in group ‘5’. However, this is without […]
- [BMAT 2021 Section 2 Question 1](https://samiqamar.com/bmat-2021-section-2-question-1/): A person with cardiovascular disease is at risk of a heart attack. A blood clot may form in one of the arteries that supplies blood to the heart muscle. If the blood clot blocks the artery, blood will be unable to reach some of the cells in the heart. These cells will die due to a lack of oxygen.Scientists aim to develop a treatment that uses stem cells to replace the cells damaged during a heart attack.Which of the following statements about cardiovascular disease and possible stem cell treatment after a heart attack is/are correct?1 Cardiovascular disease is a communicable disease […]
- [BMAT 2020 Section 2 Question 27](https://samiqamar.com/bmat-2020-section-2-question-27/): A bar magnet is rotating at a constant rate of 120 revolutions per minute inside a circular coil of wire, causing an induced voltage across the coil. Which of the following statements is/are correct?1 Increasing the number of turns of wire on the coil would increase both the maximum value and the frequency of the induced voltage.2 The direction of the induced voltage in this coil reverses every 0.25 seconds.3 There is always an induced current in a conductor which is experiencing a change in magnetic field Answer:
- [BMAT 2020 Section 2 Question 26](https://samiqamar.com/bmat-2020-section-2-question-26/): Diammonium hydrogen phosphate, (NH4)2HPO4, can be used as a fertiliser. The following equation shows how it can be synthesised:2NH3(g) + H3PO4(aq) → (NH4)2HPO4(s)What is the mass of diammonium hydrogen phosphate that is produced when 3.40 kg of ammonia is reacted with phosphoric acid (H3PO4), in excess, with a yield of 80%?(Mr values: NH3 = 17.0; H3PO4 = 98.0; (NH4)2HPO4 = 132) Answer:
- [BMAT 2020 Section 2 Question 25](https://samiqamar.com/bmat-2020-section-2-question-25/): The diagram shows part of a DNA double helix being copied Which of the following statements, considered independently, is/are correct?1 The probability of any base in strand 2 being guanine (G) is 0.17.2 If p is guanine and r cytosine, a mutation must have taken place.3 The copying process shown is taking place during mitosis Answer:
- [BMAT 2020 Section 2 Question 24](https://samiqamar.com/bmat-2020-section-2-question-24/): The diameter XY of a circle has length d cm.O is a point on the circumference of this circle such that a new circle with centre O passesthrough points X and Y.P is a point on the new circle and the arc XPY is shown in the diagram.Which of the following is an expression for the perimeter, in cm, of the shaded region? Answer:
- [BMAT 2020 Section 2 Question 23](https://samiqamar.com/bmat-2020-section-2-question-23/): A submarine uses sound of frequency 6000 Hz to locate obstructions ahead of it in the sea. A pulse of this sound reflects off an object that is 750 m in front of the submarine. The pulse returns to the submarine 1.00 s after it is transmitted. What is the wavelength of this sound in the sea water? Answer:
- [BMAT 2020 Section 2 Question 22](https://samiqamar.com/bmat-2020-section-2-question-22/): The compounds BrCl and BrI melt at – 66 °C and 42 °C, respectively. What is the best explanation for this difference in melting points? Answer:
- [BMAT 2020 Section 2 Question 21](https://samiqamar.com/bmat-2020-section-2-question-21/): The table below gives some information about the number and biomass of organisms in thefood chain:rose bush → aphid → ladybirdorganism number oforganismsbiomass at eachlevel(arbitrary units)rose bush 1 800aphid 4000 200ladybird 50 10What percentage of the biomass in the producer is transferred into the biomass of eachindividual secondary consumer, in this food chain? Answer:
- [BMAT 2020 Section 2 Question 20](https://samiqamar.com/bmat-2020-section-2-question-20/): PQRS is a kite. Points P, Q and R are plotted on the diagram.P is the point (0, 1) and R is the point (4, 5).angle PQR = 90°The point Q lies on the y-axis.The line PS is a segment of the line 2y + x = 2The coordinates of S are ( l, m).What is 2l + m ? Answer:
- [BMAT 2020 Section 2 Question 19](https://samiqamar.com/bmat-2020-section-2-question-19/): A diver of mass 45 kg jumps from a diving board and reaches a maximum height of 10 m above the surface of the water in a swimming pool. Assume Earth’s gravitational field strength is 10 N kg–1 , that air resistance is negligible, and that the diver is treated as a point particle. What is the diver’s kinetic energy as she hits the water, and at what speed does she hit the water? Answer: 19) E At the maximum height of 10m, the diver would have maximum gravitational potential energy (GPE).GPE = mgh = 45 x 10 x 10 = […]
- [BMAT 2020 Section 2 Question 18](https://samiqamar.com/bmat-2020-section-2-question-18/): Propene is an alkene. The structural formula of propene is shown. A polymer can be made from propene. What is the correct structural formula of this polymer? Answer: 18) D In this polymerization reaction, the double bond breaks down into a single bond and the individual propene molecules (monomers) combine to form a long, chainlike molecule consisting of repeating units.Imagine the given propene like this (the numbers in red are the carbon number in propene):You can see that there is a double bond between the first and second carbon. This double bond would break, forming something this:Carbon atoms usually need 4 […]
- [BMAT 2020 Section 2 Question 17](https://samiqamar.com/bmat-2020-section-2-question-17/): Six test tubes were set up. Two different solutions were added to each test tube as shown in the table.The temperature, pH and all concentrations were optimal.Which three mixtures would lead to the presence of amino acids in the test tube?test tube mixture of solutions1 lipase and lipid2 lipase and boiled protein3 protease and lipase4 boiled protease and protein5 protease and boiled protein6 protease and protein Answer: 17) F Test tube 1 – lipases would break lipids. No amino acids would be found.Test tube 2 – lipases break down lipids, not proteins. No amino acids would be found.Test tube 3 – […]
- [BMAT 2020 Section 2 Question 16](https://samiqamar.com/bmat-2020-section-2-question-16/): The graphs of the following functions are drawn:y= 2x-1 y= 1-x2 y= (1-x)2 y=2-xWhich two graphs do not intersect? Answer: 16) E The best way to solve this question is to solve for ‘y’ using different values of ‘x’, draw a mini graph on your paper and plot the points accordingly. Yes, this may take a couple of minutes. So, I suggest you save this question to the end and come back to it.You will realise that graphs 2 and 4 don’t intersect.
- [BMAT 2020 Section 2 Question 15](https://samiqamar.com/bmat-2020-section-2-question-15/): Thorium-232 ( Th) is an unstable nuclide that decays through a sequence of radioactive emissions to form a stable nuclide of lead. All of the emissions during this sequence are either alpha or beta (β–) particles. One of the intermediate nuclides, reached after four alpha and two beta decays, is a nuclide ofan element labelled X. What is the symbol for this nuclide of X?# Answer: 15) C During an alpha decay, the mass number (top number) decreases by 4 and atomic number (bottom number) decreases by 2. Four alpha decays occur.So mass number decreases to: 232 – 4(4) = 232-16 […]
- [BMAT 2020 Section 2 Question 14](https://samiqamar.com/bmat-2020-section-2-question-14/): Four metals, labelled R, T, X and Z, have the following characteristics: Answer: 14) F T is precipitated when R reacts with aqueous solution of T. This means that R replaces T. Therefore R is more reactive than T.X is the only metal out of the four that does not combine with other elements. X is the least reactive out of the four.Z is obtained by electrolysis whereas R and T are obtained by heating their oxides with carbon. Carbon replaces the less reactive metal in a redox reaction, where the carbon is oxidised and the metal is reduced. Therefore, the […]
- [BMAT 2020 Section 2 Question 13](https://samiqamar.com/bmat-2020-section-2-question-13/): Several processes can change the proportion of gases in the atmosphere by adding or removing carbon dioxide or oxygen. Which row is correct? Answer: 13) D This is fairly simple. Aerobic respiration adds carbon dioxide. Photosynthesis usesatmospheric carbon dioxide and releases oxygen. Decomposers use atmospheric oxygen for respiration.
- [BMAT 2020 Section 2 Question 12](https://samiqamar.com/bmat-2020-section-2-question-12/): Triangle PQR is equilateral with sides of length 10 cm. P, Q, and R are points on the circumference of a circle with centre O. Which one of the following is an expression, in centimetres, for the radius of the circle? Answer: 12) D Form right-angled triangles within the circle as shown below. The hypotenuse is QO. Note also, that QO is the radius of the circle.M is the midpoint of QR. Since QR = 10 cm, QM = 5 cm.Angle QMO is 90°. Angle QOM would be 60° as the 6 triangles split 360° into 6 equal angles near O.sin60° […]
- [BMAT 2020 Section 2 Question 11](https://samiqamar.com/bmat-2020-section-2-question-11/): A ‘gold medal’ used in events such as the Olympic Games is made from a silver–nickel alloy with a coating of a gold–silver alloy.The mass of the medal is 256 g, of which 24.0 g is the mass of the coating.The density of the silver–nickel alloy is 10.0 g cm–3 and the density of the gold–silver alloy is 16.0 g cm–3What is the volume of the medal? Answer: 11) D Mass of non-coating material = 256-24 = 232 g Density of non-coating material = 10 g cm-3 Volume = Mass / density = 232 / 10 = 23.2 cm3Density of coating […]
- [BMAT 2020 Section 2 Question 10](https://samiqamar.com/bmat-2020-section-2-question-10/): The reaction between hydrogen and nitrogen in the presence of an iron catalyst is known as the Haber process. It is a reversible reaction. The energy profile for this reaction is shown. What is the energy change when one mole of ammonia is decomposed into its component elements? Answer: 10) A The question states that the Haber process is reversible. The graph shows figures for when 2 moles of ammonia are formed. Overall, the reaction is exothermic with -92 kJ of energy released.In the reverse process, 2 moles of ammonia decomposing into its elements would be endothermic and 92kJ of energy […]
- [BMAT 2020 Section 2 Question 9](https://samiqamar.com/bmat-2020-section-2-question-9/): Some rabbits have a genetic condition. The dominant allele codes for this condition. A homozygous dominant rabbit mated with a rabbit that did not have the condition. They had three offspring. One of the offspring then mated with a rabbit that did not have the condition and they also produced three offspring. Two of the offspring had the condition and one did not. One body cell that is in early interphase is taken from each of the rabbits in these three generations. What is the total number of copies of the allele for the condition in this collection of cells. Answer: […]
- [BMAT 2020 Section 2 Question 8](https://samiqamar.com/bmat-2020-section-2-question-8/): In a sale, the normal price of a camera is reduced by 20%. The sale price of the camera is £180. Which expression gives the normal price of the camera? Answer: 8) D Let ‘N’ be the normal price of a camera and let ‘S’ be the sale price.In the sale, the price is reduced by 20%. SN- 0.2NS = 0.8 NTo find the normal price ‘N’, we simply rearrange. N=S ÷ 0.8We know S = £180So N = 180 ÷ 0.8
- [BMAT 2020 Section 2 Question 7](https://samiqamar.com/bmat-2020-section-2-question-7/): An electric fan heater contains a heating element and a motor that drives the fan. The circuitdiagram is shown.At first, the switch is open and the current in the motor is 0.40 A.The switch is then closed.Which of the following statements is/are correct after the switch is closed?1 The current in the heating element added to the current in the motor is 0.40 A.2 The voltage across the heating element is 240 V.3 The resistance of the circuit is smaller than it is with the switch open Answer: 7) G When the switch is closed, the circuit becomes a parallel circuit.When […]
- [BMAT 2020 Section 2 Question 6](https://samiqamar.com/bmat-2020-section-2-question-6/): Hot, concentrated aqueous sodium hydroxide and chlorine react as shown in the equation:6NaOH + 3Cl2 → 5NaCl + NaClO3 + 3H2OWhich of the following statements is/are correct?1 Chlorine has oxidation state + 5 in NaClO3.2 This is an example of a disproportionation reaction.3 Some of the oxygen in the hydroxide ions is oxidised. Answer: 6) E Statement 1 = CorrectIn NaCIO3, each O has oxidation number -2. Since there are 3 Oxygen atoms, O has a total of -6.Na = +1Total oxidation number of NaCIO3 = 0So, 01+ CI-6CI6-1+5Statement 2 = CorrectA disproportionation reaction occurs when an element is both oxidised […]
- [BMAT 2020 Section 2 Question 5](https://samiqamar.com/bmat-2020-section-2-question-5/): Scientists are using human stem cells to develop treatments for a wide variety of healthconditions.Two types of stem cell that are available for this work are: Answer: 5) G Statement 1 is wrong as the daughter cell will not produce haploid copy. It will produce diploid.Statement 2 is correct because the cells collected from the embryo are able to differentiate more. The embryo cells are pluripotent (able to give rise to all types of cells in body) whereas the bone marrow stem cells are multipotent (able to give rise to some types of cells in body)Statement 3 is correct. Stem cells […]
- [BMAT 2020 Section 2 Question 4](https://samiqamar.com/bmat-2020-section-2-question-4/): Which one of the following is a simplification of 2-2x+1 / 4×2+4x+1 ? Answer: 4) A 2- 2x+1 / 4×2+4x+1We can simplify the denominator24x 2x+1 212x + 1(2x+1)Introduce the common denominator in the main expression. In this case, the common denominator would be (2x + 1) 2(2x+1)- 1 2x+1 4x+2-1 2x + 1 4x + 1 2x+1
- [BMAT 2020 Section 2 Question 3](https://samiqamar.com/bmat-2020-section-2-question-3/): A supermarket has a large open-topped deep freezer to keep products frozen but still visible to customers. Which statement about the air in this freezer explains why the products remain frozen, even though it is open-topped? Answer: 3) D Cold air is denser than hot air so it remains at the bottom and keeps the products cold.
- [BMAT 2020 Section 2 Question 2](https://samiqamar.com/bmat-2020-section-2-question-2/): A sample of an element consists of two isotopes. The relative abundance of each isotope isshown in the table.What is the relative atomic mass of the element in this sample? Answer: 2) E Isotope 1Total mass = 31 + 38 = 69 Percentage = 60%|Isotope 1Total mass 31 +40 71Percentage = 40%Relative atomic mass =(69 x 60) + (71 x 40)= 69.8100
- [BMAT 2020 Section 2 Question 1](https://samiqamar.com/bmat-2020-section-2-question-1/): Which two of the following statements about genetic variation are correct?1 Asexual reproduction always produces genetic variation.2 Gamete production is the only possible source of genetic variation in sexual reproduction.3 The environment can cause genetic variation.4 Mutations can produce genetic variation. Answer: 1) F Asexual reproduction does not produce genetic variationIn sexual reproduction, gamete production is not the only possible source of genetic variation. Genetic variation arises from fertilisation too.Environment and mutations cause genetic variation. So statements 3 and 4 are correct.
- [BMAT 2019 Section 2 Question 27](https://samiqamar.com/bmat-2019-section-2-question-27/): A 100% efficient ideal transformer has 400 turns on its primary coil and 100 turns on its secondary coil. The input voltage across the primary coil is 240 V. An output current of 2.0 A flows in the secondary coil. What are the output voltage across the secondary coil, the input current in the primary coil, and the output power of the transformer? Answer: 27) B This question requires us to use the formula:Turns on primary coil Voltage on primary coil Turns on secondary coilVoltage on secondary coil 400 240 100Voltage on secondary coil100 x 240voltage on seconday coil == 60 […]
- [BMAT 2019 Section 2 Question 26](https://samiqamar.com/bmat-2019-section-2-question-26/): Diborane has the formula B2H6.Assume that boron consists of two isotopes, containing 20% B105 atoms and 80% B115 atoms,and that all hydrogen atoms are H1.Molecules of diborane will therefore have relative masses of 26, 27 or 28.In what relative proportion will molecules of diborane with masses of 26, 27 and 28 occur? Answer: 26) E Ratio of the two isotopes = 20% 80% = 1:4Probability of both boron being B-10 (having mass 26) = 0.2 x 0.2 = 0.04Probability of 1 boron being B-10 and other being B-11 (having mass 27) = (0.2 x 0.8) + (0.2 x 0.8) = 0.32(remember […]
- [BMAT 2019 Section 2 Question 25](https://samiqamar.com/bmat-2019-section-2-question-25/): A student carried out tests to find out which molecules were present in a sample of urine from a human male. The student recorded the presence of large protein molecules in the urine, and suggested that this indicated that the kidney was not functioning correctly.Which of the following could have resulted in a high concentration of protein in the urine sample?1 damage to cell membranes between the blood vessels and the Bowman’s capsule2 a reduced rate of active transport and selective re-absorption from the nephron3 Cells in the collecting duct do not have receptors to bind to antidiuretic hormone (ADH) and […]
- [BMAT 2019 Section 2 Question 24](https://samiqamar.com/bmat-2019-section-2-question-24/): A cross-country running track is in the shape of a regular pentagon. Competitors run clockwise around the track. When on the third leg of the course they run on a bearing of 110°. What bearing do they run on for the first leg? Answer: 24) H The easiest way to solve this would be to use a protractor on the pentagon diagram provided. Set the protractor in such a way that the line which represents third leg is at 110°. (such as in the diagram below)Remember, bearings are taken from North. This means we must draw an imaginary line pointing towards […]
- [BMAT 2019 Section 2 Question 23](https://samiqamar.com/bmat-2019-section-2-question-23/): A water jet pack has lifted a person vertically upwards, as shown in the sketch. He is now stationary at a constant height. Water rises through the tube and is ejected at a speed of 15 m s –1 through two nozzles. In a time of 12 s, each of the nozzles ejects 400 kg of water vertically downwards. What is the momentum of the water ejected by each nozzle in 12 s, and what is the upward force due to the water ejected by the jet pack? Answer: 23) A Momentum = mass x velocity = 400 x 15 = […]
- [BMAT 2019 Section 2 Question 22](https://samiqamar.com/bmat-2019-section-2-question-22/): Complete combustion of 35 cm3 of a straight-chain alkane vapour gave 105 cm3 of carbon dioxide gas. Both gas volumes were measured at the same temperature and pressure. Which of the following is the molecular formula of the alkane? Answer: 22) D Options A and C are wrong because they are alkenes.Let molecular formula of alkane be CxHy Ratio of volumes of alkane and CO2 = 35 : 105 = 1 : 3 This means that number of carbons (x) = 3 Only options C and D have hydrocarbons where number of carbons are 3. We have already established that option […]
- [BMAT 2019 Section 2 Question 21](https://samiqamar.com/bmat-2019-section-2-question-21/): Which of the following statements is/are correct for a healthy human?1 A protein section coded for by part of a gene consisting of 500 base pairs will have a maximum of 166 amino acids.2 A liver cell and a mature red blood cell from the same person will both have a chromosome number of 46.3 The number of adenine bases in an allele must be the same as the number of guanine bases. Answer: 21) B 1 – Correct. Amino acids are encoded by a group of 3 bases. 166 x 3 = 498. So a gene consisting of 500 base […]
- [BMAT 2019 Section 2 Question 20](https://samiqamar.com/bmat-2019-section-2-question-20/): To get to work, Sylvie first catches a bus and then catches a train.The probability that the bus is on time is 0.6The probability that the bus is late is 0.4If the bus is on time, then the probability that she will catch the train is 0.8If the bus is late, then the probability that she will catch the train is 0.6Given that Sylvie catches the train, what is the probability that the bus was on time? Answer:
- [BMAT 2019 Section 2 Question 19](https://samiqamar.com/bmat-2019-section-2-question-19/): Cosmologists have deduced that soon after the Universe was formed it was filled with electromagnetic radiation in the form of intense gamma-rays. They have also deduced that the Universe has been expanding since that time. One effect of this expansion is that the electromagnetic radiation that fills the Universe is now in the microwave region of the spectrum. Here are three statements about the effects of the Universe expanding on the electromagnetic radiation that filled the early Universe: 1 The expansion has caused an increase in the frequency of the radiation. 2 The expansion has caused a decrease in the wavelength […]
- [BMAT 2019 Section 2 Question 18](https://samiqamar.com/bmat-2019-section-2-question-18/): The concentration of Fe2+ ions in a solution can be determined by titration with acidifed potassium manganate(VII) solution.The ionic equation for the reaction is:5Fe2+ + MnO4– + 8H+ → 5Fe3+ + Mn2+ + 4H 2OA 25.0 cm3 sample of solution containing Fe2+ ions reacted exactly with 10.0 cm3 of 0.0500 mol dm–3 potassium manganate(VII) solution.What is the concentration of Fe2+ , in mol dm–3 ? Answer: 18) E We are given the concentration and volume of potassium manganate (VII). We can calculate the number of moles with this. (convert volume to dm3 first. 10 cm3 = 0.01 dm3) n = c […]
- [BMAT 2019 Section 2 Question 17](https://samiqamar.com/bmat-2019-section-2-question-17/): A pea plant is heterozygous for seed colour and homozygous for seed shape. Yellow seed colour (Y) is dominant to green seed colour (y). Round seed shape (R) is dominant to wrinkled seed shape (r).Using the information provided, which of the following statements, taken independently, could be correct?1 This plant contains the alleles Y, y, R and r.2 This plant contains only the alleles Y, y and R.3 This plant contains only the alleles Y, R and r.4 The genotype of this plant for seed colour is Yy.5 The genotype of this plant for seed colour is YY.6 The genotype of […]
- [BMAT 2019 Section 2 Question 16](https://samiqamar.com/bmat-2019-section-2-question-16/): One side of a rectangle is − cm.The rectangle has an area of 66 cm2.What is the perimeter, in cm, of the rectangle? Answer: 16) D Area of a rectangle = length x widthWe can assume (7 – √5) cm can either be length or width, it does not matter.Let us say it is the length. Let the width be W. Area of this rectangle (66) = (7 – √5) x WW = 66 ÷ (7 – √5) Now we just use the formula for perimeter of rectangle. P = 2 (l + w) By doing the addition inside the brackets, […]
- [BMAT 2019 Section 2 Question 15](https://samiqamar.com/bmat-2019-section-2-question-15/): Which statement about waves is correct? Answer: 15) F The only correct statement is F. Ultrasonic waves, like sound waves, are longitudinal.
- [BMAT 2019 Section 2 Question 14](https://samiqamar.com/bmat-2019-section-2-question-14/): The decomposition of hydrogen peroxide in the presence of a manganese(IV) oxide catalyst produces water and oxygen gas.2H2O2(aq) → 2H2O(l) + O2(g)0.2 g of manganese(IV) oxide granules are added to 50 cm3 of 0.1 mol dm–3 hydrogen peroxide at 20 °C. The volume of gas collected is shown on the graph as curve X.A second experiment is carried out at 20 °C using the same mass of manganese(IV) oxide. The volume of gas collected is shown as curve Y. Which of the following conditions could result in curve Y? Answer: 14) A We know that the total volume of gas produced […]
- [BMAT 2019 Section 2 Question 13](https://samiqamar.com/bmat-2019-section-2-question-13/): Which of the following is/are included in the carbon cycle?1 amino acids in an animal2 cellulose in a plant cell wall3 lipids in a bacterial cell membrane Answer: 13) H Amino acids, cellulose and lipids have carbon in them. Therefore, all 3 are part of the carbon cycle.
- [BMAT 2019 Section 2 Question 12](https://samiqamar.com/bmat-2019-section-2-question-12/): Point M has coordinates (6, 3p −1) and point N has coordinates (1− p, 2). The gradient of the straight line joining M and N is − 3 and it crosses the y-axis at (0, r ). What is the value of r ? Answer: 12) H Any straight line on a graph is governed by the formula: y = mx + cThis means that any point on that line has to follow this formula.In this formula,·•Y is a function of X (you will understand as we go along to solve this question) M is the gradient (we are given that […]
- [BMAT 2019 Section 2 Question 11](https://samiqamar.com/bmat-2019-section-2-question-11/): A large metal sphere mounted on an insulating stand is negatively charged. A smaller, uncharged metal sphere mounted on an insulating stand is placed near to the negatively charged sphere. The smaller sphere is connected to the Earth by a conducting wire. Electrons flow from the smaller sphere to Earth because they are repelled by the larger sphere. The smaller sphere is then disconnected from the Earth. Which row must be correct about the particles in the larger sphere and the final charge of the smaller sphere? Answer: 11) C It is important to think about this question logically. The smaller […]
- [BMAT 2019 Section 2 Question 10](https://samiqamar.com/bmat-2019-section-2-question-10/): Consider the non-radioactive elements in Group 1.Which of the following statements is/are correct about the element with the largest atomic number?1 It has the most vigorous reaction with cold water.2 Its atom has the same number of electrons in its highest occupied energy level asother members of the group.3 It is the most readily oxidised. Answer: 10) H In this question we are talking about the element with the largest atomic number in group 1. This is the one furthest down the group. Statement 1 is correct because reactivity with water increases down group 1. Hence, it has the most vigorous […]
- [BMAT 2019 Section 2 Question 9](https://samiqamar.com/bmat-2019-section-2-question-9/): A lizard was placed in a chamber with a constant flow of air. The temperature of the chamberwas varied between 25 °C and 10 °C. Apart from temperature and time, all other variables werekept constant.The carbon dioxide concentrations in the air leaving the chamber are shown in the graph.Which of the following statements is/are correct?1 Between 25 °C and 10 °C the respiration rate of the lizard is inversely proportional tothe environmental temperature.2 The data demonstrates that the lizard is only respiring aerobically.3 The carbon dioxide could be detected by passing the air leaving the chamber Answer: 9) D Statement 1 […]
- [BMAT 2019 Section 2 Question 8](https://samiqamar.com/bmat-2019-section-2-question-8/): Find the value of √6×102 +4×101 / 1.2×10-2 +4×10-3 ? Answer: 8) E To solve this simply, we just need to not use the figures given as standard form. Using the figures as they are may confuse a bit.E.g. 6 x 102 600We get: 600 + 40 0.012 + 0.004640 0.016√40,000 = 200
- [BMAT 2019 Section 2 Question 7](https://samiqamar.com/bmat-2019-section-2-question-7/): A measuring cylinder resting on an electronic balance contains a liquid as shown in diagram 1. A small solid object X is gently lowered into the liquid and no liquid splashes out of the cylinder. The result is shown in diagram 2.What is the density of the material from which object X is made? Answer: 7) C When the object is gently lowered, here are the changes that take place: The scale changes from 750 g to 950 g. So mass of object = 200 gThe liquid rises from 375 cm3 to 500 cm3.Volume of object = 125 cm3Density = Mass […]

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- [Home](https://samiqamar.com/): Hey Friends I’m Sami. I’m a YouTuber, Blogger, and 3rd year med student. On this site I’ll share the best possible resources for IMAT 2026, books, solved IMAT past papers, IMAT notes, IMAT practice questions and much more. The basic aim would be how to enjoy studies😊 Check out my Ultimate Guides IMAT Syllabus If you’re preparing for IMAT 2026 download the syllabus here. IMAT Books Best books for IMAT study, you can download the pdfs for free. IMAT 2025 cutoff? Here is the IMAT 2025 Ranking and cutoff for both Eu & non Eu. Complete Your IMAT Syllbus in 1 […]
- [IMAT Books](https://samiqamar.com/best-imat-books/): 🎓IMAT 2024 Books Studying for IMAT 2024 exam? Here are the best books to follow during your preparation… Best Books For IMAT 2024 Preparation Looking for the best IMAT preparation books to excel in the IMAT 2024 exam? You’ve come to the right place! In this video, we provide an in-depth review of the top IMAT books for all subjects, helping you make informed choices for your IMAT preparation. IMAT preparation books are essential resources for mastering the subjects covered in the IMAT exam. In this comprehensive guide, we share our top recommendations, covering biology, chemistry, physics, and more. Get ready […]

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